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I found a password with hashcat, but it doesn't work


How easy is it to find a password in a huge text file?Line Length Exception in hashcatwhat order does the incremental mode of john the ripper, brute force passwords in?John the ripper does not crack passwordCant crack Responder hashes with John or HashcatWhy won't pdf2john extract the password hash of this encrypted pdf? Getting blank resultsBrute-Forcing DVWA login page with hydraCan't figure out input format for Hashcat salts with odd characters in salt






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty
margin-bottom:0;









62

















My assignment required me to find the password for a PowerPoint file (97 - 2003, v. 8.0 - v. 11.0).



I used office2john.py to retrieve the hash, and I removed the file name.



The hash is:




$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a




Then I put the hash in hashcat with the following command:



hashcat64.exe -m 9800 -a 3 s.hash ?l?l?l?l?l?l?l?l -D 1,2 -w 4


hashcat cracked it and gave me the password, but when I insert the password in PowerPoint it says that the password is wrong (iemuzqau).



Did I do something wrong?










share|improve this question























  • 11





    Could you comment on the accepted answer what’s the solution for you was? Did any of the other passwords worked?

    – eckes
    Jun 17 at 9:13






  • 3





    i'm still cracking a working password i'm using the '?l?d_-.:;!' charset

    – Fabius
    Jun 17 at 9:31

















62

















My assignment required me to find the password for a PowerPoint file (97 - 2003, v. 8.0 - v. 11.0).



I used office2john.py to retrieve the hash, and I removed the file name.



The hash is:




$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a




Then I put the hash in hashcat with the following command:



hashcat64.exe -m 9800 -a 3 s.hash ?l?l?l?l?l?l?l?l -D 1,2 -w 4


hashcat cracked it and gave me the password, but when I insert the password in PowerPoint it says that the password is wrong (iemuzqau).



Did I do something wrong?










share|improve this question























  • 11





    Could you comment on the accepted answer what’s the solution for you was? Did any of the other passwords worked?

    – eckes
    Jun 17 at 9:13






  • 3





    i'm still cracking a working password i'm using the '?l?d_-.:;!' charset

    – Fabius
    Jun 17 at 9:31













62












62








62


11






My assignment required me to find the password for a PowerPoint file (97 - 2003, v. 8.0 - v. 11.0).



I used office2john.py to retrieve the hash, and I removed the file name.



The hash is:




$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a




Then I put the hash in hashcat with the following command:



hashcat64.exe -m 9800 -a 3 s.hash ?l?l?l?l?l?l?l?l -D 1,2 -w 4


hashcat cracked it and gave me the password, but when I insert the password in PowerPoint it says that the password is wrong (iemuzqau).



Did I do something wrong?










share|improve this question

















My assignment required me to find the password for a PowerPoint file (97 - 2003, v. 8.0 - v. 11.0).



I used office2john.py to retrieve the hash, and I removed the file name.



The hash is:




$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a




Then I put the hash in hashcat with the following command:



hashcat64.exe -m 9800 -a 3 s.hash ?l?l?l?l?l?l?l?l -D 1,2 -w 4


hashcat cracked it and gave me the password, but when I insert the password in PowerPoint it says that the password is wrong (iemuzqau).



Did I do something wrong?







passwords hash password-cracking hashcat






share|improve this question
















share|improve this question













share|improve this question




share|improve this question








edited Jun 17 at 8:53









Peter Mortensen

7524 silver badges9 bronze badges




7524 silver badges9 bronze badges










asked Jun 16 at 7:20









FabiusFabius

4191 gold badge2 silver badges8 bronze badges




4191 gold badge2 silver badges8 bronze badges










  • 11





    Could you comment on the accepted answer what’s the solution for you was? Did any of the other passwords worked?

    – eckes
    Jun 17 at 9:13






  • 3





    i'm still cracking a working password i'm using the '?l?d_-.:;!' charset

    – Fabius
    Jun 17 at 9:31












  • 11





    Could you comment on the accepted answer what’s the solution for you was? Did any of the other passwords worked?

    – eckes
    Jun 17 at 9:13






  • 3





    i'm still cracking a working password i'm using the '?l?d_-.:;!' charset

    – Fabius
    Jun 17 at 9:31







11




11





Could you comment on the accepted answer what’s the solution for you was? Did any of the other passwords worked?

– eckes
Jun 17 at 9:13





Could you comment on the accepted answer what’s the solution for you was? Did any of the other passwords worked?

– eckes
Jun 17 at 9:13




3




3





i'm still cracking a working password i'm using the '?l?d_-.:;!' charset

– Fabius
Jun 17 at 9:31





i'm still cracking a working password i'm using the '?l?d_-.:;!' charset

– Fabius
Jun 17 at 9:31










1 Answer
1






active

oldest

votes


















96


















The password hashes for MS Office 97-2003 are vulnerable to collision attacks. That is, multiple passwords exist that should be able to open the document.



That also means that the password "iemuzqau" is not necessarily the original password that was set by the author. It is just one of the passwords that should be accepted, because it matches the internal scheme to check for the correct password.



For the $3 type hash that you got, the hashcat methods 9810 and 9820 can be used to create password candidates faster than raw brute-force (mode 9800).
According to the linked thread that should work by first executing the following command:



hashcat64.exe -m 9810 -w 3 s.hash -o hash.rc4 -a 3 ?b?b?b?b?b


The output will be something like:



 $oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd


Then you take the output of that command and execute:



hashcat64.exe -m 9820 -w 3 hash.rc4 -a 3 ?l?l?l?l?l?l?l?l?l?l --increment


This will then produce the following output:



$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd:iemuzqau
$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd:cvsfjkwoa
$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd:yrmbatnya
$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd:mzvmxmyke
...


The mode 9820 is a mode that "keeps cracking". That is, it will not stop outputting valid passwords after the first match. This behaviour was changed recently so you might have to specify --keep-guessing on your command line, depending on the version that you use.



That does not explain why your password is not accepted by PowerPoint as only valid candidates should be generated by hashcat. But maybe you can use the described workflow to generate additional valid passwords and try them.






share|improve this answer























  • 33





    I must be missing something, but shouldn’t a collision work the same as the original password?

    – nadavvadan
    Jun 17 at 20:26






  • 44





    @nadavvadan: Not sure if PPT works that way, but in general, no. If the software encrypts the whole file with the original password, and stores the hash just for verification purposes, then it'll accept anything that matches the hash, but decrypting the file with anything but the real password will yield unreadable garbage.

    – Guntram Blohm
    Jun 17 at 21:58






  • 33





    I was missing the obvious - there’s a hash collision, but there’s also encryption involved which obviously uses a different algorithm; the collision only applies for the hash function.

    – nadavvadan
    Jun 18 at 4:09






  • 9





    Ok, so if this is the case, what's the point of the hash at all? Couldn't it just go straight to decrypting and decide (i.e. depending on valid header data) if the password was right or not? I mean, this appears to be the case if a valid password for a given hash does not work. So why's there a hash in the first place?

    – Num Lock
    Jun 18 at 4:59






  • 21





    @NumLock The most important reason is probably UX. Relying on looking at whether your decrypted data looks valid or corrupt to tell if you were given a correct password makes it impossible to distinguish between the user providing an incorrect password and providing a correct password to a corrupt or truncated file. Consequently, it means that you can't tell the user which of those things has happened; you just have to report to them that either they provided the wrong password or the file is corrupt, which is a crappy experience for the user. Office's approach solves that problem.

    – Mark Amery
    Jun 18 at 11:35













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1 Answer
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active

oldest

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1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









96


















The password hashes for MS Office 97-2003 are vulnerable to collision attacks. That is, multiple passwords exist that should be able to open the document.



That also means that the password "iemuzqau" is not necessarily the original password that was set by the author. It is just one of the passwords that should be accepted, because it matches the internal scheme to check for the correct password.



For the $3 type hash that you got, the hashcat methods 9810 and 9820 can be used to create password candidates faster than raw brute-force (mode 9800).
According to the linked thread that should work by first executing the following command:



hashcat64.exe -m 9810 -w 3 s.hash -o hash.rc4 -a 3 ?b?b?b?b?b


The output will be something like:



 $oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd


Then you take the output of that command and execute:



hashcat64.exe -m 9820 -w 3 hash.rc4 -a 3 ?l?l?l?l?l?l?l?l?l?l --increment


This will then produce the following output:



$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd:iemuzqau
$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd:cvsfjkwoa
$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd:yrmbatnya
$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd:mzvmxmyke
...


The mode 9820 is a mode that "keeps cracking". That is, it will not stop outputting valid passwords after the first match. This behaviour was changed recently so you might have to specify --keep-guessing on your command line, depending on the version that you use.



That does not explain why your password is not accepted by PowerPoint as only valid candidates should be generated by hashcat. But maybe you can use the described workflow to generate additional valid passwords and try them.






share|improve this answer























  • 33





    I must be missing something, but shouldn’t a collision work the same as the original password?

    – nadavvadan
    Jun 17 at 20:26






  • 44





    @nadavvadan: Not sure if PPT works that way, but in general, no. If the software encrypts the whole file with the original password, and stores the hash just for verification purposes, then it'll accept anything that matches the hash, but decrypting the file with anything but the real password will yield unreadable garbage.

    – Guntram Blohm
    Jun 17 at 21:58






  • 33





    I was missing the obvious - there’s a hash collision, but there’s also encryption involved which obviously uses a different algorithm; the collision only applies for the hash function.

    – nadavvadan
    Jun 18 at 4:09






  • 9





    Ok, so if this is the case, what's the point of the hash at all? Couldn't it just go straight to decrypting and decide (i.e. depending on valid header data) if the password was right or not? I mean, this appears to be the case if a valid password for a given hash does not work. So why's there a hash in the first place?

    – Num Lock
    Jun 18 at 4:59






  • 21





    @NumLock The most important reason is probably UX. Relying on looking at whether your decrypted data looks valid or corrupt to tell if you were given a correct password makes it impossible to distinguish between the user providing an incorrect password and providing a correct password to a corrupt or truncated file. Consequently, it means that you can't tell the user which of those things has happened; you just have to report to them that either they provided the wrong password or the file is corrupt, which is a crappy experience for the user. Office's approach solves that problem.

    – Mark Amery
    Jun 18 at 11:35
















96


















The password hashes for MS Office 97-2003 are vulnerable to collision attacks. That is, multiple passwords exist that should be able to open the document.



That also means that the password "iemuzqau" is not necessarily the original password that was set by the author. It is just one of the passwords that should be accepted, because it matches the internal scheme to check for the correct password.



For the $3 type hash that you got, the hashcat methods 9810 and 9820 can be used to create password candidates faster than raw brute-force (mode 9800).
According to the linked thread that should work by first executing the following command:



hashcat64.exe -m 9810 -w 3 s.hash -o hash.rc4 -a 3 ?b?b?b?b?b


The output will be something like:



 $oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd


Then you take the output of that command and execute:



hashcat64.exe -m 9820 -w 3 hash.rc4 -a 3 ?l?l?l?l?l?l?l?l?l?l --increment


This will then produce the following output:



$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd:iemuzqau
$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd:cvsfjkwoa
$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd:yrmbatnya
$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd:mzvmxmyke
...


The mode 9820 is a mode that "keeps cracking". That is, it will not stop outputting valid passwords after the first match. This behaviour was changed recently so you might have to specify --keep-guessing on your command line, depending on the version that you use.



That does not explain why your password is not accepted by PowerPoint as only valid candidates should be generated by hashcat. But maybe you can use the described workflow to generate additional valid passwords and try them.






share|improve this answer























  • 33





    I must be missing something, but shouldn’t a collision work the same as the original password?

    – nadavvadan
    Jun 17 at 20:26






  • 44





    @nadavvadan: Not sure if PPT works that way, but in general, no. If the software encrypts the whole file with the original password, and stores the hash just for verification purposes, then it'll accept anything that matches the hash, but decrypting the file with anything but the real password will yield unreadable garbage.

    – Guntram Blohm
    Jun 17 at 21:58






  • 33





    I was missing the obvious - there’s a hash collision, but there’s also encryption involved which obviously uses a different algorithm; the collision only applies for the hash function.

    – nadavvadan
    Jun 18 at 4:09






  • 9





    Ok, so if this is the case, what's the point of the hash at all? Couldn't it just go straight to decrypting and decide (i.e. depending on valid header data) if the password was right or not? I mean, this appears to be the case if a valid password for a given hash does not work. So why's there a hash in the first place?

    – Num Lock
    Jun 18 at 4:59






  • 21





    @NumLock The most important reason is probably UX. Relying on looking at whether your decrypted data looks valid or corrupt to tell if you were given a correct password makes it impossible to distinguish between the user providing an incorrect password and providing a correct password to a corrupt or truncated file. Consequently, it means that you can't tell the user which of those things has happened; you just have to report to them that either they provided the wrong password or the file is corrupt, which is a crappy experience for the user. Office's approach solves that problem.

    – Mark Amery
    Jun 18 at 11:35














96














96










96









The password hashes for MS Office 97-2003 are vulnerable to collision attacks. That is, multiple passwords exist that should be able to open the document.



That also means that the password "iemuzqau" is not necessarily the original password that was set by the author. It is just one of the passwords that should be accepted, because it matches the internal scheme to check for the correct password.



For the $3 type hash that you got, the hashcat methods 9810 and 9820 can be used to create password candidates faster than raw brute-force (mode 9800).
According to the linked thread that should work by first executing the following command:



hashcat64.exe -m 9810 -w 3 s.hash -o hash.rc4 -a 3 ?b?b?b?b?b


The output will be something like:



 $oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd


Then you take the output of that command and execute:



hashcat64.exe -m 9820 -w 3 hash.rc4 -a 3 ?l?l?l?l?l?l?l?l?l?l --increment


This will then produce the following output:



$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd:iemuzqau
$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd:cvsfjkwoa
$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd:yrmbatnya
$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd:mzvmxmyke
...


The mode 9820 is a mode that "keeps cracking". That is, it will not stop outputting valid passwords after the first match. This behaviour was changed recently so you might have to specify --keep-guessing on your command line, depending on the version that you use.



That does not explain why your password is not accepted by PowerPoint as only valid candidates should be generated by hashcat. But maybe you can use the described workflow to generate additional valid passwords and try them.






share|improve this answer
















The password hashes for MS Office 97-2003 are vulnerable to collision attacks. That is, multiple passwords exist that should be able to open the document.



That also means that the password "iemuzqau" is not necessarily the original password that was set by the author. It is just one of the passwords that should be accepted, because it matches the internal scheme to check for the correct password.



For the $3 type hash that you got, the hashcat methods 9810 and 9820 can be used to create password candidates faster than raw brute-force (mode 9800).
According to the linked thread that should work by first executing the following command:



hashcat64.exe -m 9810 -w 3 s.hash -o hash.rc4 -a 3 ?b?b?b?b?b


The output will be something like:



 $oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd


Then you take the output of that command and execute:



hashcat64.exe -m 9820 -w 3 hash.rc4 -a 3 ?l?l?l?l?l?l?l?l?l?l --increment


This will then produce the following output:



$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd:iemuzqau
$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd:cvsfjkwoa
$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd:yrmbatnya
$oldoffice$3*1b085471a28011c5348c5f0b8f29d24e*99294d3ebc790cfc325cca851f56d433*9e3556d0775d0aa198060a815be7be4c58e1fe2a:5ffd0b24bd:mzvmxmyke
...


The mode 9820 is a mode that "keeps cracking". That is, it will not stop outputting valid passwords after the first match. This behaviour was changed recently so you might have to specify --keep-guessing on your command line, depending on the version that you use.



That does not explain why your password is not accepted by PowerPoint as only valid candidates should be generated by hashcat. But maybe you can use the described workflow to generate additional valid passwords and try them.







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edited Jun 18 at 19:12









Michael

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answered Jun 16 at 11:31









DenisDenis

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  • 33





    I must be missing something, but shouldn’t a collision work the same as the original password?

    – nadavvadan
    Jun 17 at 20:26






  • 44





    @nadavvadan: Not sure if PPT works that way, but in general, no. If the software encrypts the whole file with the original password, and stores the hash just for verification purposes, then it'll accept anything that matches the hash, but decrypting the file with anything but the real password will yield unreadable garbage.

    – Guntram Blohm
    Jun 17 at 21:58






  • 33





    I was missing the obvious - there’s a hash collision, but there’s also encryption involved which obviously uses a different algorithm; the collision only applies for the hash function.

    – nadavvadan
    Jun 18 at 4:09






  • 9





    Ok, so if this is the case, what's the point of the hash at all? Couldn't it just go straight to decrypting and decide (i.e. depending on valid header data) if the password was right or not? I mean, this appears to be the case if a valid password for a given hash does not work. So why's there a hash in the first place?

    – Num Lock
    Jun 18 at 4:59






  • 21





    @NumLock The most important reason is probably UX. Relying on looking at whether your decrypted data looks valid or corrupt to tell if you were given a correct password makes it impossible to distinguish between the user providing an incorrect password and providing a correct password to a corrupt or truncated file. Consequently, it means that you can't tell the user which of those things has happened; you just have to report to them that either they provided the wrong password or the file is corrupt, which is a crappy experience for the user. Office's approach solves that problem.

    – Mark Amery
    Jun 18 at 11:35













  • 33





    I must be missing something, but shouldn’t a collision work the same as the original password?

    – nadavvadan
    Jun 17 at 20:26






  • 44





    @nadavvadan: Not sure if PPT works that way, but in general, no. If the software encrypts the whole file with the original password, and stores the hash just for verification purposes, then it'll accept anything that matches the hash, but decrypting the file with anything but the real password will yield unreadable garbage.

    – Guntram Blohm
    Jun 17 at 21:58






  • 33





    I was missing the obvious - there’s a hash collision, but there’s also encryption involved which obviously uses a different algorithm; the collision only applies for the hash function.

    – nadavvadan
    Jun 18 at 4:09






  • 9





    Ok, so if this is the case, what's the point of the hash at all? Couldn't it just go straight to decrypting and decide (i.e. depending on valid header data) if the password was right or not? I mean, this appears to be the case if a valid password for a given hash does not work. So why's there a hash in the first place?

    – Num Lock
    Jun 18 at 4:59






  • 21





    @NumLock The most important reason is probably UX. Relying on looking at whether your decrypted data looks valid or corrupt to tell if you were given a correct password makes it impossible to distinguish between the user providing an incorrect password and providing a correct password to a corrupt or truncated file. Consequently, it means that you can't tell the user which of those things has happened; you just have to report to them that either they provided the wrong password or the file is corrupt, which is a crappy experience for the user. Office's approach solves that problem.

    – Mark Amery
    Jun 18 at 11:35








33




33





I must be missing something, but shouldn’t a collision work the same as the original password?

– nadavvadan
Jun 17 at 20:26





I must be missing something, but shouldn’t a collision work the same as the original password?

– nadavvadan
Jun 17 at 20:26




44




44





@nadavvadan: Not sure if PPT works that way, but in general, no. If the software encrypts the whole file with the original password, and stores the hash just for verification purposes, then it'll accept anything that matches the hash, but decrypting the file with anything but the real password will yield unreadable garbage.

– Guntram Blohm
Jun 17 at 21:58





@nadavvadan: Not sure if PPT works that way, but in general, no. If the software encrypts the whole file with the original password, and stores the hash just for verification purposes, then it'll accept anything that matches the hash, but decrypting the file with anything but the real password will yield unreadable garbage.

– Guntram Blohm
Jun 17 at 21:58




33




33





I was missing the obvious - there’s a hash collision, but there’s also encryption involved which obviously uses a different algorithm; the collision only applies for the hash function.

– nadavvadan
Jun 18 at 4:09





I was missing the obvious - there’s a hash collision, but there’s also encryption involved which obviously uses a different algorithm; the collision only applies for the hash function.

– nadavvadan
Jun 18 at 4:09




9




9





Ok, so if this is the case, what's the point of the hash at all? Couldn't it just go straight to decrypting and decide (i.e. depending on valid header data) if the password was right or not? I mean, this appears to be the case if a valid password for a given hash does not work. So why's there a hash in the first place?

– Num Lock
Jun 18 at 4:59





Ok, so if this is the case, what's the point of the hash at all? Couldn't it just go straight to decrypting and decide (i.e. depending on valid header data) if the password was right or not? I mean, this appears to be the case if a valid password for a given hash does not work. So why's there a hash in the first place?

– Num Lock
Jun 18 at 4:59




21




21





@NumLock The most important reason is probably UX. Relying on looking at whether your decrypted data looks valid or corrupt to tell if you were given a correct password makes it impossible to distinguish between the user providing an incorrect password and providing a correct password to a corrupt or truncated file. Consequently, it means that you can't tell the user which of those things has happened; you just have to report to them that either they provided the wrong password or the file is corrupt, which is a crappy experience for the user. Office's approach solves that problem.

– Mark Amery
Jun 18 at 11:35






@NumLock The most important reason is probably UX. Relying on looking at whether your decrypted data looks valid or corrupt to tell if you were given a correct password makes it impossible to distinguish between the user providing an incorrect password and providing a correct password to a corrupt or truncated file. Consequently, it means that you can't tell the user which of those things has happened; you just have to report to them that either they provided the wrong password or the file is corrupt, which is a crappy experience for the user. Office's approach solves that problem.

– Mark Amery
Jun 18 at 11:35



















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