I'm rewriting a full color Mandelbrot Set explorer in Python using tkinter. For it, I need to be able to convert a Tuple[int, int, int] into a hex string in the form #123456. Here are example uses of the two variants that I came up with:

>>>rgb_to_hex(123, 45, 6)
'#7b2d06'

>>>rgb_to_hex(99, 88, 77)
'#63584d'

>>>tup_rgb_to_hex((123, 45, 6))
'#7b2d06'

>>>tup_rgb_to_hex((99, 88, 77))
'#63584d'

>>>rgb_to_hex(*(123, 45, 6))
'#7b2d06'

>>>rgb_to_hex(*(99, 88, 77))
'#63584d'

The functions I've come up with are very simple, but intolerably slow. This code is a rare case where performance is a real concern. It will need to be called once per pixel, and my goal is to support the creation of images up to 50,000x30,000 pixels (1500000000 in total‬). 100 million executions take ~300 seconds:

>>>timeit.timeit(lambda: rgb_to_hex(255, 254, 253), number=int(1e8))
304.3993674000001

Which, unless my math is fubared, means this function alone will take 75 minutes in total for my extreme case.

I wrote two versions. The latter was to reduce redundancy (and since I'll be handling tuples anyways), but it was even slower, so I ended up just using unpacking on the first version:

# Takes a tuple instead
>>>timeit.timeit(lambda: tup_rgb_to_hex((255, 254, 253)), number=int(1e8))
342.8174099

# Unpacks arguments
>>>timeit.timeit(lambda: rgb_to_hex(*(255, 254, 253)), number=int(1e8))
308.64342439999973

The code:

from typing import Tuple

def _channel_to_hex(color_val: int) -> str:
 raw: str = hex(color_val)[2:]
 return raw.zfill(2)

def rgb_to_hex(red: int, green: int, blue: int) -> str:
 return "#" + _channel_to_hex(red) + _channel_to_hex(green) + _channel_to_hex(blue)

def tup_rgb_to_hex(rgb: Tuple[int, int, int]) -> str:
 return "#" + "".join([_channel_to_hex(c) for c in rgb])

I'd prefer to be able to use the tup_ variant for cleanliness, but there may not be a good way to automate the iteration with acceptable amounts of overhead.

Any performance-related tips (or anything else if you see something) are welcome.

You seem to be jumping through some unnecessary hoops. Just format a string directly:

from timeit import timeit


def _channel_to_hex(color_val: int) -> str:
 raw: str = hex(color_val)[2:]
 return raw.zfill(2)


def rgb_to_hex(red: int, green: int, blue: int) -> str:
 return "#" + _channel_to_hex(red) + _channel_to_hex(green) + _channel_to_hex(blue)


def direct_format(r, g, b):
 return f'#r:02xg:02xb:02x'


def one_word(r, g, b):
 rgb = r<<16 | g<<8 | b
 return f'#rgb:06x'



def main():
 N = 100000
 methods = (
 rgb_to_hex,
 direct_format,
 one_word,
 )
 for method in methods:
 hex = method(1, 2, 255)
 assert '#0102ff' == hex

 def run():
 return method(1, 2, 255)

 dur = timeit(run, number=N)
 print(f'method.__name__:15 1e6*dur/N:.2f us')


main()

produces:

rgb_to_hex 6.75 us
direct_format 3.14 us
one_word 2.74 us

That said, the faster thing to do is almost certainly to generate an image in-memory with a different framework and then send it to tkinter.

Another approach to generate the hex string is to directly reuse methods of format strings rather than writing your own function.

rgb_to_hex = "#:02x:02x:02x".format # rgb_to_hex(r, g, b) expands to "...".format(r, g, b)

rgb_tup_to_hex = "#%02x%02x%02x".__mod__ # rgb_tup_to_hex((r, g, b)) expands to "..." % (r, g, b)

These are faster (rgb_to_hex_orig is renamed from the rgb_to_hex function in the question):

rgb_tup = (0x20, 0xFB, 0xC2)

%timeit rgb_to_hex_orig(*rgb_tup)
%timeit direct_format(*rgb_tup)
%timeit one_word(*rgb_tup)
%timeit rgb_to_hex(*rgb_tup)
%timeit rgb_tup_to_hex(rgb_tup)

Results:

1.57 µs ± 5.14 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)
1.18 µs ± 5.34 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)
704 ns ± 3.35 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)
672 ns ± 4.54 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)
502 ns ± 7.23 ns per loop (mean ± std. dev. of 7 runs, 1000000 loops each)

rgb_tup_to_hex is the fastest partially due to it takes a tuple directly as its argument and avoids the small overhead of unpacking arguments.

However, I doubt these improvements would help solve your problem given its magnitude.

Using the Pillow / PIL library, pixel values can be directly set based on indices using tuples. Therefore converting tuples to strings are not really necessary. Here are examples showing basics of displaying PIL images in tkinter. This is likely still slow if the changes are done pixel by pixel. For extensive changes, the ImageDraw module or Image.putdata could be used.

memoization

The _channel_to_hex is called 3 times per pixel. It only takes 256 different inputs, so a logical first step would be to memoize the results. This can be done with either functools.lru_cache

from functools import lru_cache
@lru_cache(None)
def _channel_to_hex(color_val: int) -> str:
 raw: str = hex(color_val)[2:]
 return raw.zfill(2)

This already reduces the time needed with about a 3rd

An alternative is using a dict:

color_hexes =
 color_val: hex(color_val)[2:].zfill(2)
 for color_val in range(256)


def rgb_to_hex_dict(red: int, green: int, blue: int) -> str:
 return "#" + color_hexes[red] + color_hexes[green] + color_hexes[blue]

If the color-tuples are also limited (256**3 in worst case), so these can also be memoized

color_tuple_hexes = 
 rgb_to_hex_dict(*color_tuple)
 for color_tuple in itertools.product(range(256), repeat=3)

This takes about 15 seconds on my machine, but only needs to be done once.

If only a limited set of tuples is used, you can also use lru_cache

@lru_cache(None)
def rgb_to_hex_dict(red: int, green: int, blue: int) -> str:
 return "#" + color_hexes[red] + color_hexes[green] + color_hexes[blue]

numpy

if you have your data in a 3-dimensional numpy array, for example:

color_data = np.random.randint(256, size=(10,10,3))

You could do something like this:

coeffs = np.array([256**i for i in range(3)])
np_hex = (color_data * coeffs[np.newaxis, np.newaxis, :]).sum(axis=2)
np.vectorize(lambda x: "#" + hex(x)[2:].zfill(6))(np_hex)

Numpy is your best friend.

Given your comment:

The tuples are produced by "color scheme" functions. The functions take the (real, imaginary) coordinates of the pixel and how many iterations it took that pixel to fail, and return a three-tuple. They could return anything to indicate the color (that code is completely in my control), I just thought a three-tuple would by simplest. In theory, I could expect the functions to directly return a hex string, but that's just kicking the can down the road a bit since they need to be able to generate the string somehow.

Create a numpy array for the image you're going to create, then just assign your values into the array directly. Something like this:

import numpy as np

image = np.empty(shape=(final_image.ysize, final_image.xsize, 3), dtype=np.uint8)

# And instead of calling a function, assign to the array simply like:
image[x_coor, y_coor] = color_tuple

# Or if you really need a function:
image.__setitem__((x_coor, y_coor), color_tuple) # I haven't tested this with numpy, but something like it should work.

You do need to make sure that your arrays are in the same shape as tkinter expects it's images, though. And if you can make another shortcut to put the data into the array sooner, take it.

If you're doing an action this often, then you need to cut out function calls and such as often as you can. If possible, make the slice assignments bigger to set area's at the same time.