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LT Spice Voltage Output

How to sketch the Bode diagram of the output filter of a Buck converter?What are the freeware SPICE simulators available?Voltage regulators in SPICE softwareNG-Spice / Macspice - plot source current?LT Spice incorrect output voltage for boost converterUnderstanding Mosfet simulation and initial conditions in SpiceComprehensive SPICE guideDetrmining open loop gain of an amplifier in LT-spice using a transient simulationPlot voltage for different resistor values in LTSpiceCan a spice library contain different component types?

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margin-bottom:0;

5

$begingroup$

I am using LT Spice for simulation of my circuit. I have used a probe to check for the voltage on the Capacitor.

What is the green dotted line that can be seen in the plot? Thank you.

simulation ltspice spice pspice

share|improve this question

edited Apr 29 at 10:23

Niteesh Shanbog

71544 silver badges1818 bronze badges

asked Apr 29 at 9:26

hcsitashcsitas

2844 bronze badges

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Also see: sketching a Bode plot. Formulas and a small amount of description are there.
  $endgroup$
  – jonk
  Apr 29 at 17:00
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Very clear! Thank you.
  $endgroup$
  – hcsitas
  Apr 30 at 10:37
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Glad it helped.
  $endgroup$
  – jonk
  Apr 30 at 16:50
  

  
  
  
  

add a comment
 | 

5

$begingroup$

I am using LT Spice for simulation of my circuit. I have used a probe to check for the voltage on the Capacitor.

What is the green dotted line that can be seen in the plot? Thank you.

simulation ltspice spice pspice

share|improve this question

edited Apr 29 at 10:23

Niteesh Shanbog

71544 silver badges1818 bronze badges

asked Apr 29 at 9:26

hcsitashcsitas

2844 bronze badges

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Also see: sketching a Bode plot. Formulas and a small amount of description are there.
  $endgroup$
  – jonk
  Apr 29 at 17:00
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Very clear! Thank you.
  $endgroup$
  – hcsitas
  Apr 30 at 10:37
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Glad it helped.
  $endgroup$
  – jonk
  Apr 30 at 16:50
  

  
  
  
  

add a comment
 | 

$begingroup$

I am using LT Spice for simulation of my circuit. I have used a probe to check for the voltage on the Capacitor.

What is the green dotted line that can be seen in the plot? Thank you.

simulation ltspice spice pspice

share|improve this question

edited Apr 29 at 10:23

Niteesh Shanbog

71544 silver badges1818 bronze badges

asked Apr 29 at 9:26

hcsitashcsitas

2844 bronze badges

$endgroup$

share|improve this question

edited Apr 29 at 10:23

Niteesh Shanbog

71544 silver badges1818 bronze badges

asked Apr 29 at 9:26

hcsitashcsitas

2844 bronze badges

share|improve this question

edited Apr 29 at 10:23

Niteesh Shanbog

71544 silver badges1818 bronze badges

asked Apr 29 at 9:26

hcsitashcsitas

2844 bronze badges

edited Apr 29 at 10:23

Niteesh Shanbog

71544 silver badges1818 bronze badges

edited Apr 29 at 10:23

Niteesh Shanbog

71544 silver badges1818 bronze badges

asked Apr 29 at 9:26

hcsitashcsitas

2844 bronze badges

asked Apr 29 at 9:26

hcsitashcsitas

2844 bronze badges

3 Answers
3

active

oldest

votes

2

$begingroup$

The green dotted line represents the difference in phase between the voltage accross the capacitor (Vc) and input voltage (V1). The values (in degrees) on the right show you how much phase shifting there is. For example, at the lower frequencies, there is no phase difference (0 degrees), and after about 1MHz, there is a -200 degree shift.

This image should give you a general idea of what a phase shift is.

share|improve this answer

answered Apr 29 at 16:48

Liam F-ALiam F-A

9899 bronze badges

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Very clear! Thank you.
  $endgroup$
  – hcsitas
  Apr 30 at 10:32
  

  
  
  
  

add a comment
 | 

16

$begingroup$

Since you are doing AC analysis, you are plotting the gain and phase. So the dotted line is showing the phase response of your circuit.

share|improve this answer

edited Apr 29 at 21:02

CanSevgi

4566 bronze badges

answered Apr 29 at 9:32

NavaroNavaro

40233 silver badges1010 bronze badges

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Very clear! Thank you.
  $endgroup$
  – hcsitas
  Apr 30 at 10:32
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Answer marked for poster with fewest points...
  $endgroup$
  – hcsitas
  Apr 30 at 10:39
  

  
  
  
  

add a comment
 | 

6

$begingroup$

You are doing an AC analysis, the voltage across the capacitor is:

$$V_1 cdotdfracdfrac1j cdot omega cdot CR+j cdot omega cdot L+dfrac1j cdot omega cdot C = dfracV_11- omega^2 cdot L cdot C + j omega cdot C cdot R$$

Since this is a complex number it has both a magnitude and a phase angle.

LTspice is plotting the amplitude (in dB) as a solid line against the left hand vertical scale.

$$ dB = 20 cdot log_10 left( dfracV1 text volt right)$$

and the phase angle in degrees as a dotted line against the right hand vertical scale.

share|improve this answer

edited Apr 29 at 11:19

answered Apr 29 at 10:46

Warren HillWarren Hill

3,8751212 silver badges2727 bronze badges

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Answer marked for poster with fewest points...
  $endgroup$
  – hcsitas
  Apr 30 at 10:40
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @hcsitas Thanks for the kind comment. I probably should have written still clearer and I apologize for missing that mark for you.
  $endgroup$
  – jonk
  Apr 30 at 16:50
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Nope, it was crystal clear. I’m new to Spice but not the other stuff so your explanation hit home right away. Thanks again.
  $endgroup$
  – hcsitas
  May 1 at 17:16
  

  
  
  
  

add a comment
 | 

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2

$begingroup$

The green dotted line represents the difference in phase between the voltage accross the capacitor (Vc) and input voltage (V1). The values (in degrees) on the right show you how much phase shifting there is. For example, at the lower frequencies, there is no phase difference (0 degrees), and after about 1MHz, there is a -200 degree shift.

This image should give you a general idea of what a phase shift is.

share|improve this answer

answered Apr 29 at 16:48

Liam F-ALiam F-A

9899 bronze badges

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Very clear! Thank you.
  $endgroup$
  – hcsitas
  Apr 30 at 10:32
  

  
  
  
  

add a comment
 | 

2

$begingroup$

The green dotted line represents the difference in phase between the voltage accross the capacitor (Vc) and input voltage (V1). The values (in degrees) on the right show you how much phase shifting there is. For example, at the lower frequencies, there is no phase difference (0 degrees), and after about 1MHz, there is a -200 degree shift.

This image should give you a general idea of what a phase shift is.

share|improve this answer

answered Apr 29 at 16:48

Liam F-ALiam F-A

9899 bronze badges

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Very clear! Thank you.
  $endgroup$
  – hcsitas
  Apr 30 at 10:32
  

  
  
  
  

add a comment
 | 

$begingroup$

The green dotted line represents the difference in phase between the voltage accross the capacitor (Vc) and input voltage (V1). The values (in degrees) on the right show you how much phase shifting there is. For example, at the lower frequencies, there is no phase difference (0 degrees), and after about 1MHz, there is a -200 degree shift.

This image should give you a general idea of what a phase shift is.

share|improve this answer

answered Apr 29 at 16:48

Liam F-ALiam F-A

9899 bronze badges

$endgroup$

share|improve this answer

answered Apr 29 at 16:48

Liam F-ALiam F-A

9899 bronze badges

answered Apr 29 at 16:48

Liam F-ALiam F-A

9899 bronze badges

answered Apr 29 at 16:48

Liam F-ALiam F-A

9899 bronze badges

16

$begingroup$

Since you are doing AC analysis, you are plotting the gain and phase. So the dotted line is showing the phase response of your circuit.

share|improve this answer

edited Apr 29 at 21:02

CanSevgi

4566 bronze badges

answered Apr 29 at 9:32

NavaroNavaro

40233 silver badges1010 bronze badges

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Very clear! Thank you.
  $endgroup$
  – hcsitas
  Apr 30 at 10:32
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Answer marked for poster with fewest points...
  $endgroup$
  – hcsitas
  Apr 30 at 10:39
  

  
  
  
  

add a comment
 | 

16

$begingroup$

Since you are doing AC analysis, you are plotting the gain and phase. So the dotted line is showing the phase response of your circuit.

share|improve this answer

edited Apr 29 at 21:02

CanSevgi

4566 bronze badges

answered Apr 29 at 9:32

NavaroNavaro

40233 silver badges1010 bronze badges

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Very clear! Thank you.
  $endgroup$
  – hcsitas
  Apr 30 at 10:32
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Answer marked for poster with fewest points...
  $endgroup$
  – hcsitas
  Apr 30 at 10:39
  

  
  
  
  

add a comment
 | 

$begingroup$

Since you are doing AC analysis, you are plotting the gain and phase. So the dotted line is showing the phase response of your circuit.

share|improve this answer

edited Apr 29 at 21:02

CanSevgi

4566 bronze badges

answered Apr 29 at 9:32

NavaroNavaro

40233 silver badges1010 bronze badges

$endgroup$

share|improve this answer

edited Apr 29 at 21:02

CanSevgi

4566 bronze badges

answered Apr 29 at 9:32

NavaroNavaro

40233 silver badges1010 bronze badges

edited Apr 29 at 21:02

CanSevgi

4566 bronze badges

edited Apr 29 at 21:02

CanSevgi

4566 bronze badges

answered Apr 29 at 9:32

NavaroNavaro

40233 silver badges1010 bronze badges

answered Apr 29 at 9:32

NavaroNavaro

40233 silver badges1010 bronze badges

6

$begingroup$

You are doing an AC analysis, the voltage across the capacitor is:

$$V_1 cdotdfracdfrac1j cdot omega cdot CR+j cdot omega cdot L+dfrac1j cdot omega cdot C = dfracV_11- omega^2 cdot L cdot C + j omega cdot C cdot R$$

Since this is a complex number it has both a magnitude and a phase angle.

LTspice is plotting the amplitude (in dB) as a solid line against the left hand vertical scale.

$$ dB = 20 cdot log_10 left( dfracV1 text volt right)$$

and the phase angle in degrees as a dotted line against the right hand vertical scale.

share|improve this answer

edited Apr 29 at 11:19

answered Apr 29 at 10:46

Warren HillWarren Hill

3,8751212 silver badges2727 bronze badges

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Answer marked for poster with fewest points...
  $endgroup$
  – hcsitas
  Apr 30 at 10:40
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @hcsitas Thanks for the kind comment. I probably should have written still clearer and I apologize for missing that mark for you.
  $endgroup$
  – jonk
  Apr 30 at 16:50
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Nope, it was crystal clear. I’m new to Spice but not the other stuff so your explanation hit home right away. Thanks again.
  $endgroup$
  – hcsitas
  May 1 at 17:16
  

  
  
  
  

add a comment
 | 

6

$begingroup$

You are doing an AC analysis, the voltage across the capacitor is:

$$V_1 cdotdfracdfrac1j cdot omega cdot CR+j cdot omega cdot L+dfrac1j cdot omega cdot C = dfracV_11- omega^2 cdot L cdot C + j omega cdot C cdot R$$

Since this is a complex number it has both a magnitude and a phase angle.

LTspice is plotting the amplitude (in dB) as a solid line against the left hand vertical scale.

$$ dB = 20 cdot log_10 left( dfracV1 text volt right)$$

and the phase angle in degrees as a dotted line against the right hand vertical scale.

share|improve this answer

edited Apr 29 at 11:19

answered Apr 29 at 10:46

Warren HillWarren Hill

3,8751212 silver badges2727 bronze badges

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Answer marked for poster with fewest points...
  $endgroup$
  – hcsitas
  Apr 30 at 10:40
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @hcsitas Thanks for the kind comment. I probably should have written still clearer and I apologize for missing that mark for you.
  $endgroup$
  – jonk
  Apr 30 at 16:50
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  Nope, it was crystal clear. I’m new to Spice but not the other stuff so your explanation hit home right away. Thanks again.
  $endgroup$
  – hcsitas
  May 1 at 17:16
  

  
  
  
  

add a comment
 | 

$begingroup$

You are doing an AC analysis, the voltage across the capacitor is:

$$V_1 cdotdfracdfrac1j cdot omega cdot CR+j cdot omega cdot L+dfrac1j cdot omega cdot C = dfracV_11- omega^2 cdot L cdot C + j omega cdot C cdot R$$

Since this is a complex number it has both a magnitude and a phase angle.

LTspice is plotting the amplitude (in dB) as a solid line against the left hand vertical scale.

$$ dB = 20 cdot log_10 left( dfracV1 text volt right)$$

and the phase angle in degrees as a dotted line against the right hand vertical scale.

share|improve this answer

edited Apr 29 at 11:19

answered Apr 29 at 10:46

Warren HillWarren Hill

3,8751212 silver badges2727 bronze badges

$endgroup$

share|improve this answer

edited Apr 29 at 11:19

answered Apr 29 at 10:46

Warren HillWarren Hill

3,8751212 silver badges2727 bronze badges

answered Apr 29 at 10:46

Warren HillWarren Hill

3,8751212 silver badges2727 bronze badges

answered Apr 29 at 10:46

Warren HillWarren Hill

3,8751212 silver badges2727 bronze badges