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18

5

may be it seems strange for you, but I want to run command in a specific folder without changing the current folder in the shell. Example - this is what I usually do:

~$ cd .folder
~/.folder$ command --key
~/.folder$ cd ..
~$ another_command --key

Though I want something like this:

~$ .folder command --key
~$ another_command --key

Is it possible?

bash command-line scripts

share|improve this question

edited Jan 22 '14 at 16:49

Rmano

27.6k99 gold badges8585 silver badges155155 bronze badges

asked Jan 22 '14 at 16:02

Timur FayzrakhmanovTimur Fayzrakhmanov

23.8k88 gold badges2121 silver badges3535 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Can't you do ~/.folder/command --key ? Does the command require your current directory to be ~/.folder ?
  
  – glenn jackman
  Jan 22 '14 at 16:58
  
  

  
  
  
  

add a comment
 | 

18

5

may be it seems strange for you, but I want to run command in a specific folder without changing the current folder in the shell. Example - this is what I usually do:

~$ cd .folder
~/.folder$ command --key
~/.folder$ cd ..
~$ another_command --key

Though I want something like this:

~$ .folder command --key
~$ another_command --key

Is it possible?

bash command-line scripts

share|improve this question

edited Jan 22 '14 at 16:49

Rmano

27.6k99 gold badges8585 silver badges155155 bronze badges

asked Jan 22 '14 at 16:02

Timur FayzrakhmanovTimur Fayzrakhmanov

23.8k88 gold badges2121 silver badges3535 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Can't you do ~/.folder/command --key ? Does the command require your current directory to be ~/.folder ?
  
  – glenn jackman
  Jan 22 '14 at 16:58
  
  

  
  
  
  

add a comment
 | 

may be it seems strange for you, but I want to run command in a specific folder without changing the current folder in the shell. Example - this is what I usually do:

~$ cd .folder
~/.folder$ command --key
~/.folder$ cd ..
~$ another_command --key

Though I want something like this:

~$ .folder command --key
~$ another_command --key

Is it possible?

bash command-line scripts

share|improve this question

edited Jan 22 '14 at 16:49

Rmano

27.6k99 gold badges8585 silver badges155155 bronze badges

asked Jan 22 '14 at 16:02

Timur FayzrakhmanovTimur Fayzrakhmanov

23.8k88 gold badges2121 silver badges3535 bronze badges

~$ cd .folder
~/.folder$ command --key
~/.folder$ cd ..
~$ another_command --key

~$ .folder command --key
~$ another_command --key

share|improve this question

edited Jan 22 '14 at 16:49

Rmano

27.6k99 gold badges8585 silver badges155155 bronze badges

asked Jan 22 '14 at 16:02

Timur FayzrakhmanovTimur Fayzrakhmanov

23.8k88 gold badges2121 silver badges3535 bronze badges

share|improve this question

edited Jan 22 '14 at 16:49

Rmano

27.6k99 gold badges8585 silver badges155155 bronze badges

asked Jan 22 '14 at 16:02

Timur FayzrakhmanovTimur Fayzrakhmanov

23.8k88 gold badges2121 silver badges3535 bronze badges

edited Jan 22 '14 at 16:49

Rmano

27.6k99 gold badges8585 silver badges155155 bronze badges

edited Jan 22 '14 at 16:49

Rmano

27.6k99 gold badges8585 silver badges155155 bronze badges

asked Jan 22 '14 at 16:02

Timur FayzrakhmanovTimur Fayzrakhmanov

23.8k88 gold badges2121 silver badges3535 bronze badges

asked Jan 22 '14 at 16:02

Timur FayzrakhmanovTimur Fayzrakhmanov

23.8k88 gold badges2121 silver badges3535 bronze badges

4 Answers
4

active

oldest

votes

43

If you want to avoid the second cd you can use

(cd .folder && command --key)
another_command --key

share|improve this answer

edited Jul 10 '17 at 10:35

answered Jan 22 '14 at 16:06

Florian DieschFlorian Diesch

70k1717 gold badges184184 silver badges197197 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Very quick answer! I even can't to accept it because system doesn't allow me))
  
  – Timur Fayzrakhmanov
  Jan 22 '14 at 16:12
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  magic parenthesis! how does that work? +1
  
  – precise
  Jan 22 '14 at 18:06
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The commands within the parenthesis are run in a new shell process so changing the directory, setting environment variables etc. inside the parenthesis do not affect the parent shell that runs the other commands.
  
  – Florian Diesch
  Jan 22 '14 at 18:25
  

  
  
  
  


• 
  
  
  

  
  7
  

  
  
  
  
  
  

  
  
  I'd change the ; to && for good measure. If the cd fails (e.g. because you typoed the directory name), you probably don't want to run the command.
  
  – geirha
  Jan 24 '14 at 9:35
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  +1 for @geirha's comment. It's a really important point. OP, would you consider editing?
  
  – jaybee
  Jul 10 '17 at 4:11
  

  
  
  
  

 | 
show 2 more comments

8

Without cd... Not even once. I found two ways:

# Save where you are and cd to other dir
pushd .folder
command --key
# Get back where you were at the beginning.
popd
another_command --key

and second:

find . -maxdepth 1 -type d -name ".folder" -execdir command --key ;
another_command --key

share|improve this answer

answered Jan 22 '14 at 16:42

Radu RădeanuRadu Rădeanu

132k3737 gold badges273273 silver badges342342 bronze badges

add a comment
 | 

1

A simple bash function for running a command in specific directory:

# Run a command in specific directory
run_within_dir() 
 target_dir="$1"
 previous_dir=$(pwd)
 shift
 cd $target_dir && "$@"
 cd $previous_dir

Usage:

$ cd ~
$ run_within_dir /tmp ls -l # change into `/tmp` dir before running `ls -al`
$ pwd # still at home dir

share|improve this answer

answered Sep 27 at 2:01

wonderwonder

11111 bronze badge

add a comment
 | 

0

I had a need to do this in a bash-free way, and was surprised there's no utility (similar to env(1) or sudo(1) which runs a command in a modified working directory. So, I wrote a simple C program that does it:

#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>

char ENV_PATH[8192] = "PWD=";

int main(int argc, char** argv) 
 if(argc < 3) 
 fprintf(stderr, "Usage: in <dir> <cmd> [<args>...]n");
 return 1;
 

 if(chdir(argv[1])) 
 fprintf(stderr, "Error setting working directory to "%s"n", argv[1]);
 return 2;
 

 if(!getcwd(ENV_PATH + 4, 8192-4)) 
 fprintf(stderr, "Error getting the full path to the working directory "%s"n", argv[1]);
 return 3;
 

 if(putenv(ENV_PATH)) 
 fprintf(stderr, "Error setting the environment variable "%s"n", ENV_PATH);
 return 4;
 

 execvp(argv[2], argv+2);

The usage is like this:

$ in /path/to/directory command --key

share|improve this answer

answered Aug 15 '18 at 2:32

LucretielLucretiel

101

add a comment
 | 

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43

If you want to avoid the second cd you can use

(cd .folder && command --key)
another_command --key

share|improve this answer

edited Jul 10 '17 at 10:35

answered Jan 22 '14 at 16:06

Florian DieschFlorian Diesch

70k1717 gold badges184184 silver badges197197 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Very quick answer! I even can't to accept it because system doesn't allow me))
  
  – Timur Fayzrakhmanov
  Jan 22 '14 at 16:12
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  magic parenthesis! how does that work? +1
  
  – precise
  Jan 22 '14 at 18:06
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The commands within the parenthesis are run in a new shell process so changing the directory, setting environment variables etc. inside the parenthesis do not affect the parent shell that runs the other commands.
  
  – Florian Diesch
  Jan 22 '14 at 18:25
  

  
  
  
  


• 
  
  
  

  
  7
  

  
  
  
  
  
  

  
  
  I'd change the ; to && for good measure. If the cd fails (e.g. because you typoed the directory name), you probably don't want to run the command.
  
  – geirha
  Jan 24 '14 at 9:35
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  +1 for @geirha's comment. It's a really important point. OP, would you consider editing?
  
  – jaybee
  Jul 10 '17 at 4:11
  

  
  
  
  

 | 
show 2 more comments

43

If you want to avoid the second cd you can use

(cd .folder && command --key)
another_command --key

share|improve this answer

edited Jul 10 '17 at 10:35

answered Jan 22 '14 at 16:06

Florian DieschFlorian Diesch

70k1717 gold badges184184 silver badges197197 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Very quick answer! I even can't to accept it because system doesn't allow me))
  
  – Timur Fayzrakhmanov
  Jan 22 '14 at 16:12
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  magic parenthesis! how does that work? +1
  
  – precise
  Jan 22 '14 at 18:06
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The commands within the parenthesis are run in a new shell process so changing the directory, setting environment variables etc. inside the parenthesis do not affect the parent shell that runs the other commands.
  
  – Florian Diesch
  Jan 22 '14 at 18:25
  

  
  
  
  


• 
  
  
  

  
  7
  

  
  
  
  
  
  

  
  
  I'd change the ; to && for good measure. If the cd fails (e.g. because you typoed the directory name), you probably don't want to run the command.
  
  – geirha
  Jan 24 '14 at 9:35
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  +1 for @geirha's comment. It's a really important point. OP, would you consider editing?
  
  – jaybee
  Jul 10 '17 at 4:11
  

  
  
  
  

 | 
show 2 more comments

If you want to avoid the second cd you can use

(cd .folder && command --key)
another_command --key

share|improve this answer

edited Jul 10 '17 at 10:35

answered Jan 22 '14 at 16:06

Florian DieschFlorian Diesch

70k1717 gold badges184184 silver badges197197 bronze badges

(cd .folder && command --key)
another_command --key

share|improve this answer

edited Jul 10 '17 at 10:35

answered Jan 22 '14 at 16:06

Florian DieschFlorian Diesch

70k1717 gold badges184184 silver badges197197 bronze badges

answered Jan 22 '14 at 16:06

Florian DieschFlorian Diesch

70k1717 gold badges184184 silver badges197197 bronze badges

answered Jan 22 '14 at 16:06

Florian DieschFlorian Diesch

70k1717 gold badges184184 silver badges197197 bronze badges

8

Without cd... Not even once. I found two ways:

# Save where you are and cd to other dir
pushd .folder
command --key
# Get back where you were at the beginning.
popd
another_command --key

and second:

find . -maxdepth 1 -type d -name ".folder" -execdir command --key ;
another_command --key

share|improve this answer

answered Jan 22 '14 at 16:42

Radu RădeanuRadu Rădeanu

132k3737 gold badges273273 silver badges342342 bronze badges

add a comment
 | 

8

Without cd... Not even once. I found two ways:

# Save where you are and cd to other dir
pushd .folder
command --key
# Get back where you were at the beginning.
popd
another_command --key

and second:

find . -maxdepth 1 -type d -name ".folder" -execdir command --key ;
another_command --key

share|improve this answer

answered Jan 22 '14 at 16:42

Radu RădeanuRadu Rădeanu

132k3737 gold badges273273 silver badges342342 bronze badges

add a comment
 | 

Without cd... Not even once. I found two ways:

# Save where you are and cd to other dir
pushd .folder
command --key
# Get back where you were at the beginning.
popd
another_command --key

and second:

find . -maxdepth 1 -type d -name ".folder" -execdir command --key ;
another_command --key

share|improve this answer

answered Jan 22 '14 at 16:42

Radu RădeanuRadu Rădeanu

132k3737 gold badges273273 silver badges342342 bronze badges

# Save where you are and cd to other dir
pushd .folder
command --key
# Get back where you were at the beginning.
popd
another_command --key

find . -maxdepth 1 -type d -name ".folder" -execdir command --key ;
another_command --key

share|improve this answer

answered Jan 22 '14 at 16:42

Radu RădeanuRadu Rădeanu

132k3737 gold badges273273 silver badges342342 bronze badges

answered Jan 22 '14 at 16:42

Radu RădeanuRadu Rădeanu

132k3737 gold badges273273 silver badges342342 bronze badges

answered Jan 22 '14 at 16:42

Radu RădeanuRadu Rădeanu

132k3737 gold badges273273 silver badges342342 bronze badges

1

A simple bash function for running a command in specific directory:

# Run a command in specific directory
run_within_dir() 
 target_dir="$1"
 previous_dir=$(pwd)
 shift
 cd $target_dir && "$@"
 cd $previous_dir

Usage:

$ cd ~
$ run_within_dir /tmp ls -l # change into `/tmp` dir before running `ls -al`
$ pwd # still at home dir

share|improve this answer

answered Sep 27 at 2:01

wonderwonder

11111 bronze badge

add a comment
 | 

1

A simple bash function for running a command in specific directory:

# Run a command in specific directory
run_within_dir() 
 target_dir="$1"
 previous_dir=$(pwd)
 shift
 cd $target_dir && "$@"
 cd $previous_dir

Usage:

$ cd ~
$ run_within_dir /tmp ls -l # change into `/tmp` dir before running `ls -al`
$ pwd # still at home dir

share|improve this answer

answered Sep 27 at 2:01

wonderwonder

11111 bronze badge

add a comment
 | 

A simple bash function for running a command in specific directory:

# Run a command in specific directory
run_within_dir() 
 target_dir="$1"
 previous_dir=$(pwd)
 shift
 cd $target_dir && "$@"
 cd $previous_dir

Usage:

$ cd ~
$ run_within_dir /tmp ls -l # change into `/tmp` dir before running `ls -al`
$ pwd # still at home dir

share|improve this answer

answered Sep 27 at 2:01

wonderwonder

11111 bronze badge

# Run a command in specific directory
run_within_dir() 
 target_dir="$1"
 previous_dir=$(pwd)
 shift
 cd $target_dir && "$@"
 cd $previous_dir

$ cd ~
$ run_within_dir /tmp ls -l # change into `/tmp` dir before running `ls -al`
$ pwd # still at home dir

share|improve this answer

answered Sep 27 at 2:01

wonderwonder

11111 bronze badge

answered Sep 27 at 2:01

wonderwonder

11111 bronze badge

answered Sep 27 at 2:01

wonderwonder

11111 bronze badge

0

I had a need to do this in a bash-free way, and was surprised there's no utility (similar to env(1) or sudo(1) which runs a command in a modified working directory. So, I wrote a simple C program that does it:

#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>

char ENV_PATH[8192] = "PWD=";

int main(int argc, char** argv) 
 if(argc < 3) 
 fprintf(stderr, "Usage: in <dir> <cmd> [<args>...]n");
 return 1;
 

 if(chdir(argv[1])) 
 fprintf(stderr, "Error setting working directory to "%s"n", argv[1]);
 return 2;
 

 if(!getcwd(ENV_PATH + 4, 8192-4)) 
 fprintf(stderr, "Error getting the full path to the working directory "%s"n", argv[1]);
 return 3;
 

 if(putenv(ENV_PATH)) 
 fprintf(stderr, "Error setting the environment variable "%s"n", ENV_PATH);
 return 4;
 

 execvp(argv[2], argv+2);

The usage is like this:

$ in /path/to/directory command --key

share|improve this answer

answered Aug 15 '18 at 2:32

LucretielLucretiel

101

add a comment
 | 

0

I had a need to do this in a bash-free way, and was surprised there's no utility (similar to env(1) or sudo(1) which runs a command in a modified working directory. So, I wrote a simple C program that does it:

#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>

char ENV_PATH[8192] = "PWD=";

int main(int argc, char** argv) 
 if(argc < 3) 
 fprintf(stderr, "Usage: in <dir> <cmd> [<args>...]n");
 return 1;
 

 if(chdir(argv[1])) 
 fprintf(stderr, "Error setting working directory to "%s"n", argv[1]);
 return 2;
 

 if(!getcwd(ENV_PATH + 4, 8192-4)) 
 fprintf(stderr, "Error getting the full path to the working directory "%s"n", argv[1]);
 return 3;
 

 if(putenv(ENV_PATH)) 
 fprintf(stderr, "Error setting the environment variable "%s"n", ENV_PATH);
 return 4;
 

 execvp(argv[2], argv+2);

The usage is like this:

$ in /path/to/directory command --key

share|improve this answer

answered Aug 15 '18 at 2:32

LucretielLucretiel

101

add a comment
 | 

I had a need to do this in a bash-free way, and was surprised there's no utility (similar to env(1) or sudo(1) which runs a command in a modified working directory. So, I wrote a simple C program that does it:

#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>

char ENV_PATH[8192] = "PWD=";

int main(int argc, char** argv) 
 if(argc < 3) 
 fprintf(stderr, "Usage: in <dir> <cmd> [<args>...]n");
 return 1;
 

 if(chdir(argv[1])) 
 fprintf(stderr, "Error setting working directory to "%s"n", argv[1]);
 return 2;
 

 if(!getcwd(ENV_PATH + 4, 8192-4)) 
 fprintf(stderr, "Error getting the full path to the working directory "%s"n", argv[1]);
 return 3;
 

 if(putenv(ENV_PATH)) 
 fprintf(stderr, "Error setting the environment variable "%s"n", ENV_PATH);
 return 4;
 

 execvp(argv[2], argv+2);

The usage is like this:

$ in /path/to/directory command --key

share|improve this answer

answered Aug 15 '18 at 2:32

LucretielLucretiel

101

#include <unistd.h>
#include <stdio.h>
#include <stdlib.h>

char ENV_PATH[8192] = "PWD=";

int main(int argc, char** argv) 
 if(argc < 3) 
 fprintf(stderr, "Usage: in <dir> <cmd> [<args>...]n");
 return 1;
 

 if(chdir(argv[1])) 
 fprintf(stderr, "Error setting working directory to "%s"n", argv[1]);
 return 2;
 

 if(!getcwd(ENV_PATH + 4, 8192-4)) 
 fprintf(stderr, "Error getting the full path to the working directory "%s"n", argv[1]);
 return 3;
 

 if(putenv(ENV_PATH)) 
 fprintf(stderr, "Error setting the environment variable "%s"n", ENV_PATH);
 return 4;
 

 execvp(argv[2], argv+2);

$ in /path/to/directory command --key

share|improve this answer

answered Aug 15 '18 at 2:32

LucretielLucretiel

101

answered Aug 15 '18 at 2:32

LucretielLucretiel

101

answered Aug 15 '18 at 2:32

LucretielLucretiel

101