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0

I have shell script prompting an answer y/n. at the prompt before giving input, I used control-c signal which calls Signal Handling function. In Signal Handling function there is a prompt "q" to exit or "y" and "y" should be used with the FIRST read prompt.

I tried to (( echo "y" | read )) but didn't work

This is part of my script:

IntHandle ()
 
 echo -e "nUse 'q' to quit "
 read var1 
 if [[ $var1 == q ]]
 then
 exit 1
 else
 echo "y" 


 trap 'IntHandle' SIGINT
 read -p "no valid user id entered, new user ids? [yn]: " ans ----> here 
 used control-c signal before give y/n to ans
if [[ $ans == "y" ]]
then 
 read -p " username :" name
fi
 .
 .
 .
 .

.

output should be like below:

no valid user id entered, new user ids? [yn]: #control-c entered

' Use 'q' to quit ' y ------> here "y" entered rather "q" in Siganl Handeling
function then it is saved in "ans" variable
which gets the condition true to prompt a username.

usernames: Larry -----> the name which is entered after true condition. . . .

command-line bash

share|improve this question

edited Jun 8 at 16:44

vidarlo

13.5k66 gold badges3333 silver badges5959 bronze badges

asked Jun 8 at 16:25

RedHatRedHat

1

add a comment
 | 

0

I have shell script prompting an answer y/n. at the prompt before giving input, I used control-c signal which calls Signal Handling function. In Signal Handling function there is a prompt "q" to exit or "y" and "y" should be used with the FIRST read prompt.

I tried to (( echo "y" | read )) but didn't work

This is part of my script:

IntHandle ()
 
 echo -e "nUse 'q' to quit "
 read var1 
 if [[ $var1 == q ]]
 then
 exit 1
 else
 echo "y" 


 trap 'IntHandle' SIGINT
 read -p "no valid user id entered, new user ids? [yn]: " ans ----> here 
 used control-c signal before give y/n to ans
if [[ $ans == "y" ]]
then 
 read -p " username :" name
fi
 .
 .
 .
 .

.

output should be like below:

no valid user id entered, new user ids? [yn]: #control-c entered

' Use 'q' to quit ' y ------> here "y" entered rather "q" in Siganl Handeling
function then it is saved in "ans" variable
which gets the condition true to prompt a username.

usernames: Larry -----> the name which is entered after true condition. . . .

command-line bash

share|improve this question

edited Jun 8 at 16:44

vidarlo

13.5k66 gold badges3333 silver badges5959 bronze badges

asked Jun 8 at 16:25

RedHatRedHat

1

add a comment
 | 

I have shell script prompting an answer y/n. at the prompt before giving input, I used control-c signal which calls Signal Handling function. In Signal Handling function there is a prompt "q" to exit or "y" and "y" should be used with the FIRST read prompt.

I tried to (( echo "y" | read )) but didn't work

This is part of my script:

IntHandle ()
 
 echo -e "nUse 'q' to quit "
 read var1 
 if [[ $var1 == q ]]
 then
 exit 1
 else
 echo "y" 


 trap 'IntHandle' SIGINT
 read -p "no valid user id entered, new user ids? [yn]: " ans ----> here 
 used control-c signal before give y/n to ans
if [[ $ans == "y" ]]
then 
 read -p " username :" name
fi
 .
 .
 .
 .

.

output should be like below:

no valid user id entered, new user ids? [yn]: #control-c entered

' Use 'q' to quit ' y ------> here "y" entered rather "q" in Siganl Handeling
function then it is saved in "ans" variable
which gets the condition true to prompt a username.

usernames: Larry -----> the name which is entered after true condition. . . .

command-line bash

share|improve this question

edited Jun 8 at 16:44

vidarlo

13.5k66 gold badges3333 silver badges5959 bronze badges

asked Jun 8 at 16:25

RedHatRedHat

1

IntHandle ()
 
 echo -e "nUse 'q' to quit "
 read var1 
 if [[ $var1 == q ]]
 then
 exit 1
 else
 echo "y" 


 trap 'IntHandle' SIGINT
 read -p "no valid user id entered, new user ids? [yn]: " ans ----> here 
 used control-c signal before give y/n to ans
if [[ $ans == "y" ]]
then 
 read -p " username :" name
fi
 .
 .
 .
 .

share|improve this question

edited Jun 8 at 16:44

vidarlo

13.5k66 gold badges3333 silver badges5959 bronze badges

asked Jun 8 at 16:25

RedHatRedHat

1

share|improve this question

edited Jun 8 at 16:44

vidarlo

13.5k66 gold badges3333 silver badges5959 bronze badges

asked Jun 8 at 16:25

RedHatRedHat

1

edited Jun 8 at 16:44

vidarlo

13.5k66 gold badges3333 silver badges5959 bronze badges

edited Jun 8 at 16:44

vidarlo

13.5k66 gold badges3333 silver badges5959 bronze badges

asked Jun 8 at 16:25

RedHatRedHat

1

asked Jun 8 at 16:25

RedHatRedHat

1

1 Answer
1

active

oldest

votes

2

This is a X-Y problem. Why on earth use read for setting a variable in a script?

Set it the normal way; ans=y

This would make the function look like this:

IntHandle ()
 
 echo -e "nUse 'q' to quit "
 read var1 
 if [[ $var1 == q ]]
 then
 exit 1
 else
 ans=y
 fi

share|improve this answer

answered Jun 8 at 16:43

vidarlovidarlo

13.5k66 gold badges3333 silver badges5959 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  First, I did before "ans=y" but did not work because I am still being prompted to enter "y" or "n" in the first prompt which it should not. Just when I enter "y" rather than "q" in the function prompt, it would set "ans" variable by "y" and skip me the prompt.
  
  – RedHat
  Jun 9 at 0:58
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I need to skip the stdin in the first prompt when I use control-c signal before giving "y" or "n" to ans variable.
  
  – RedHat
  Jun 9 at 1:00
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  No, you need to modify the flow of the program to skip that prompt if the value is set. Whenever ^C is pressed, your code will jump to IntHandle(). How can that be used to skip the prompt? I'm trying to nudge you along here, because, as I said, you have put your eyes on a solution, which is wrong.
  
  – vidarlo
  Jun 9 at 7:25
  
  

  
  
  
  

add a comment
 | 

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2

This is a X-Y problem. Why on earth use read for setting a variable in a script?

Set it the normal way; ans=y

This would make the function look like this:

IntHandle ()
 
 echo -e "nUse 'q' to quit "
 read var1 
 if [[ $var1 == q ]]
 then
 exit 1
 else
 ans=y
 fi

share|improve this answer

answered Jun 8 at 16:43

vidarlovidarlo

13.5k66 gold badges3333 silver badges5959 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  First, I did before "ans=y" but did not work because I am still being prompted to enter "y" or "n" in the first prompt which it should not. Just when I enter "y" rather than "q" in the function prompt, it would set "ans" variable by "y" and skip me the prompt.
  
  – RedHat
  Jun 9 at 0:58
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I need to skip the stdin in the first prompt when I use control-c signal before giving "y" or "n" to ans variable.
  
  – RedHat
  Jun 9 at 1:00
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  No, you need to modify the flow of the program to skip that prompt if the value is set. Whenever ^C is pressed, your code will jump to IntHandle(). How can that be used to skip the prompt? I'm trying to nudge you along here, because, as I said, you have put your eyes on a solution, which is wrong.
  
  – vidarlo
  Jun 9 at 7:25
  
  

  
  
  
  

add a comment
 | 

2

This is a X-Y problem. Why on earth use read for setting a variable in a script?

Set it the normal way; ans=y

This would make the function look like this:

IntHandle ()
 
 echo -e "nUse 'q' to quit "
 read var1 
 if [[ $var1 == q ]]
 then
 exit 1
 else
 ans=y
 fi

share|improve this answer

answered Jun 8 at 16:43

vidarlovidarlo

13.5k66 gold badges3333 silver badges5959 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  First, I did before "ans=y" but did not work because I am still being prompted to enter "y" or "n" in the first prompt which it should not. Just when I enter "y" rather than "q" in the function prompt, it would set "ans" variable by "y" and skip me the prompt.
  
  – RedHat
  Jun 9 at 0:58
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I need to skip the stdin in the first prompt when I use control-c signal before giving "y" or "n" to ans variable.
  
  – RedHat
  Jun 9 at 1:00
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  No, you need to modify the flow of the program to skip that prompt if the value is set. Whenever ^C is pressed, your code will jump to IntHandle(). How can that be used to skip the prompt? I'm trying to nudge you along here, because, as I said, you have put your eyes on a solution, which is wrong.
  
  – vidarlo
  Jun 9 at 7:25
  
  

  
  
  
  

add a comment
 | 

This is a X-Y problem. Why on earth use read for setting a variable in a script?

Set it the normal way; ans=y

This would make the function look like this:

IntHandle ()
 
 echo -e "nUse 'q' to quit "
 read var1 
 if [[ $var1 == q ]]
 then
 exit 1
 else
 ans=y
 fi

share|improve this answer

answered Jun 8 at 16:43

vidarlovidarlo

13.5k66 gold badges3333 silver badges5959 bronze badges

IntHandle ()
 
 echo -e "nUse 'q' to quit "
 read var1 
 if [[ $var1 == q ]]
 then
 exit 1
 else
 ans=y
 fi

share|improve this answer

answered Jun 8 at 16:43

vidarlovidarlo

13.5k66 gold badges3333 silver badges5959 bronze badges

answered Jun 8 at 16:43

vidarlovidarlo

13.5k66 gold badges3333 silver badges5959 bronze badges

answered Jun 8 at 16:43

vidarlovidarlo

13.5k66 gold badges3333 silver badges5959 bronze badges