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why this command using pipe doesn't work?
why my bash script only outputs one line on echoing awk variableA pipe command doesn't workWhy doesn't the command “ls | file” work?Move and rename files that have no name extensionexample of console output that is not written to standard outputawk - comparing 2 columns of 2 files and print common linesHow to search the file content in a directory for a certain pattern then return (redirect) the filename to another file?If I’m trying to run the same script in ten different directories in a row, will this way work and is there a more concise command sequence?Unable to update variable in bash script
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty
margin-bottom:0;
Why does find . | cat
works (printing all the files names) but find . | file -i
doesn't work for showing all files mime type?
shouldn't it work since there is an output from find .
and an input from file -i
?
(Sorry if this is a stupid question, I'm a beginner using bash and I couldn't find another question that could explain this to me)
command-line bash
add a comment
|
Why does find . | cat
works (printing all the files names) but find . | file -i
doesn't work for showing all files mime type?
shouldn't it work since there is an output from find .
and an input from file -i
?
(Sorry if this is a stupid question, I'm a beginner using bash and I couldn't find another question that could explain this to me)
command-line bash
add a comment
|
Why does find . | cat
works (printing all the files names) but find . | file -i
doesn't work for showing all files mime type?
shouldn't it work since there is an output from find .
and an input from file -i
?
(Sorry if this is a stupid question, I'm a beginner using bash and I couldn't find another question that could explain this to me)
command-line bash
Why does find . | cat
works (printing all the files names) but find . | file -i
doesn't work for showing all files mime type?
shouldn't it work since there is an output from find .
and an input from file -i
?
(Sorry if this is a stupid question, I'm a beginner using bash and I couldn't find another question that could explain this to me)
command-line bash
command-line bash
asked May 29 at 14:45
Leonardo Meinerz RamosLeonardo Meinerz Ramos
31 bronze badge
31 bronze badge
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1 Answer
1
active
oldest
votes
With a pipe, the command on the right-hand side reads the data on its stdin channel. The file
command requires the files to be command line arguments, not data on stdin.
This is exactly what the xargs
command is for: read from stdin, and provide the data as command line arguments:
find . | xargs file -i
Or, use the -f
option for file
:
find . | file -i -f -
Read the man pages for more details.
add a comment
|
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
With a pipe, the command on the right-hand side reads the data on its stdin channel. The file
command requires the files to be command line arguments, not data on stdin.
This is exactly what the xargs
command is for: read from stdin, and provide the data as command line arguments:
find . | xargs file -i
Or, use the -f
option for file
:
find . | file -i -f -
Read the man pages for more details.
add a comment
|
With a pipe, the command on the right-hand side reads the data on its stdin channel. The file
command requires the files to be command line arguments, not data on stdin.
This is exactly what the xargs
command is for: read from stdin, and provide the data as command line arguments:
find . | xargs file -i
Or, use the -f
option for file
:
find . | file -i -f -
Read the man pages for more details.
add a comment
|
With a pipe, the command on the right-hand side reads the data on its stdin channel. The file
command requires the files to be command line arguments, not data on stdin.
This is exactly what the xargs
command is for: read from stdin, and provide the data as command line arguments:
find . | xargs file -i
Or, use the -f
option for file
:
find . | file -i -f -
Read the man pages for more details.
With a pipe, the command on the right-hand side reads the data on its stdin channel. The file
command requires the files to be command line arguments, not data on stdin.
This is exactly what the xargs
command is for: read from stdin, and provide the data as command line arguments:
find . | xargs file -i
Or, use the -f
option for file
:
find . | file -i -f -
Read the man pages for more details.
edited May 29 at 15:49
αғsнιη
26.1k23 gold badges105 silver badges168 bronze badges
26.1k23 gold badges105 silver badges168 bronze badges
answered May 29 at 14:49
glenn jackmanglenn jackman
13.3k27 silver badges47 bronze badges
13.3k27 silver badges47 bronze badges
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