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Count of values grouped per month, year - Pandas
MySQL Query GROUP BY day / month / yearHow do I get the row count of a pandas DataFrame?Select rows from a DataFrame based on values in a column in pandasGet statistics for each group (such as count, mean, etc) using pandas GroupBy?Count unique dates in pandas dataframeCounting values using pandas groupbysplitting of date column to day, month, year in python 2.7Count Unique Days Groupby Month/YearCounting events per contributor per dayHow to count the number of dropoffs per month for dataframe column
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I am trying to groupby counts of dates per month and year in a specific output. I can do it per day but can't get the same output per month/year.
d = (
'Date' : ['1/1/18','1/1/18','2/1/18','3/1/18','1/2/18','1/3/18','2/1/19','3/1/19'],
'Val' : ['A','B','C','D','A','B','C','D'],
)
df = pd.DataFrame(data = d)
df['Date'] = pd.to_datetime(df['Date'], format= '%d/%m/%y')
df['Count_d'] = df.Date.map(df.groupby('Date').size())
This is the output I want:
Date Val Count_d
0 2018-01-01 A 2
1 2018-01-01 B 2
2 2018-01-02 C 1
3 2018-01-03 D 1
4 2018-02-01 A 1
5 2018-03-01 B 1
6 2019-01-02 C 1
7 2019-01-03 D 1
When I attempt to do similar but per month and year I use the following:
df1 = df.groupby([df['Date'].dt.year.rename('year'), df['Date'].dt.month.rename('month')]).agg('count')
print(df)
But the output is:
Date Val
count count
year month
2018 1 4 4
2 1 1
3 1 1
2019 1 2 2
Intended Output:
Date Val Count_d Count_m Count_y
0 2018-01-01 A 2 4 6
1 2018-01-01 B 2 4 6
2 2018-01-02 C 1 4 6
3 2018-01-03 D 1 4 6
4 2018-02-01 A 1 1 6
5 2018-03-01 B 1 1 6
6 2019-01-02 C 1 2 2
7 2019-01-03 D 1 2 2
python pandas group-by count transform
add a comment
|
I am trying to groupby counts of dates per month and year in a specific output. I can do it per day but can't get the same output per month/year.
d = (
'Date' : ['1/1/18','1/1/18','2/1/18','3/1/18','1/2/18','1/3/18','2/1/19','3/1/19'],
'Val' : ['A','B','C','D','A','B','C','D'],
)
df = pd.DataFrame(data = d)
df['Date'] = pd.to_datetime(df['Date'], format= '%d/%m/%y')
df['Count_d'] = df.Date.map(df.groupby('Date').size())
This is the output I want:
Date Val Count_d
0 2018-01-01 A 2
1 2018-01-01 B 2
2 2018-01-02 C 1
3 2018-01-03 D 1
4 2018-02-01 A 1
5 2018-03-01 B 1
6 2019-01-02 C 1
7 2019-01-03 D 1
When I attempt to do similar but per month and year I use the following:
df1 = df.groupby([df['Date'].dt.year.rename('year'), df['Date'].dt.month.rename('month')]).agg('count')
print(df)
But the output is:
Date Val
count count
year month
2018 1 4 4
2 1 1
3 1 1
2019 1 2 2
Intended Output:
Date Val Count_d Count_m Count_y
0 2018-01-01 A 2 4 6
1 2018-01-01 B 2 4 6
2 2018-01-02 C 1 4 6
3 2018-01-03 D 1 4 6
4 2018-02-01 A 1 1 6
5 2018-03-01 B 1 1 6
6 2019-01-02 C 1 2 2
7 2019-01-03 D 1 2 2
python pandas group-by count transform
add a comment
|
I am trying to groupby counts of dates per month and year in a specific output. I can do it per day but can't get the same output per month/year.
d = (
'Date' : ['1/1/18','1/1/18','2/1/18','3/1/18','1/2/18','1/3/18','2/1/19','3/1/19'],
'Val' : ['A','B','C','D','A','B','C','D'],
)
df = pd.DataFrame(data = d)
df['Date'] = pd.to_datetime(df['Date'], format= '%d/%m/%y')
df['Count_d'] = df.Date.map(df.groupby('Date').size())
This is the output I want:
Date Val Count_d
0 2018-01-01 A 2
1 2018-01-01 B 2
2 2018-01-02 C 1
3 2018-01-03 D 1
4 2018-02-01 A 1
5 2018-03-01 B 1
6 2019-01-02 C 1
7 2019-01-03 D 1
When I attempt to do similar but per month and year I use the following:
df1 = df.groupby([df['Date'].dt.year.rename('year'), df['Date'].dt.month.rename('month')]).agg('count')
print(df)
But the output is:
Date Val
count count
year month
2018 1 4 4
2 1 1
3 1 1
2019 1 2 2
Intended Output:
Date Val Count_d Count_m Count_y
0 2018-01-01 A 2 4 6
1 2018-01-01 B 2 4 6
2 2018-01-02 C 1 4 6
3 2018-01-03 D 1 4 6
4 2018-02-01 A 1 1 6
5 2018-03-01 B 1 1 6
6 2019-01-02 C 1 2 2
7 2019-01-03 D 1 2 2
python pandas group-by count transform
I am trying to groupby counts of dates per month and year in a specific output. I can do it per day but can't get the same output per month/year.
d = (
'Date' : ['1/1/18','1/1/18','2/1/18','3/1/18','1/2/18','1/3/18','2/1/19','3/1/19'],
'Val' : ['A','B','C','D','A','B','C','D'],
)
df = pd.DataFrame(data = d)
df['Date'] = pd.to_datetime(df['Date'], format= '%d/%m/%y')
df['Count_d'] = df.Date.map(df.groupby('Date').size())
This is the output I want:
Date Val Count_d
0 2018-01-01 A 2
1 2018-01-01 B 2
2 2018-01-02 C 1
3 2018-01-03 D 1
4 2018-02-01 A 1
5 2018-03-01 B 1
6 2019-01-02 C 1
7 2019-01-03 D 1
When I attempt to do similar but per month and year I use the following:
df1 = df.groupby([df['Date'].dt.year.rename('year'), df['Date'].dt.month.rename('month')]).agg('count')
print(df)
But the output is:
Date Val
count count
year month
2018 1 4 4
2 1 1
3 1 1
2019 1 2 2
Intended Output:
Date Val Count_d Count_m Count_y
0 2018-01-01 A 2 4 6
1 2018-01-01 B 2 4 6
2 2018-01-02 C 1 4 6
3 2018-01-03 D 1 4 6
4 2018-02-01 A 1 1 6
5 2018-03-01 B 1 1 6
6 2019-01-02 C 1 2 2
7 2019-01-03 D 1 2 2
python pandas group-by count transform
python pandas group-by count transform
edited Apr 19 at 3:08
jonboy
asked Apr 17 at 11:05
jonboyjonboy
492 silver badges15 bronze badges
492 silver badges15 bronze badges
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2 Answers
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votes
Use GroupBy.transform for columns with same size like original DataFrame:
df['Date'] = pd.to_datetime(df['Date'], format= '%d/%m/%y')
y = df['Date'].dt.year
m = df['Date'].dt.month
df['Count_d'] = df.groupby('Date')['Date'].transform('size')
df['Count_m'] = df.groupby([y, m])['Date'].transform('size')
df['Count_y'] = df.groupby(y)['Date'].transform('size')
print(df)
Date Val Count_d Count_m Count_y
0 2018-01-01 A 2 4 6
1 2018-01-01 B 2 4 6
2 2018-01-02 C 1 4 6
3 2018-01-03 D 1 4 6
4 2018-02-01 A 1 1 6
5 2018-03-01 B 1 1 6
6 2019-01-02 C 1 2 2
7 2019-01-03 D 1 2 2
just found that they are removing agg with dict. any idea why?
– anky_91
Apr 17 at 11:14
@anky_91 - because same size columns like original df.
– jezrael
Apr 17 at 11:15
where did you see that @anky_91
– Erfan
Apr 17 at 11:15
@Erfan got a future warning. i was implementing wrongly i guess, jez made that clear
– anky_91
Apr 17 at 11:16
add a comment
|
You can do this with pd.Grouper
df['Count_d'] = df.groupby([pd.Grouper(key='Date', freq='D')])['Date'].transform('size').astype(int)
df['Count_m'] = df.groupby([pd.Grouper(key='Date', freq='M')])['Date'].transform('size').astype(int)
df['Count_y'] = df.groupby([pd.Grouper(key='Date', freq='Y')])['Date'].transform('size').astype(int)
Which will give
Date Val Count_d Count_m Count_y
0 2018-01-01 A 2 4 6
1 2018-01-01 B 2 4 6
2 2018-01-02 C 1 4 6
3 2018-01-03 D 1 4 6
4 2018-02-01 A 1 1 6
5 2018-03-01 B 1 1 6
6 2019-01-02 C 1 2 2
7 2019-01-03 D 1 2 2
You can groupby various different frequencies with this, see the documentation on DateOffsets
add a comment
|
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Use GroupBy.transform for columns with same size like original DataFrame:
df['Date'] = pd.to_datetime(df['Date'], format= '%d/%m/%y')
y = df['Date'].dt.year
m = df['Date'].dt.month
df['Count_d'] = df.groupby('Date')['Date'].transform('size')
df['Count_m'] = df.groupby([y, m])['Date'].transform('size')
df['Count_y'] = df.groupby(y)['Date'].transform('size')
print(df)
Date Val Count_d Count_m Count_y
0 2018-01-01 A 2 4 6
1 2018-01-01 B 2 4 6
2 2018-01-02 C 1 4 6
3 2018-01-03 D 1 4 6
4 2018-02-01 A 1 1 6
5 2018-03-01 B 1 1 6
6 2019-01-02 C 1 2 2
7 2019-01-03 D 1 2 2
just found that they are removing agg with dict. any idea why?
– anky_91
Apr 17 at 11:14
@anky_91 - because same size columns like original df.
– jezrael
Apr 17 at 11:15
where did you see that @anky_91
– Erfan
Apr 17 at 11:15
@Erfan got a future warning. i was implementing wrongly i guess, jez made that clear
– anky_91
Apr 17 at 11:16
add a comment
|
Use GroupBy.transform for columns with same size like original DataFrame:
df['Date'] = pd.to_datetime(df['Date'], format= '%d/%m/%y')
y = df['Date'].dt.year
m = df['Date'].dt.month
df['Count_d'] = df.groupby('Date')['Date'].transform('size')
df['Count_m'] = df.groupby([y, m])['Date'].transform('size')
df['Count_y'] = df.groupby(y)['Date'].transform('size')
print(df)
Date Val Count_d Count_m Count_y
0 2018-01-01 A 2 4 6
1 2018-01-01 B 2 4 6
2 2018-01-02 C 1 4 6
3 2018-01-03 D 1 4 6
4 2018-02-01 A 1 1 6
5 2018-03-01 B 1 1 6
6 2019-01-02 C 1 2 2
7 2019-01-03 D 1 2 2
just found that they are removing agg with dict. any idea why?
– anky_91
Apr 17 at 11:14
@anky_91 - because same size columns like original df.
– jezrael
Apr 17 at 11:15
where did you see that @anky_91
– Erfan
Apr 17 at 11:15
@Erfan got a future warning. i was implementing wrongly i guess, jez made that clear
– anky_91
Apr 17 at 11:16
add a comment
|
Use GroupBy.transform for columns with same size like original DataFrame:
df['Date'] = pd.to_datetime(df['Date'], format= '%d/%m/%y')
y = df['Date'].dt.year
m = df['Date'].dt.month
df['Count_d'] = df.groupby('Date')['Date'].transform('size')
df['Count_m'] = df.groupby([y, m])['Date'].transform('size')
df['Count_y'] = df.groupby(y)['Date'].transform('size')
print(df)
Date Val Count_d Count_m Count_y
0 2018-01-01 A 2 4 6
1 2018-01-01 B 2 4 6
2 2018-01-02 C 1 4 6
3 2018-01-03 D 1 4 6
4 2018-02-01 A 1 1 6
5 2018-03-01 B 1 1 6
6 2019-01-02 C 1 2 2
7 2019-01-03 D 1 2 2
Use GroupBy.transform for columns with same size like original DataFrame:
df['Date'] = pd.to_datetime(df['Date'], format= '%d/%m/%y')
y = df['Date'].dt.year
m = df['Date'].dt.month
df['Count_d'] = df.groupby('Date')['Date'].transform('size')
df['Count_m'] = df.groupby([y, m])['Date'].transform('size')
df['Count_y'] = df.groupby(y)['Date'].transform('size')
print(df)
Date Val Count_d Count_m Count_y
0 2018-01-01 A 2 4 6
1 2018-01-01 B 2 4 6
2 2018-01-02 C 1 4 6
3 2018-01-03 D 1 4 6
4 2018-02-01 A 1 1 6
5 2018-03-01 B 1 1 6
6 2019-01-02 C 1 2 2
7 2019-01-03 D 1 2 2
edited Apr 17 at 11:16
answered Apr 17 at 11:11
jezraeljezrael
416k33 gold badges437 silver badges499 bronze badges
416k33 gold badges437 silver badges499 bronze badges
just found that they are removing agg with dict. any idea why?
– anky_91
Apr 17 at 11:14
@anky_91 - because same size columns like original df.
– jezrael
Apr 17 at 11:15
where did you see that @anky_91
– Erfan
Apr 17 at 11:15
@Erfan got a future warning. i was implementing wrongly i guess, jez made that clear
– anky_91
Apr 17 at 11:16
add a comment
|
just found that they are removing agg with dict. any idea why?
– anky_91
Apr 17 at 11:14
@anky_91 - because same size columns like original df.
– jezrael
Apr 17 at 11:15
where did you see that @anky_91
– Erfan
Apr 17 at 11:15
@Erfan got a future warning. i was implementing wrongly i guess, jez made that clear
– anky_91
Apr 17 at 11:16
just found that they are removing agg with dict. any idea why?
– anky_91
Apr 17 at 11:14
just found that they are removing agg with dict. any idea why?
– anky_91
Apr 17 at 11:14
@anky_91 - because same size columns like original df.
– jezrael
Apr 17 at 11:15
@anky_91 - because same size columns like original df.
– jezrael
Apr 17 at 11:15
where did you see that @anky_91
– Erfan
Apr 17 at 11:15
where did you see that @anky_91
– Erfan
Apr 17 at 11:15
@Erfan got a future warning. i was implementing wrongly i guess, jez made that clear
– anky_91
Apr 17 at 11:16
@Erfan got a future warning. i was implementing wrongly i guess, jez made that clear
– anky_91
Apr 17 at 11:16
add a comment
|
You can do this with pd.Grouper
df['Count_d'] = df.groupby([pd.Grouper(key='Date', freq='D')])['Date'].transform('size').astype(int)
df['Count_m'] = df.groupby([pd.Grouper(key='Date', freq='M')])['Date'].transform('size').astype(int)
df['Count_y'] = df.groupby([pd.Grouper(key='Date', freq='Y')])['Date'].transform('size').astype(int)
Which will give
Date Val Count_d Count_m Count_y
0 2018-01-01 A 2 4 6
1 2018-01-01 B 2 4 6
2 2018-01-02 C 1 4 6
3 2018-01-03 D 1 4 6
4 2018-02-01 A 1 1 6
5 2018-03-01 B 1 1 6
6 2019-01-02 C 1 2 2
7 2019-01-03 D 1 2 2
You can groupby various different frequencies with this, see the documentation on DateOffsets
add a comment
|
You can do this with pd.Grouper
df['Count_d'] = df.groupby([pd.Grouper(key='Date', freq='D')])['Date'].transform('size').astype(int)
df['Count_m'] = df.groupby([pd.Grouper(key='Date', freq='M')])['Date'].transform('size').astype(int)
df['Count_y'] = df.groupby([pd.Grouper(key='Date', freq='Y')])['Date'].transform('size').astype(int)
Which will give
Date Val Count_d Count_m Count_y
0 2018-01-01 A 2 4 6
1 2018-01-01 B 2 4 6
2 2018-01-02 C 1 4 6
3 2018-01-03 D 1 4 6
4 2018-02-01 A 1 1 6
5 2018-03-01 B 1 1 6
6 2019-01-02 C 1 2 2
7 2019-01-03 D 1 2 2
You can groupby various different frequencies with this, see the documentation on DateOffsets
add a comment
|
You can do this with pd.Grouper
df['Count_d'] = df.groupby([pd.Grouper(key='Date', freq='D')])['Date'].transform('size').astype(int)
df['Count_m'] = df.groupby([pd.Grouper(key='Date', freq='M')])['Date'].transform('size').astype(int)
df['Count_y'] = df.groupby([pd.Grouper(key='Date', freq='Y')])['Date'].transform('size').astype(int)
Which will give
Date Val Count_d Count_m Count_y
0 2018-01-01 A 2 4 6
1 2018-01-01 B 2 4 6
2 2018-01-02 C 1 4 6
3 2018-01-03 D 1 4 6
4 2018-02-01 A 1 1 6
5 2018-03-01 B 1 1 6
6 2019-01-02 C 1 2 2
7 2019-01-03 D 1 2 2
You can groupby various different frequencies with this, see the documentation on DateOffsets
You can do this with pd.Grouper
df['Count_d'] = df.groupby([pd.Grouper(key='Date', freq='D')])['Date'].transform('size').astype(int)
df['Count_m'] = df.groupby([pd.Grouper(key='Date', freq='M')])['Date'].transform('size').astype(int)
df['Count_y'] = df.groupby([pd.Grouper(key='Date', freq='Y')])['Date'].transform('size').astype(int)
Which will give
Date Val Count_d Count_m Count_y
0 2018-01-01 A 2 4 6
1 2018-01-01 B 2 4 6
2 2018-01-02 C 1 4 6
3 2018-01-03 D 1 4 6
4 2018-02-01 A 1 1 6
5 2018-03-01 B 1 1 6
6 2019-01-02 C 1 2 2
7 2019-01-03 D 1 2 2
You can groupby various different frequencies with this, see the documentation on DateOffsets
answered Apr 17 at 11:11
Ken SymeKen Syme
2,5061 gold badge12 silver badges17 bronze badges
2,5061 gold badge12 silver badges17 bronze badges
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add a comment
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