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How to extract lower and upper bound in numeric format from a confidence interval string?


How can I plot data with confidence intervals?R - Bootstrapped Confidence Interval - Obtain Parameters of Upper and Lower BoundsHow to display several bootstrap confidence intervals on one plotHow can confidence intervals be numerically visualized in corrplot()?How to compute confidence Interval of the fitted value via nls()rAmCharts Scattered plot with Upper and lower confidence interval around Fitted valuesextract confidence intervals from binomial test in Rhow to add confidence interval as coloured area to a boxplot of predicted values in ggplot2?How to extract values of confidence interval from ggplot2 stat summary in R?Plotting a ggplot() when having the confidence interval upper and lower values






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty
margin-bottom:0;









10

















Suppose a vector including some confidence intervals as below



confint <- c("[0.741 ; 2.233]", "[263.917 ; 402.154]", "[12.788 ; 17.975]", "[0.680 ; 2.450]", "[0.650 ; 1.827]", "[0.719 ; 2.190]")


I want to have two new vectors one including the lower Limits in numeric format as



lower <- c(0.741, 263.917, 12.788, 0.680, 0.650 , 0.719)


and othe including the upper Limits in numeric format like



upper <- c(2.233, 402.154, 17.975, 2.450, 1.827, 2.190)









share|improve this question
































    10

















    Suppose a vector including some confidence intervals as below



    confint <- c("[0.741 ; 2.233]", "[263.917 ; 402.154]", "[12.788 ; 17.975]", "[0.680 ; 2.450]", "[0.650 ; 1.827]", "[0.719 ; 2.190]")


    I want to have two new vectors one including the lower Limits in numeric format as



    lower <- c(0.741, 263.917, 12.788, 0.680, 0.650 , 0.719)


    and othe including the upper Limits in numeric format like



    upper <- c(2.233, 402.154, 17.975, 2.450, 1.827, 2.190)









    share|improve this question




























      10












      10








      10


      1






      Suppose a vector including some confidence intervals as below



      confint <- c("[0.741 ; 2.233]", "[263.917 ; 402.154]", "[12.788 ; 17.975]", "[0.680 ; 2.450]", "[0.650 ; 1.827]", "[0.719 ; 2.190]")


      I want to have two new vectors one including the lower Limits in numeric format as



      lower <- c(0.741, 263.917, 12.788, 0.680, 0.650 , 0.719)


      and othe including the upper Limits in numeric format like



      upper <- c(2.233, 402.154, 17.975, 2.450, 1.827, 2.190)









      share|improve this question















      Suppose a vector including some confidence intervals as below



      confint <- c("[0.741 ; 2.233]", "[263.917 ; 402.154]", "[12.788 ; 17.975]", "[0.680 ; 2.450]", "[0.650 ; 1.827]", "[0.719 ; 2.190]")


      I want to have two new vectors one including the lower Limits in numeric format as



      lower <- c(0.741, 263.917, 12.788, 0.680, 0.650 , 0.719)


      and othe including the upper Limits in numeric format like



      upper <- c(2.233, 402.154, 17.975, 2.450, 1.827, 2.190)






      r






      share|improve this question














      share|improve this question











      share|improve this question




      share|improve this question










      asked May 27 at 12:31









      FatetaFateta

      1298 bronze badges




      1298 bronze badges

























          6 Answers
          6






          active

          oldest

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          12


















          A base R solution



          lower = as.numeric(sub(".*?(\d+\.\d+).*", "\1", confint))
          upper = as.numeric(sub(".*\b(\d+\.\d+).*", "\1", confint))

          lower
          [1] 0.741 263.917 12.788 0.680 0.650 0.719
          upper
          [1] 2.233 402.154 17.975 2.450 1.827 2.190





          share|improve this answer



































            3


















            mypattern <- '\[(\d+\.\d+) ; (\d+\.\d+)\]'
            as.numeric(gsub(mypattern, '\1', confint))
            as.numeric(gsub(mypattern, '\2', confint))





            share|improve this answer

































              2


















              A different base R possibility could be:



              sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [1])
              sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [2])

              [1] "0.741" "263.917" "12.788" "0.680" "0.650" "0.719"
              [1] "2.233" "402.154" "17.975" "2.450" "1.827" "2.190"


              If you need it as a numeric vector:



              sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [1])
              sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [2])





              share|improve this answer




























              • @Ronak Shah I updated my post according some of your ideas. Thank you :)

                – tmfmnk
                May 27 at 12:59











              • I realised it needed some more tweaking to get exact output but I think it was a similar approach. +1 to you.

                – Ronak Shah
                May 27 at 13:21


















              2


















              Meanwhile, I came up with another base R solution



              lower <- as.numeric(sub(".]*", "", sub(";.*", "", confint)))
              upper <- as.numeric(sub("].*", "", sub(".*;", "", confint)))


              Thank you all!






              share|improve this answer



































                1


















                You can use functions from the stringr library.



                You can split strings with str_split() according a specific character (; in your case), then remove character with str_remove() ([ and ] in your case) and you will obtain what you want.



                str_remove(str_split_fixed(confint, ";", n = 2)[,1], '\[') %>% as.numeric()
                # [1] 0.741 263.917 12.788 0.680 0.650 0.719





                share|improve this answer



































                  1


















                  A tidyverse solution:



                  library(dplyr)
                  library(tidyr)

                  df = data.frame(confint)
                  df = df %>%
                  mutate(confint = gsub("(\[|\])","",confint)) %>%
                  separate(confint,c("lower","upper"),";",convert=T)





                  share|improve this answer



























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                    6 Answers
                    6






                    active

                    oldest

                    votes








                    6 Answers
                    6






                    active

                    oldest

                    votes









                    active

                    oldest

                    votes






                    active

                    oldest

                    votes









                    12


















                    A base R solution



                    lower = as.numeric(sub(".*?(\d+\.\d+).*", "\1", confint))
                    upper = as.numeric(sub(".*\b(\d+\.\d+).*", "\1", confint))

                    lower
                    [1] 0.741 263.917 12.788 0.680 0.650 0.719
                    upper
                    [1] 2.233 402.154 17.975 2.450 1.827 2.190





                    share|improve this answer
































                      12


















                      A base R solution



                      lower = as.numeric(sub(".*?(\d+\.\d+).*", "\1", confint))
                      upper = as.numeric(sub(".*\b(\d+\.\d+).*", "\1", confint))

                      lower
                      [1] 0.741 263.917 12.788 0.680 0.650 0.719
                      upper
                      [1] 2.233 402.154 17.975 2.450 1.827 2.190





                      share|improve this answer






























                        12














                        12










                        12









                        A base R solution



                        lower = as.numeric(sub(".*?(\d+\.\d+).*", "\1", confint))
                        upper = as.numeric(sub(".*\b(\d+\.\d+).*", "\1", confint))

                        lower
                        [1] 0.741 263.917 12.788 0.680 0.650 0.719
                        upper
                        [1] 2.233 402.154 17.975 2.450 1.827 2.190





                        share|improve this answer
















                        A base R solution



                        lower = as.numeric(sub(".*?(\d+\.\d+).*", "\1", confint))
                        upper = as.numeric(sub(".*\b(\d+\.\d+).*", "\1", confint))

                        lower
                        [1] 0.741 263.917 12.788 0.680 0.650 0.719
                        upper
                        [1] 2.233 402.154 17.975 2.450 1.827 2.190






                        share|improve this answer















                        share|improve this answer




                        share|improve this answer








                        edited May 27 at 12:45

























                        answered May 27 at 12:41









                        G5WG5W

                        25.9k9 gold badges24 silver badges46 bronze badges




                        25.9k9 gold badges24 silver badges46 bronze badges


























                            3


















                            mypattern <- '\[(\d+\.\d+) ; (\d+\.\d+)\]'
                            as.numeric(gsub(mypattern, '\1', confint))
                            as.numeric(gsub(mypattern, '\2', confint))





                            share|improve this answer






























                              3


















                              mypattern <- '\[(\d+\.\d+) ; (\d+\.\d+)\]'
                              as.numeric(gsub(mypattern, '\1', confint))
                              as.numeric(gsub(mypattern, '\2', confint))





                              share|improve this answer




























                                3














                                3










                                3









                                mypattern <- '\[(\d+\.\d+) ; (\d+\.\d+)\]'
                                as.numeric(gsub(mypattern, '\1', confint))
                                as.numeric(gsub(mypattern, '\2', confint))





                                share|improve this answer














                                mypattern <- '\[(\d+\.\d+) ; (\d+\.\d+)\]'
                                as.numeric(gsub(mypattern, '\1', confint))
                                as.numeric(gsub(mypattern, '\2', confint))






                                share|improve this answer













                                share|improve this answer




                                share|improve this answer










                                answered May 27 at 12:52









                                pzhaopzhao

                                2401 silver badge8 bronze badges




                                2401 silver badge8 bronze badges
























                                    2


















                                    A different base R possibility could be:



                                    sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [1])
                                    sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [2])

                                    [1] "0.741" "263.917" "12.788" "0.680" "0.650" "0.719"
                                    [1] "2.233" "402.154" "17.975" "2.450" "1.827" "2.190"


                                    If you need it as a numeric vector:



                                    sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [1])
                                    sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [2])





                                    share|improve this answer




























                                    • @Ronak Shah I updated my post according some of your ideas. Thank you :)

                                      – tmfmnk
                                      May 27 at 12:59











                                    • I realised it needed some more tweaking to get exact output but I think it was a similar approach. +1 to you.

                                      – Ronak Shah
                                      May 27 at 13:21















                                    2


















                                    A different base R possibility could be:



                                    sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [1])
                                    sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [2])

                                    [1] "0.741" "263.917" "12.788" "0.680" "0.650" "0.719"
                                    [1] "2.233" "402.154" "17.975" "2.450" "1.827" "2.190"


                                    If you need it as a numeric vector:



                                    sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [1])
                                    sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [2])





                                    share|improve this answer




























                                    • @Ronak Shah I updated my post according some of your ideas. Thank you :)

                                      – tmfmnk
                                      May 27 at 12:59











                                    • I realised it needed some more tweaking to get exact output but I think it was a similar approach. +1 to you.

                                      – Ronak Shah
                                      May 27 at 13:21













                                    2














                                    2










                                    2









                                    A different base R possibility could be:



                                    sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [1])
                                    sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [2])

                                    [1] "0.741" "263.917" "12.788" "0.680" "0.650" "0.719"
                                    [1] "2.233" "402.154" "17.975" "2.450" "1.827" "2.190"


                                    If you need it as a numeric vector:



                                    sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [1])
                                    sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [2])





                                    share|improve this answer
















                                    A different base R possibility could be:



                                    sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [1])
                                    sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) gsub("[^0-9.-]+", "\1", x) [2])

                                    [1] "0.741" "263.917" "12.788" "0.680" "0.650" "0.719"
                                    [1] "2.233" "402.154" "17.975" "2.450" "1.827" "2.190"


                                    If you need it as a numeric vector:



                                    sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [1])
                                    sapply(strsplit(confint, " ; ", fixed = TRUE), function(x) as.numeric(gsub("[^0-9.-]+", "\1", x)) [2])






                                    share|improve this answer















                                    share|improve this answer




                                    share|improve this answer








                                    edited May 27 at 12:58

























                                    answered May 27 at 12:49









                                    tmfmnktmfmnk

                                    12.4k1 gold badge10 silver badges26 bronze badges




                                    12.4k1 gold badge10 silver badges26 bronze badges















                                    • @Ronak Shah I updated my post according some of your ideas. Thank you :)

                                      – tmfmnk
                                      May 27 at 12:59











                                    • I realised it needed some more tweaking to get exact output but I think it was a similar approach. +1 to you.

                                      – Ronak Shah
                                      May 27 at 13:21

















                                    • @Ronak Shah I updated my post according some of your ideas. Thank you :)

                                      – tmfmnk
                                      May 27 at 12:59











                                    • I realised it needed some more tweaking to get exact output but I think it was a similar approach. +1 to you.

                                      – Ronak Shah
                                      May 27 at 13:21
















                                    @Ronak Shah I updated my post according some of your ideas. Thank you :)

                                    – tmfmnk
                                    May 27 at 12:59





                                    @Ronak Shah I updated my post according some of your ideas. Thank you :)

                                    – tmfmnk
                                    May 27 at 12:59













                                    I realised it needed some more tweaking to get exact output but I think it was a similar approach. +1 to you.

                                    – Ronak Shah
                                    May 27 at 13:21





                                    I realised it needed some more tweaking to get exact output but I think it was a similar approach. +1 to you.

                                    – Ronak Shah
                                    May 27 at 13:21











                                    2


















                                    Meanwhile, I came up with another base R solution



                                    lower <- as.numeric(sub(".]*", "", sub(";.*", "", confint)))
                                    upper <- as.numeric(sub("].*", "", sub(".*;", "", confint)))


                                    Thank you all!






                                    share|improve this answer
































                                      2


















                                      Meanwhile, I came up with another base R solution



                                      lower <- as.numeric(sub(".]*", "", sub(";.*", "", confint)))
                                      upper <- as.numeric(sub("].*", "", sub(".*;", "", confint)))


                                      Thank you all!






                                      share|improve this answer






























                                        2














                                        2










                                        2









                                        Meanwhile, I came up with another base R solution



                                        lower <- as.numeric(sub(".]*", "", sub(";.*", "", confint)))
                                        upper <- as.numeric(sub("].*", "", sub(".*;", "", confint)))


                                        Thank you all!






                                        share|improve this answer
















                                        Meanwhile, I came up with another base R solution



                                        lower <- as.numeric(sub(".]*", "", sub(";.*", "", confint)))
                                        upper <- as.numeric(sub("].*", "", sub(".*;", "", confint)))


                                        Thank you all!







                                        share|improve this answer















                                        share|improve this answer




                                        share|improve this answer








                                        edited Jun 11 at 5:31

























                                        answered May 27 at 13:22









                                        FatetaFateta

                                        1298 bronze badges




                                        1298 bronze badges
























                                            1


















                                            You can use functions from the stringr library.



                                            You can split strings with str_split() according a specific character (; in your case), then remove character with str_remove() ([ and ] in your case) and you will obtain what you want.



                                            str_remove(str_split_fixed(confint, ";", n = 2)[,1], '\[') %>% as.numeric()
                                            # [1] 0.741 263.917 12.788 0.680 0.650 0.719





                                            share|improve this answer
































                                              1


















                                              You can use functions from the stringr library.



                                              You can split strings with str_split() according a specific character (; in your case), then remove character with str_remove() ([ and ] in your case) and you will obtain what you want.



                                              str_remove(str_split_fixed(confint, ";", n = 2)[,1], '\[') %>% as.numeric()
                                              # [1] 0.741 263.917 12.788 0.680 0.650 0.719





                                              share|improve this answer






























                                                1














                                                1










                                                1









                                                You can use functions from the stringr library.



                                                You can split strings with str_split() according a specific character (; in your case), then remove character with str_remove() ([ and ] in your case) and you will obtain what you want.



                                                str_remove(str_split_fixed(confint, ";", n = 2)[,1], '\[') %>% as.numeric()
                                                # [1] 0.741 263.917 12.788 0.680 0.650 0.719





                                                share|improve this answer
















                                                You can use functions from the stringr library.



                                                You can split strings with str_split() according a specific character (; in your case), then remove character with str_remove() ([ and ] in your case) and you will obtain what you want.



                                                str_remove(str_split_fixed(confint, ";", n = 2)[,1], '\[') %>% as.numeric()
                                                # [1] 0.741 263.917 12.788 0.680 0.650 0.719






                                                share|improve this answer















                                                share|improve this answer




                                                share|improve this answer








                                                edited May 27 at 12:45

























                                                answered May 27 at 12:38









                                                demarsylvaindemarsylvain

                                                1,5132 gold badges7 silver badges21 bronze badges




                                                1,5132 gold badges7 silver badges21 bronze badges
























                                                    1


















                                                    A tidyverse solution:



                                                    library(dplyr)
                                                    library(tidyr)

                                                    df = data.frame(confint)
                                                    df = df %>%
                                                    mutate(confint = gsub("(\[|\])","",confint)) %>%
                                                    separate(confint,c("lower","upper"),";",convert=T)





                                                    share|improve this answer






























                                                      1


















                                                      A tidyverse solution:



                                                      library(dplyr)
                                                      library(tidyr)

                                                      df = data.frame(confint)
                                                      df = df %>%
                                                      mutate(confint = gsub("(\[|\])","",confint)) %>%
                                                      separate(confint,c("lower","upper"),";",convert=T)





                                                      share|improve this answer




























                                                        1














                                                        1










                                                        1









                                                        A tidyverse solution:



                                                        library(dplyr)
                                                        library(tidyr)

                                                        df = data.frame(confint)
                                                        df = df %>%
                                                        mutate(confint = gsub("(\[|\])","",confint)) %>%
                                                        separate(confint,c("lower","upper"),";",convert=T)





                                                        share|improve this answer














                                                        A tidyverse solution:



                                                        library(dplyr)
                                                        library(tidyr)

                                                        df = data.frame(confint)
                                                        df = df %>%
                                                        mutate(confint = gsub("(\[|\])","",confint)) %>%
                                                        separate(confint,c("lower","upper"),";",convert=T)






                                                        share|improve this answer













                                                        share|improve this answer




                                                        share|improve this answer










                                                        answered May 27 at 14:12









                                                        FinoFino

                                                        1,2405 silver badges16 bronze badges




                                                        1,2405 silver badges16 bronze badges































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