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Removing certain file types that do not contain the hostname in the file name
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I am doing a file deployment for multiple machines per site, so it is much easier for me to zip all the files once and deploy to every machine. However I would like to remove the config for all the other PC's.
The zip contains various generic files, and also a specific config for each machine.
For example a less of the zip would provide:
generic1.xjson
generic2.xjson
generic3.xjson
generic1.yjson
generic2.yjson
PC-1-1.json
PC-1-2.json
PC-1-3.json
So I am looking to remove every PC-1-*.json that does not contain the PC's hostname.
(the PC hostnames are always exactly PC-1-1, etc.)
I was trying to do something along the lines of:
ls -1 | grep -v *$hostname* | xargs -0 rm *PC-*-*.json
This would remove all the files including the one for the current hostname.
Looking for what I have wrong in this, or if there is a better way of doing this function.
bash files uninstall hostname xargs
asked Aug 9 at 19:19
Andrew WilliamsAndrew Williams
182 bronze badges
add a comment
|
I am doing a file deployment for multiple machines per site, so it is much easier for me to zip all the files once and deploy to every machine. However I would like to remove the config for all the other PC's.
The zip contains various generic files, and also a specific config for each machine.
For example a less of the zip would provide:
generic1.xjson
generic2.xjson
generic3.xjson
generic1.yjson
generic2.yjson
PC-1-1.json
PC-1-2.json
PC-1-3.json
So I am looking to remove every PC-1-*.json that does not contain the PC's hostname.
(the PC hostnames are always exactly PC-1-1, etc.)
I was trying to do something along the lines of:
ls -1 | grep -v *$hostname* | xargs -0 rm *PC-*-*.json
This would remove all the files including the one for the current hostname.
Looking for what I have wrong in this, or if there is a better way of doing this function.
bash files uninstall hostname xargs
asked Aug 9 at 19:19
Andrew WilliamsAndrew Williams
182 bronze badges
add a comment
|
I am doing a file deployment for multiple machines per site, so it is much easier for me to zip all the files once and deploy to every machine. However I would like to remove the config for all the other PC's.
The zip contains various generic files, and also a specific config for each machine.
For example a less of the zip would provide:
generic1.xjson
generic2.xjson
generic3.xjson
generic1.yjson
generic2.yjson
PC-1-1.json
PC-1-2.json
PC-1-3.json
So I am looking to remove every PC-1-*.json that does not contain the PC's hostname.
(the PC hostnames are always exactly PC-1-1, etc.)
I was trying to do something along the lines of:
ls -1 | grep -v *$hostname* | xargs -0 rm *PC-*-*.json
This would remove all the files including the one for the current hostname.
Looking for what I have wrong in this, or if there is a better way of doing this function.
bash files uninstall hostname xargs
asked Aug 9 at 19:19
Andrew WilliamsAndrew Williams
182 bronze badges
I am doing a file deployment for multiple machines per site, so it is much easier for me to zip all the files once and deploy to every machine. However I would like to remove the config for all the other PC's.
The zip contains various generic files, and also a specific config for each machine.
For example a less of the zip would provide:
generic1.xjson
generic2.xjson
generic3.xjson
generic1.yjson
generic2.yjson
PC-1-1.json
PC-1-2.json
PC-1-3.json
So I am looking to remove every PC-1-*.json that does not contain the PC's hostname.
(the PC hostnames are always exactly PC-1-1, etc.)
I was trying to do something along the lines of:
ls -1 | grep -v *$hostname* | xargs -0 rm *PC-*-*.json
This would remove all the files including the one for the current hostname.
Looking for what I have wrong in this, or if there is a better way of doing this function.
bash files uninstall hostname xargs
bash files uninstall hostname xargs
asked Aug 9 at 19:19
Andrew WilliamsAndrew Williams
182 bronze badges
asked Aug 9 at 19:19
Andrew WilliamsAndrew Williams
182 bronze badges
asked Aug 9 at 19:19
Andrew WilliamsAndrew Williams
182 bronze badges
asked Aug 9 at 19:19
Andrew WilliamsAndrew Williams
182 bronze badges
asked Aug 9 at 19:19
Andrew WilliamsAndrew Williams
182 bronze badges
182 bronze badges
add a comment
|
add a comment
|
1 Answer
1
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oldest
votes
Your command does not work as expected because of rm *PC-*-*.json! it would expands by shell and includes all PC-x-x.json files.
Actually you're using xargs in a wrong way.
Something like this should do the job:
ls -Q1 | grep -v $hostname | grep -E "PC-1-[0-9]+.json" | xargs echo
change echo with rm when you where sure that it works.
A better solution would be using find:
find -type f -name "PC-*-*.json" -not -name "*$hostname*" -exec rm -i +
- remove
-ifromrmafter you were sure that command is working correctly.
answered Aug 9 at 19:38
RavexinaRavexina
36.9k15 gold badges101 silver badges131 bronze badges
I ended up using the: ls -Q1 | grep -v $HOSTNAME | grep -E "[0-99]+.json" | xargs rm Variant, I cut off the PC-1 part of the second grep, as there should never be any json in my environment that is formatted like this expect the files I want to target. Also, like an idiot, I was using $hostname in place of $HOSTNAME, which, being relatively new to this I didn't know was not printing the hostname in my query. Thanks for the help!
– Andrew Williams
Aug 9 at 19:52
1
Nice! I think it makes a difference if you switch the filename tests and do-iname "PC-*-*.json" -not -iname "*$hostname*"instead as the second one has to be evaluated much more seldom this way. Also, OP wants-type f(as the first test). Oh and wait, why-iname? OP definitely wantsnamefor both tests.
– dessert
Aug 9 at 19:54
@dessert You're right... I'll update the answer.inameis somehow burned into my memory and I always use it...
– Ravexina
Aug 10 at 5:54
@AndrewWilliams You're welcome... aboutHOSTNAMEyou are correct! I thoughthostnameis a variable you defined youreslf ;)
– Ravexina
Aug 10 at 5:57
add a comment
|
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your command does not work as expected because of rm *PC-*-*.json! it would expands by shell and includes all PC-x-x.json files.
Actually you're using xargs in a wrong way.
Something like this should do the job:
ls -Q1 | grep -v $hostname | grep -E "PC-1-[0-9]+.json" | xargs echo
change echo with rm when you where sure that it works.
A better solution would be using find:
find -type f -name "PC-*-*.json" -not -name "*$hostname*" -exec rm -i +
- remove
-ifromrmafter you were sure that command is working correctly.
answered Aug 9 at 19:38
RavexinaRavexina
36.9k15 gold badges101 silver badges131 bronze badges
I ended up using the: ls -Q1 | grep -v $HOSTNAME | grep -E "[0-99]+.json" | xargs rm Variant, I cut off the PC-1 part of the second grep, as there should never be any json in my environment that is formatted like this expect the files I want to target. Also, like an idiot, I was using $hostname in place of $HOSTNAME, which, being relatively new to this I didn't know was not printing the hostname in my query. Thanks for the help!
– Andrew Williams
Aug 9 at 19:52
1
Nice! I think it makes a difference if you switch the filename tests and do-iname "PC-*-*.json" -not -iname "*$hostname*"instead as the second one has to be evaluated much more seldom this way. Also, OP wants-type f(as the first test). Oh and wait, why-iname? OP definitely wantsnamefor both tests.
– dessert
Aug 9 at 19:54
@dessert You're right... I'll update the answer.inameis somehow burned into my memory and I always use it...
– Ravexina
Aug 10 at 5:54
@AndrewWilliams You're welcome... aboutHOSTNAMEyou are correct! I thoughthostnameis a variable you defined youreslf ;)
– Ravexina
Aug 10 at 5:57
add a comment
|
Your command does not work as expected because of rm *PC-*-*.json! it would expands by shell and includes all PC-x-x.json files.
Actually you're using xargs in a wrong way.
Something like this should do the job:
ls -Q1 | grep -v $hostname | grep -E "PC-1-[0-9]+.json" | xargs echo
change echo with rm when you where sure that it works.
A better solution would be using find:
find -type f -name "PC-*-*.json" -not -name "*$hostname*" -exec rm -i +
- remove
-ifromrmafter you were sure that command is working correctly.
answered Aug 9 at 19:38
RavexinaRavexina
36.9k15 gold badges101 silver badges131 bronze badges
I ended up using the: ls -Q1 | grep -v $HOSTNAME | grep -E "[0-99]+.json" | xargs rm Variant, I cut off the PC-1 part of the second grep, as there should never be any json in my environment that is formatted like this expect the files I want to target. Also, like an idiot, I was using $hostname in place of $HOSTNAME, which, being relatively new to this I didn't know was not printing the hostname in my query. Thanks for the help!
– Andrew Williams
Aug 9 at 19:52
1
Nice! I think it makes a difference if you switch the filename tests and do-iname "PC-*-*.json" -not -iname "*$hostname*"instead as the second one has to be evaluated much more seldom this way. Also, OP wants-type f(as the first test). Oh and wait, why-iname? OP definitely wantsnamefor both tests.
– dessert
Aug 9 at 19:54
@dessert You're right... I'll update the answer.inameis somehow burned into my memory and I always use it...
– Ravexina
Aug 10 at 5:54
@AndrewWilliams You're welcome... aboutHOSTNAMEyou are correct! I thoughthostnameis a variable you defined youreslf ;)
– Ravexina
Aug 10 at 5:57
add a comment
|
Your command does not work as expected because of rm *PC-*-*.json! it would expands by shell and includes all PC-x-x.json files.
Actually you're using xargs in a wrong way.
Something like this should do the job:
ls -Q1 | grep -v $hostname | grep -E "PC-1-[0-9]+.json" | xargs echo
change echo with rm when you where sure that it works.
A better solution would be using find:
find -type f -name "PC-*-*.json" -not -name "*$hostname*" -exec rm -i +
- remove
-ifromrmafter you were sure that command is working correctly.
answered Aug 9 at 19:38
RavexinaRavexina
36.9k15 gold badges101 silver badges131 bronze badges
Your command does not work as expected because of rm *PC-*-*.json! it would expands by shell and includes all PC-x-x.json files.
Actually you're using xargs in a wrong way.
Something like this should do the job:
ls -Q1 | grep -v $hostname | grep -E "PC-1-[0-9]+.json" | xargs echo
change echo with rm when you where sure that it works.
A better solution would be using find:
find -type f -name "PC-*-*.json" -not -name "*$hostname*" -exec rm -i +
- remove
-ifromrmafter you were sure that command is working correctly.
answered Aug 9 at 19:38
RavexinaRavexina
36.9k15 gold badges101 silver badges131 bronze badges
edited Aug 10 at 15:50
answered Aug 9 at 19:38
RavexinaRavexina
36.9k15 gold badges101 silver badges131 bronze badges
answered Aug 9 at 19:38
RavexinaRavexina
36.9k15 gold badges101 silver badges131 bronze badges
answered Aug 9 at 19:38
RavexinaRavexina
36.9k15 gold badges101 silver badges131 bronze badges
36.9k15 gold badges101 silver badges131 bronze badges
I ended up using the: ls -Q1 | grep -v $HOSTNAME | grep -E "[0-99]+.json" | xargs rm Variant, I cut off the PC-1 part of the second grep, as there should never be any json in my environment that is formatted like this expect the files I want to target. Also, like an idiot, I was using $hostname in place of $HOSTNAME, which, being relatively new to this I didn't know was not printing the hostname in my query. Thanks for the help!
– Andrew Williams
Aug 9 at 19:52
1
Nice! I think it makes a difference if you switch the filename tests and do-iname "PC-*-*.json" -not -iname "*$hostname*"instead as the second one has to be evaluated much more seldom this way. Also, OP wants-type f(as the first test). Oh and wait, why-iname? OP definitely wantsnamefor both tests.
– dessert
Aug 9 at 19:54
@dessert You're right... I'll update the answer.inameis somehow burned into my memory and I always use it...
– Ravexina
Aug 10 at 5:54
@AndrewWilliams You're welcome... aboutHOSTNAMEyou are correct! I thoughthostnameis a variable you defined youreslf ;)
– Ravexina
Aug 10 at 5:57
add a comment
|
I ended up using the: ls -Q1 | grep -v $HOSTNAME | grep -E "[0-99]+.json" | xargs rm Variant, I cut off the PC-1 part of the second grep, as there should never be any json in my environment that is formatted like this expect the files I want to target. Also, like an idiot, I was using $hostname in place of $HOSTNAME, which, being relatively new to this I didn't know was not printing the hostname in my query. Thanks for the help!
– Andrew Williams
Aug 9 at 19:52
1
Nice! I think it makes a difference if you switch the filename tests and do-iname "PC-*-*.json" -not -iname "*$hostname*"instead as the second one has to be evaluated much more seldom this way. Also, OP wants-type f(as the first test). Oh and wait, why-iname? OP definitely wantsnamefor both tests.
– dessert
Aug 9 at 19:54
@dessert You're right... I'll update the answer.inameis somehow burned into my memory and I always use it...
– Ravexina
Aug 10 at 5:54
@AndrewWilliams You're welcome... aboutHOSTNAMEyou are correct! I thoughthostnameis a variable you defined youreslf ;)
– Ravexina
Aug 10 at 5:57
I ended up using the: ls -Q1 | grep -v $HOSTNAME | grep -E "[0-99]+.json" | xargs rm Variant, I cut off the PC-1 part of the second grep, as there should never be any json in my environment that is formatted like this expect the files I want to target. Also, like an idiot, I was using $hostname in place of $HOSTNAME, which, being relatively new to this I didn't know was not printing the hostname in my query. Thanks for the help!
– Andrew Williams
Aug 9 at 19:52
I ended up using the: ls -Q1 | grep -v $HOSTNAME | grep -E "[0-99]+.json" | xargs rm Variant, I cut off the PC-1 part of the second grep, as there should never be any json in my environment that is formatted like this expect the files I want to target. Also, like an idiot, I was using $hostname in place of $HOSTNAME, which, being relatively new to this I didn't know was not printing the hostname in my query. Thanks for the help!
– Andrew Williams
Aug 9 at 19:52
1
1
Nice! I think it makes a difference if you switch the filename tests and do
-iname "PC-*-*.json" -not -iname "*$hostname*" instead as the second one has to be evaluated much more seldom this way. Also, OP wants -type f (as the first test). Oh and wait, why -iname? OP definitely wants name for both tests.– dessert
Aug 9 at 19:54
Nice! I think it makes a difference if you switch the filename tests and do
-iname "PC-*-*.json" -not -iname "*$hostname*" instead as the second one has to be evaluated much more seldom this way. Also, OP wants -type f (as the first test). Oh and wait, why -iname? OP definitely wants name for both tests.– dessert
Aug 9 at 19:54
@dessert You're right... I'll update the answer.
iname is somehow burned into my memory and I always use it...– Ravexina
Aug 10 at 5:54
@dessert You're right... I'll update the answer.
iname is somehow burned into my memory and I always use it...– Ravexina
Aug 10 at 5:54
@AndrewWilliams You're welcome... about
HOSTNAME you are correct! I thought hostname is a variable you defined youreslf ;)– Ravexina
Aug 10 at 5:57
@AndrewWilliams You're welcome... about
HOSTNAME you are correct! I thought hostname is a variable you defined youreslf ;)– Ravexina
Aug 10 at 5:57
add a comment
|
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