How to construct and plot the following accumulated list?How to construct pairs in a list?Select rows of matrix that are higher than a given rowHow do I select only those lists whose elements are all above a certain number?Selecting every n-th element from a listFinding pairs where the intersection of them is empty set from a nested listHow to compare and remove x-coordinates (and the associated y-coordinates) that are less than previous x-coordinates?ListPlot with colorsModifying a function so that it will take multiple conditionsHow to construct a list of lengths efficientlySelecting cases from a list based on two conditions
Is there an evolutionary advantage to having two heads?
Smart people send dumb people to a new planet on a space craft that crashes into a body of water
How to plot an unstable attractor?
French translation of “only ever”
Word Mastermind
Tic-Tac-Toe for the terminal
How does an ARM MCU run faster than the external crystal?
If a massive object like Jupiter flew past the Earth how close would it need to come to pull people off of the surface?
Is this story about US tax office reasonable?
How to prevent bad sectors?
Break equation in parts
What's the connection between "kicking a pigeon" and "how a bill becomes a law"?
Ticket sales for Queen at the Live Aid
Is there an explanation for Austria's Freedom Party virtually retaining its vote share despite recent scandal?
Reducing Spill Overs
Best strategy for UK visa for a school trip (travelling alone or accomanpied child)?
Crossword gone overboard
I think I may have violated academic integrity last year - what should I do?
How long does it take to crack RSA 1024 with a PC?
Question about exercise 11.5 in TeXbook
Circumcircle bisects the segment connecting the vertices of two regular even-sided polygons
Can I use the Shadow Step feature to effectively teleport into a Darkness spell I cast upon myself?
Can a non-EU citizen travel within schengen zone freely without passport?
Where is the logic in castrating fighters?
How to construct and plot the following accumulated list?
How to construct pairs in a list?Select rows of matrix that are higher than a given rowHow do I select only those lists whose elements are all above a certain number?Selecting every n-th element from a listFinding pairs where the intersection of them is empty set from a nested listHow to compare and remove x-coordinates (and the associated y-coordinates) that are less than previous x-coordinates?ListPlot with colorsModifying a function so that it will take multiple conditionsHow to construct a list of lengths efficientlySelecting cases from a list based on two conditions
$begingroup$
I have a list, say it is
a = 1,3,3.2,3.9,4,4.4,4.9,5,7,8
To get the accumulate:
acc = Accumlate[a]
I want to plot the number of elements less than or equal to a certain element against the accumulated value of the list elements.
The pairs should look like (acc[[i]], number of elements less than a[[i]]). For instance, (1, 1), (4, 2), (7.2,3), etc.
Then I want to take the derivative of the plot to plot it as well.
plotting list-manipulation
edited Apr 13 at 16:26
Roman
9,46511440
asked Apr 13 at 11:22
HamzaHamza
275
$endgroup$
add a comment |
$begingroup$
I have a list, say it is
a = 1,3,3.2,3.9,4,4.4,4.9,5,7,8
To get the accumulate:
acc = Accumlate[a]
I want to plot the number of elements less than or equal to a certain element against the accumulated value of the list elements.
The pairs should look like (acc[[i]], number of elements less than a[[i]]). For instance, (1, 1), (4, 2), (7.2,3), etc.
Then I want to take the derivative of the plot to plot it as well.
plotting list-manipulation
edited Apr 13 at 16:26
Roman
9,46511440
asked Apr 13 at 11:22
HamzaHamza
275
$endgroup$
1
$begingroup$
The plotting is not a problem seeListPlot. Also, if you want a derivative you will have to define this as you don't have a continuous function. What have you tried so far?
$endgroup$
– Hugh
Apr 13 at 11:26
$begingroup$
The plot is an issue when I have very large number of pairs like 1000 pairs. I am trying to do it using ListPlot and a Do loop but it does not work. I am doing: ListLinePlot[Do[Print[acc[[i]], Count[a[[i]]], i, 10]] but it only prints the pairs for me with an empty plot.
$endgroup$
– Hamza
Apr 13 at 12:04
$begingroup$
Your combined use ofDoandPrintdoesn't do what you expect.Printmerely prints to the screen but does not build a list; useTableinstead. Also,Countis something else.
$endgroup$
– Roman
Apr 13 at 16:29
add a comment |
$begingroup$
I have a list, say it is
a = 1,3,3.2,3.9,4,4.4,4.9,5,7,8
To get the accumulate:
acc = Accumlate[a]
I want to plot the number of elements less than or equal to a certain element against the accumulated value of the list elements.
The pairs should look like (acc[[i]], number of elements less than a[[i]]). For instance, (1, 1), (4, 2), (7.2,3), etc.
Then I want to take the derivative of the plot to plot it as well.
plotting list-manipulation
edited Apr 13 at 16:26
Roman
9,46511440
asked Apr 13 at 11:22
HamzaHamza
275
$endgroup$
I have a list, say it is
a = 1,3,3.2,3.9,4,4.4,4.9,5,7,8
To get the accumulate:
acc = Accumlate[a]
I want to plot the number of elements less than or equal to a certain element against the accumulated value of the list elements.
The pairs should look like (acc[[i]], number of elements less than a[[i]]). For instance, (1, 1), (4, 2), (7.2,3), etc.
Then I want to take the derivative of the plot to plot it as well.
plotting list-manipulation
plotting list-manipulation
edited Apr 13 at 16:26
Roman
9,46511440
asked Apr 13 at 11:22
HamzaHamza
275
edited Apr 13 at 16:26
Roman
9,46511440
asked Apr 13 at 11:22
HamzaHamza
275
edited Apr 13 at 16:26
Roman
9,46511440
edited Apr 13 at 16:26
Roman
9,46511440
edited Apr 13 at 16:26
Roman
9,46511440
9,46511440
asked Apr 13 at 11:22
HamzaHamza
275
asked Apr 13 at 11:22
HamzaHamza
275
asked Apr 13 at 11:22
HamzaHamza
275
275
1
$begingroup$
The plotting is not a problem seeListPlot. Also, if you want a derivative you will have to define this as you don't have a continuous function. What have you tried so far?
$endgroup$
– Hugh
Apr 13 at 11:26
$begingroup$
The plot is an issue when I have very large number of pairs like 1000 pairs. I am trying to do it using ListPlot and a Do loop but it does not work. I am doing: ListLinePlot[Do[Print[acc[[i]], Count[a[[i]]], i, 10]] but it only prints the pairs for me with an empty plot.
$endgroup$
– Hamza
Apr 13 at 12:04
$begingroup$
Your combined use ofDoandPrintdoesn't do what you expect.Printmerely prints to the screen but does not build a list; useTableinstead. Also,Countis something else.
$endgroup$
– Roman
Apr 13 at 16:29
add a comment |
1
$begingroup$
The plotting is not a problem seeListPlot. Also, if you want a derivative you will have to define this as you don't have a continuous function. What have you tried so far?
$endgroup$
– Hugh
Apr 13 at 11:26
$begingroup$
The plot is an issue when I have very large number of pairs like 1000 pairs. I am trying to do it using ListPlot and a Do loop but it does not work. I am doing: ListLinePlot[Do[Print[acc[[i]], Count[a[[i]]], i, 10]] but it only prints the pairs for me with an empty plot.
$endgroup$
– Hamza
Apr 13 at 12:04
$begingroup$
Your combined use ofDoandPrintdoesn't do what you expect.Printmerely prints to the screen but does not build a list; useTableinstead. Also,Countis something else.
$endgroup$
– Roman
Apr 13 at 16:29
1
1
$begingroup$
The plotting is not a problem see
ListPlot. Also, if you want a derivative you will have to define this as you don't have a continuous function. What have you tried so far?$endgroup$
– Hugh
Apr 13 at 11:26
$begingroup$
The plotting is not a problem see
ListPlot. Also, if you want a derivative you will have to define this as you don't have a continuous function. What have you tried so far?$endgroup$
– Hugh
Apr 13 at 11:26
$begingroup$
The plot is an issue when I have very large number of pairs like 1000 pairs. I am trying to do it using ListPlot and a Do loop but it does not work. I am doing: ListLinePlot[Do[Print[acc[[i]], Count[a[[i]]], i, 10]] but it only prints the pairs for me with an empty plot.
$endgroup$
– Hamza
Apr 13 at 12:04
$begingroup$
The plot is an issue when I have very large number of pairs like 1000 pairs. I am trying to do it using ListPlot and a Do loop but it does not work. I am doing: ListLinePlot[Do[Print[acc[[i]], Count[a[[i]]], i, 10]] but it only prints the pairs for me with an empty plot.
$endgroup$
– Hamza
Apr 13 at 12:04
$begingroup$
Your combined use of
Do and Print doesn't do what you expect. Print merely prints to the screen but does not build a list; use Table instead. Also, Count is something else.$endgroup$
– Roman
Apr 13 at 16:29
$begingroup$
Your combined use of
Do and Print doesn't do what you expect. Print merely prints to the screen but does not build a list; use Table instead. Also, Count is something else.$endgroup$
– Roman
Apr 13 at 16:29
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Assuming that there are no duplicate elements in the list, and that the list is sorted in ascending order:
ListLinePlot[Transpose[Accumulate[a], Range[Length[a]]]]
If the list isn't sorted, you should replace Accumulate[a] with Accumulate[Sort[a]].
If you need the derivative, it may be easier to first construct an interpolating function. Here I make the interpolation linear (InterpolationOrder -> 1) but you can change this. You can get the above plot with Plot[b[x], x, 1, Total[a]] and the first-derivative plot with
b = Interpolation[Transpose[Accumulate[Sort[a]], Range[Length[a]]],
InterpolationOrder -> 1];
Plot[b'[x], x, 1, Total[a]]
answered Apr 13 at 16:18
RomanRoman
9,46511440
$endgroup$
add a comment |
$begingroup$
try this
a = 1, 3, 3.2, 3.9, 4, 4.4, 4.9, 5, 7, 8;
acc = Accumulate@a;
aa[x_] := Length@Select[a, # <= a[[x]] &];
list = Transpose[acc, aa /@ Range@Length@a]
ListLinePlot@list
1,1,4,2,7.2,3,11.1,4,15.1,5,19.5,6,24.4,7,29.4,8,36.4,9,44.4,10
answered Apr 13 at 12:45
J42161217J42161217
5,335525
$endgroup$
$begingroup$
The y-axis should represent the number of elements less than or equal a[[i]] not the element itself.
$endgroup$
– Hamza
Apr 13 at 13:57
$begingroup$
@Hamza fixed....
$endgroup$
– J42161217
Apr 13 at 14:12
add a comment |
Your Answer
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "387"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f195111%2fhow-to-construct-and-plot-the-following-accumulated-list%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Assuming that there are no duplicate elements in the list, and that the list is sorted in ascending order:
ListLinePlot[Transpose[Accumulate[a], Range[Length[a]]]]
If the list isn't sorted, you should replace Accumulate[a] with Accumulate[Sort[a]].
If you need the derivative, it may be easier to first construct an interpolating function. Here I make the interpolation linear (InterpolationOrder -> 1) but you can change this. You can get the above plot with Plot[b[x], x, 1, Total[a]] and the first-derivative plot with
b = Interpolation[Transpose[Accumulate[Sort[a]], Range[Length[a]]],
InterpolationOrder -> 1];
Plot[b'[x], x, 1, Total[a]]
answered Apr 13 at 16:18
RomanRoman
9,46511440
$endgroup$
add a comment |
$begingroup$
Assuming that there are no duplicate elements in the list, and that the list is sorted in ascending order:
ListLinePlot[Transpose[Accumulate[a], Range[Length[a]]]]
If the list isn't sorted, you should replace Accumulate[a] with Accumulate[Sort[a]].
If you need the derivative, it may be easier to first construct an interpolating function. Here I make the interpolation linear (InterpolationOrder -> 1) but you can change this. You can get the above plot with Plot[b[x], x, 1, Total[a]] and the first-derivative plot with
b = Interpolation[Transpose[Accumulate[Sort[a]], Range[Length[a]]],
InterpolationOrder -> 1];
Plot[b'[x], x, 1, Total[a]]
answered Apr 13 at 16:18
RomanRoman
9,46511440
$endgroup$
add a comment |
$begingroup$
Assuming that there are no duplicate elements in the list, and that the list is sorted in ascending order:
ListLinePlot[Transpose[Accumulate[a], Range[Length[a]]]]
If the list isn't sorted, you should replace Accumulate[a] with Accumulate[Sort[a]].
If you need the derivative, it may be easier to first construct an interpolating function. Here I make the interpolation linear (InterpolationOrder -> 1) but you can change this. You can get the above plot with Plot[b[x], x, 1, Total[a]] and the first-derivative plot with
b = Interpolation[Transpose[Accumulate[Sort[a]], Range[Length[a]]],
InterpolationOrder -> 1];
Plot[b'[x], x, 1, Total[a]]
answered Apr 13 at 16:18
RomanRoman
9,46511440
$endgroup$
Assuming that there are no duplicate elements in the list, and that the list is sorted in ascending order:
ListLinePlot[Transpose[Accumulate[a], Range[Length[a]]]]
If the list isn't sorted, you should replace Accumulate[a] with Accumulate[Sort[a]].
If you need the derivative, it may be easier to first construct an interpolating function. Here I make the interpolation linear (InterpolationOrder -> 1) but you can change this. You can get the above plot with Plot[b[x], x, 1, Total[a]] and the first-derivative plot with
b = Interpolation[Transpose[Accumulate[Sort[a]], Range[Length[a]]],
InterpolationOrder -> 1];
Plot[b'[x], x, 1, Total[a]]
answered Apr 13 at 16:18
RomanRoman
9,46511440
edited Apr 13 at 16:30
answered Apr 13 at 16:18
RomanRoman
9,46511440
answered Apr 13 at 16:18
RomanRoman
9,46511440
answered Apr 13 at 16:18
RomanRoman
9,46511440
9,46511440
add a comment |
add a comment |
$begingroup$
try this
a = 1, 3, 3.2, 3.9, 4, 4.4, 4.9, 5, 7, 8;
acc = Accumulate@a;
aa[x_] := Length@Select[a, # <= a[[x]] &];
list = Transpose[acc, aa /@ Range@Length@a]
ListLinePlot@list
1,1,4,2,7.2,3,11.1,4,15.1,5,19.5,6,24.4,7,29.4,8,36.4,9,44.4,10
answered Apr 13 at 12:45
J42161217J42161217
5,335525
$endgroup$
$begingroup$
The y-axis should represent the number of elements less than or equal a[[i]] not the element itself.
$endgroup$
– Hamza
Apr 13 at 13:57
$begingroup$
@Hamza fixed....
$endgroup$
– J42161217
Apr 13 at 14:12
add a comment |
$begingroup$
try this
a = 1, 3, 3.2, 3.9, 4, 4.4, 4.9, 5, 7, 8;
acc = Accumulate@a;
aa[x_] := Length@Select[a, # <= a[[x]] &];
list = Transpose[acc, aa /@ Range@Length@a]
ListLinePlot@list
1,1,4,2,7.2,3,11.1,4,15.1,5,19.5,6,24.4,7,29.4,8,36.4,9,44.4,10
answered Apr 13 at 12:45
J42161217J42161217
5,335525
$endgroup$
$begingroup$
The y-axis should represent the number of elements less than or equal a[[i]] not the element itself.
$endgroup$
– Hamza
Apr 13 at 13:57
$begingroup$
@Hamza fixed....
$endgroup$
– J42161217
Apr 13 at 14:12
add a comment |
$begingroup$
try this
a = 1, 3, 3.2, 3.9, 4, 4.4, 4.9, 5, 7, 8;
acc = Accumulate@a;
aa[x_] := Length@Select[a, # <= a[[x]] &];
list = Transpose[acc, aa /@ Range@Length@a]
ListLinePlot@list
1,1,4,2,7.2,3,11.1,4,15.1,5,19.5,6,24.4,7,29.4,8,36.4,9,44.4,10
answered Apr 13 at 12:45
J42161217J42161217
5,335525
$endgroup$
try this
a = 1, 3, 3.2, 3.9, 4, 4.4, 4.9, 5, 7, 8;
acc = Accumulate@a;
aa[x_] := Length@Select[a, # <= a[[x]] &];
list = Transpose[acc, aa /@ Range@Length@a]
ListLinePlot@list
1,1,4,2,7.2,3,11.1,4,15.1,5,19.5,6,24.4,7,29.4,8,36.4,9,44.4,10
answered Apr 13 at 12:45
J42161217J42161217
5,335525
edited Apr 13 at 14:12
answered Apr 13 at 12:45
J42161217J42161217
5,335525
answered Apr 13 at 12:45
J42161217J42161217
5,335525
answered Apr 13 at 12:45
J42161217J42161217
5,335525
5,335525
$begingroup$
The y-axis should represent the number of elements less than or equal a[[i]] not the element itself.
$endgroup$
– Hamza
Apr 13 at 13:57
$begingroup$
@Hamza fixed....
$endgroup$
– J42161217
Apr 13 at 14:12
add a comment |
$begingroup$
The y-axis should represent the number of elements less than or equal a[[i]] not the element itself.
$endgroup$
– Hamza
Apr 13 at 13:57
$begingroup$
@Hamza fixed....
$endgroup$
– J42161217
Apr 13 at 14:12
$begingroup$
The y-axis should represent the number of elements less than or equal a[[i]] not the element itself.
$endgroup$
– Hamza
Apr 13 at 13:57
$begingroup$
The y-axis should represent the number of elements less than or equal a[[i]] not the element itself.
$endgroup$
– Hamza
Apr 13 at 13:57
$begingroup$
@Hamza fixed....
$endgroup$
– J42161217
Apr 13 at 14:12
$begingroup$
@Hamza fixed....
$endgroup$
– J42161217
Apr 13 at 14:12
add a comment |
Thanks for contributing an answer to Mathematica Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f195111%2fhow-to-construct-and-plot-the-following-accumulated-list%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
$begingroup$
The plotting is not a problem see
ListPlot. Also, if you want a derivative you will have to define this as you don't have a continuous function. What have you tried so far?$endgroup$
– Hugh
Apr 13 at 11:26
$begingroup$
The plot is an issue when I have very large number of pairs like 1000 pairs. I am trying to do it using ListPlot and a Do loop but it does not work. I am doing: ListLinePlot[Do[Print[acc[[i]], Count[a[[i]]], i, 10]] but it only prints the pairs for me with an empty plot.
$endgroup$
– Hamza
Apr 13 at 12:04
$begingroup$
Your combined use of
DoandPrintdoesn't do what you expect.Printmerely prints to the screen but does not build a list; useTableinstead. Also,Countis something else.$endgroup$
– Roman
Apr 13 at 16:29