Cause of continuous spectral lines [closed]Photoelectric effect and electron lossWhy don't alkaline earth metals lose only one electron when they are ionized?Why are atom spherical in shape ?What do atoms look like?What is generally meant by distinct line spectrum?Determination of initial excited state via luminescenceWhat gives rise to the color of sapphires?
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Cause of continuous spectral lines [closed]
Photoelectric effect and electron lossWhy don't alkaline earth metals lose only one electron when they are ionized?Why are atom spherical in shape ?What do atoms look like?What is generally meant by distinct line spectrum?Determination of initial excited state via luminescenceWhat gives rise to the color of sapphires?
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We know different types of atoms have different spectral lines. But what exactly are the spectral lines representing? What causes white light to have a continuous spectra while other atoms show discontinuous spectral lines?
atoms light
asked Jun 2 at 6:35
NightKrugerNightKruger
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closed as too broad by Mithoron, Jon Custer, Poutnik, Buck Thorn, Karsten Theis Jun 7 at 12:41
Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
add a comment
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$begingroup$
We know different types of atoms have different spectral lines. But what exactly are the spectral lines representing? What causes white light to have a continuous spectra while other atoms show discontinuous spectral lines?
atoms light
asked Jun 2 at 6:35
NightKrugerNightKruger
625 bronze badges
$endgroup$
closed as too broad by Mithoron, Jon Custer, Poutnik, Buck Thorn, Karsten Theis Jun 7 at 12:41
Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
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As a corollary to your question and answers : white light is not necessarily a continuous spectrum, the brain only needs stimuli of the three different receptor cells in a pattern to "see white". So white light is rarely a continuous spectrum, but it is broad enough to stimulate all the receptors.
$endgroup$
– Stian Yttervik
Jun 2 at 17:26
add a comment
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$begingroup$
We know different types of atoms have different spectral lines. But what exactly are the spectral lines representing? What causes white light to have a continuous spectra while other atoms show discontinuous spectral lines?
atoms light
asked Jun 2 at 6:35
NightKrugerNightKruger
625 bronze badges
$endgroup$
We know different types of atoms have different spectral lines. But what exactly are the spectral lines representing? What causes white light to have a continuous spectra while other atoms show discontinuous spectral lines?
atoms light
atoms light
asked Jun 2 at 6:35
NightKrugerNightKruger
625 bronze badges
asked Jun 2 at 6:35
NightKrugerNightKruger
625 bronze badges
asked Jun 2 at 6:35
NightKrugerNightKruger
625 bronze badges
asked Jun 2 at 6:35
NightKrugerNightKruger
625 bronze badges
asked Jun 2 at 6:35
NightKrugerNightKruger
625 bronze badges
625 bronze badges
closed as too broad by Mithoron, Jon Custer, Poutnik, Buck Thorn, Karsten Theis Jun 7 at 12:41
Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
closed as too broad by Mithoron, Jon Custer, Poutnik, Buck Thorn, Karsten Theis Jun 7 at 12:41
Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
closed as too broad by Mithoron, Jon Custer, Poutnik, Buck Thorn, Karsten Theis Jun 7 at 12:41
Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.
$begingroup$
As a corollary to your question and answers : white light is not necessarily a continuous spectrum, the brain only needs stimuli of the three different receptor cells in a pattern to "see white". So white light is rarely a continuous spectrum, but it is broad enough to stimulate all the receptors.
$endgroup$
– Stian Yttervik
Jun 2 at 17:26
add a comment
|
$begingroup$
As a corollary to your question and answers : white light is not necessarily a continuous spectrum, the brain only needs stimuli of the three different receptor cells in a pattern to "see white". So white light is rarely a continuous spectrum, but it is broad enough to stimulate all the receptors.
$endgroup$
– Stian Yttervik
Jun 2 at 17:26
$begingroup$
As a corollary to your question and answers : white light is not necessarily a continuous spectrum, the brain only needs stimuli of the three different receptor cells in a pattern to "see white". So white light is rarely a continuous spectrum, but it is broad enough to stimulate all the receptors.
$endgroup$
– Stian Yttervik
Jun 2 at 17:26
$begingroup$
As a corollary to your question and answers : white light is not necessarily a continuous spectrum, the brain only needs stimuli of the three different receptor cells in a pattern to "see white". So white light is rarely a continuous spectrum, but it is broad enough to stimulate all the receptors.
$endgroup$
– Stian Yttervik
Jun 2 at 17:26
add a comment
|
2 Answers
2
active
oldest
votes
$begingroup$
The spectral lines represent transitions between pairs of discrete energy levels in the atom; an electron is excited by absorbing the energy of a photon and a transition from one of these levels to another occurs as the photon is destroyed. Emission lines occur when the reverse process happens.
If enough energy is absorbed the atom can be ionised and an electron with un-quantised energy can be liberated and moves to a position of complete separation where attractive forces between electron and nucleus is insignificant. As the liberated electron's energy is un-quantised the absorption giving rise to ionisation is continuous. The absorption is truly continuous, no matter how high a spectral resolution is used discrete absorption lines will not be observed.
Black body radiation is continuous emission from a hot body. The analysis of this emission lead Plank in 1901 to propose, for the first time, the idea that the photons were quantised, thus avoiding the 'ultra-violet catastrophe'. He did this by allowing ultra-violet photons to have more energy than visible ones which in turn had more energy that infra-red ones. Nowadays we know that he energy is directly proportional to frequency via the Planck constant, $E=hv$.
In the black body, all the numerous energy levels in the body are highly excited and transitions between them continuously occur as the body is being continuously heated. These transition energies overlap one another in energy so that the spectrum is continuous.
(In molecules there are also discrete energy levels, in the ground state these are due to the vibrational and rotational motion of the molecule. A molecule may also have electronically excited states and these can also have discrete vibrational and rotational energy levels. Furthermore there are dissociative excited states that have continuous absorption spectra.)
answered Jun 2 at 8:28
porphyrinporphyrin
20k1 gold badge35 silver badges60 bronze badges
$endgroup$
$begingroup$
just as a side comment (it might be of interest for the OP), the continuum observed in electrons' energy when ionization occurs is the photoelectric effect; all energy excess increases electron's speed.
$endgroup$
– santimirandarp
Jun 2 at 13:47
1
$begingroup$
yes; a good point
$endgroup$
– porphyrin
Jun 6 at 13:21
add a comment
|
$begingroup$
Natural white light had continuous spectrum, as the source - black radiator - has continuous emission in all wavelengths.
Atoms emit or absorb only at the wavelengths, that are corresponding to energy differences between discreet energy levels of electrons in atoms.
answered Jun 2 at 6:52
PoutnikPoutnik
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add a comment
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
The spectral lines represent transitions between pairs of discrete energy levels in the atom; an electron is excited by absorbing the energy of a photon and a transition from one of these levels to another occurs as the photon is destroyed. Emission lines occur when the reverse process happens.
If enough energy is absorbed the atom can be ionised and an electron with un-quantised energy can be liberated and moves to a position of complete separation where attractive forces between electron and nucleus is insignificant. As the liberated electron's energy is un-quantised the absorption giving rise to ionisation is continuous. The absorption is truly continuous, no matter how high a spectral resolution is used discrete absorption lines will not be observed.
Black body radiation is continuous emission from a hot body. The analysis of this emission lead Plank in 1901 to propose, for the first time, the idea that the photons were quantised, thus avoiding the 'ultra-violet catastrophe'. He did this by allowing ultra-violet photons to have more energy than visible ones which in turn had more energy that infra-red ones. Nowadays we know that he energy is directly proportional to frequency via the Planck constant, $E=hv$.
In the black body, all the numerous energy levels in the body are highly excited and transitions between them continuously occur as the body is being continuously heated. These transition energies overlap one another in energy so that the spectrum is continuous.
(In molecules there are also discrete energy levels, in the ground state these are due to the vibrational and rotational motion of the molecule. A molecule may also have electronically excited states and these can also have discrete vibrational and rotational energy levels. Furthermore there are dissociative excited states that have continuous absorption spectra.)
answered Jun 2 at 8:28
porphyrinporphyrin
20k1 gold badge35 silver badges60 bronze badges
$endgroup$
$begingroup$
just as a side comment (it might be of interest for the OP), the continuum observed in electrons' energy when ionization occurs is the photoelectric effect; all energy excess increases electron's speed.
$endgroup$
– santimirandarp
Jun 2 at 13:47
1
$begingroup$
yes; a good point
$endgroup$
– porphyrin
Jun 6 at 13:21
add a comment
|
$begingroup$
The spectral lines represent transitions between pairs of discrete energy levels in the atom; an electron is excited by absorbing the energy of a photon and a transition from one of these levels to another occurs as the photon is destroyed. Emission lines occur when the reverse process happens.
If enough energy is absorbed the atom can be ionised and an electron with un-quantised energy can be liberated and moves to a position of complete separation where attractive forces between electron and nucleus is insignificant. As the liberated electron's energy is un-quantised the absorption giving rise to ionisation is continuous. The absorption is truly continuous, no matter how high a spectral resolution is used discrete absorption lines will not be observed.
Black body radiation is continuous emission from a hot body. The analysis of this emission lead Plank in 1901 to propose, for the first time, the idea that the photons were quantised, thus avoiding the 'ultra-violet catastrophe'. He did this by allowing ultra-violet photons to have more energy than visible ones which in turn had more energy that infra-red ones. Nowadays we know that he energy is directly proportional to frequency via the Planck constant, $E=hv$.
In the black body, all the numerous energy levels in the body are highly excited and transitions between them continuously occur as the body is being continuously heated. These transition energies overlap one another in energy so that the spectrum is continuous.
(In molecules there are also discrete energy levels, in the ground state these are due to the vibrational and rotational motion of the molecule. A molecule may also have electronically excited states and these can also have discrete vibrational and rotational energy levels. Furthermore there are dissociative excited states that have continuous absorption spectra.)
answered Jun 2 at 8:28
porphyrinporphyrin
20k1 gold badge35 silver badges60 bronze badges
$endgroup$
$begingroup$
just as a side comment (it might be of interest for the OP), the continuum observed in electrons' energy when ionization occurs is the photoelectric effect; all energy excess increases electron's speed.
$endgroup$
– santimirandarp
Jun 2 at 13:47
1
$begingroup$
yes; a good point
$endgroup$
– porphyrin
Jun 6 at 13:21
add a comment
|
$begingroup$
The spectral lines represent transitions between pairs of discrete energy levels in the atom; an electron is excited by absorbing the energy of a photon and a transition from one of these levels to another occurs as the photon is destroyed. Emission lines occur when the reverse process happens.
If enough energy is absorbed the atom can be ionised and an electron with un-quantised energy can be liberated and moves to a position of complete separation where attractive forces between electron and nucleus is insignificant. As the liberated electron's energy is un-quantised the absorption giving rise to ionisation is continuous. The absorption is truly continuous, no matter how high a spectral resolution is used discrete absorption lines will not be observed.
Black body radiation is continuous emission from a hot body. The analysis of this emission lead Plank in 1901 to propose, for the first time, the idea that the photons were quantised, thus avoiding the 'ultra-violet catastrophe'. He did this by allowing ultra-violet photons to have more energy than visible ones which in turn had more energy that infra-red ones. Nowadays we know that he energy is directly proportional to frequency via the Planck constant, $E=hv$.
In the black body, all the numerous energy levels in the body are highly excited and transitions between them continuously occur as the body is being continuously heated. These transition energies overlap one another in energy so that the spectrum is continuous.
(In molecules there are also discrete energy levels, in the ground state these are due to the vibrational and rotational motion of the molecule. A molecule may also have electronically excited states and these can also have discrete vibrational and rotational energy levels. Furthermore there are dissociative excited states that have continuous absorption spectra.)
answered Jun 2 at 8:28
porphyrinporphyrin
20k1 gold badge35 silver badges60 bronze badges
$endgroup$
The spectral lines represent transitions between pairs of discrete energy levels in the atom; an electron is excited by absorbing the energy of a photon and a transition from one of these levels to another occurs as the photon is destroyed. Emission lines occur when the reverse process happens.
If enough energy is absorbed the atom can be ionised and an electron with un-quantised energy can be liberated and moves to a position of complete separation where attractive forces between electron and nucleus is insignificant. As the liberated electron's energy is un-quantised the absorption giving rise to ionisation is continuous. The absorption is truly continuous, no matter how high a spectral resolution is used discrete absorption lines will not be observed.
Black body radiation is continuous emission from a hot body. The analysis of this emission lead Plank in 1901 to propose, for the first time, the idea that the photons were quantised, thus avoiding the 'ultra-violet catastrophe'. He did this by allowing ultra-violet photons to have more energy than visible ones which in turn had more energy that infra-red ones. Nowadays we know that he energy is directly proportional to frequency via the Planck constant, $E=hv$.
In the black body, all the numerous energy levels in the body are highly excited and transitions between them continuously occur as the body is being continuously heated. These transition energies overlap one another in energy so that the spectrum is continuous.
(In molecules there are also discrete energy levels, in the ground state these are due to the vibrational and rotational motion of the molecule. A molecule may also have electronically excited states and these can also have discrete vibrational and rotational energy levels. Furthermore there are dissociative excited states that have continuous absorption spectra.)
answered Jun 2 at 8:28
porphyrinporphyrin
20k1 gold badge35 silver badges60 bronze badges
edited Jun 2 at 11:54
answered Jun 2 at 8:28
porphyrinporphyrin
20k1 gold badge35 silver badges60 bronze badges
answered Jun 2 at 8:28
porphyrinporphyrin
20k1 gold badge35 silver badges60 bronze badges
answered Jun 2 at 8:28
porphyrinporphyrin
20k1 gold badge35 silver badges60 bronze badges
20k1 gold badge35 silver badges60 bronze badges
$begingroup$
just as a side comment (it might be of interest for the OP), the continuum observed in electrons' energy when ionization occurs is the photoelectric effect; all energy excess increases electron's speed.
$endgroup$
– santimirandarp
Jun 2 at 13:47
1
$begingroup$
yes; a good point
$endgroup$
– porphyrin
Jun 6 at 13:21
add a comment
|
$begingroup$
just as a side comment (it might be of interest for the OP), the continuum observed in electrons' energy when ionization occurs is the photoelectric effect; all energy excess increases electron's speed.
$endgroup$
– santimirandarp
Jun 2 at 13:47
1
$begingroup$
yes; a good point
$endgroup$
– porphyrin
Jun 6 at 13:21
$begingroup$
just as a side comment (it might be of interest for the OP), the continuum observed in electrons' energy when ionization occurs is the photoelectric effect; all energy excess increases electron's speed.
$endgroup$
– santimirandarp
Jun 2 at 13:47
$begingroup$
just as a side comment (it might be of interest for the OP), the continuum observed in electrons' energy when ionization occurs is the photoelectric effect; all energy excess increases electron's speed.
$endgroup$
– santimirandarp
Jun 2 at 13:47
1
1
$begingroup$
yes; a good point
$endgroup$
– porphyrin
Jun 6 at 13:21
$begingroup$
yes; a good point
$endgroup$
– porphyrin
Jun 6 at 13:21
add a comment
|
$begingroup$
Natural white light had continuous spectrum, as the source - black radiator - has continuous emission in all wavelengths.
Atoms emit or absorb only at the wavelengths, that are corresponding to energy differences between discreet energy levels of electrons in atoms.
answered Jun 2 at 6:52
PoutnikPoutnik
5,8211 gold badge7 silver badges26 bronze badges
$endgroup$
add a comment
|
$begingroup$
Natural white light had continuous spectrum, as the source - black radiator - has continuous emission in all wavelengths.
Atoms emit or absorb only at the wavelengths, that are corresponding to energy differences between discreet energy levels of electrons in atoms.
answered Jun 2 at 6:52
PoutnikPoutnik
5,8211 gold badge7 silver badges26 bronze badges
$endgroup$
add a comment
|
$begingroup$
Natural white light had continuous spectrum, as the source - black radiator - has continuous emission in all wavelengths.
Atoms emit or absorb only at the wavelengths, that are corresponding to energy differences between discreet energy levels of electrons in atoms.
answered Jun 2 at 6:52
PoutnikPoutnik
5,8211 gold badge7 silver badges26 bronze badges
$endgroup$
Natural white light had continuous spectrum, as the source - black radiator - has continuous emission in all wavelengths.
Atoms emit or absorb only at the wavelengths, that are corresponding to energy differences between discreet energy levels of electrons in atoms.
answered Jun 2 at 6:52
PoutnikPoutnik
5,8211 gold badge7 silver badges26 bronze badges
answered Jun 2 at 6:52
PoutnikPoutnik
5,8211 gold badge7 silver badges26 bronze badges
answered Jun 2 at 6:52
PoutnikPoutnik
5,8211 gold badge7 silver badges26 bronze badges
answered Jun 2 at 6:52
PoutnikPoutnik
5,8211 gold badge7 silver badges26 bronze badges
5,8211 gold badge7 silver badges26 bronze badges
add a comment
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add a comment
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$begingroup$
As a corollary to your question and answers : white light is not necessarily a continuous spectrum, the brain only needs stimuli of the three different receptor cells in a pattern to "see white". So white light is rarely a continuous spectrum, but it is broad enough to stimulate all the receptors.
$endgroup$
– Stian Yttervik
Jun 2 at 17:26