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Gas chromatography flame ionization detector (FID) - why hydrogen gas?

Why do batteries specifically vent *hydrogen* in the event of abuse?Why is the ionization energy for Hydrogen non-zero?Why is the electronegativity of hydrogen 2.20?Why are hydrogen ions always associated with another molecule?Hydrogen venting: Why no flame arrestors?Use a solid or liquid stationary phase in gas chromatographyConcept of Adjusted Retention Time in Chromatography

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4

$begingroup$

Why is $ceH2$ used in an FID, apart from the fact its combustion does not contaminate the flame?

In other words, is the temperature of the flame important or critical? Is the stability of the temperature?

hydrogen chromatography

share|improve this question

edited May 19 at 19:32

Peter Mortensen

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asked May 19 at 12:08

Dirk BruereDirk Bruere

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$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  What alternative would you suggest ? E.g.a methane-air flame in FID would be like e.g using methylchloride as the makeup gas in ECD.
  $endgroup$
  – Poutnik
  May 19 at 12:43
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @Poutnik One alternative would be electric arc ionization. Another extreme UV. What is special about H2?
  $endgroup$
  – Dirk Bruere
  May 19 at 13:21
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  It would be even much worse than methane. The key is to keep as low baseline ionisation as possible. That does not happen with methane flame and definitely not with arc or UV ionisation. With the arc, there would be additionally very high noise, several orders higher than useful signal.
  $endgroup$
  – Poutnik
  May 19 at 13:26
  

  
  
  
  

add a comment
 | 

4

$begingroup$

Why is $ceH2$ used in an FID, apart from the fact its combustion does not contaminate the flame?

In other words, is the temperature of the flame important or critical? Is the stability of the temperature?

hydrogen chromatography

share|improve this question

edited May 19 at 19:32

Peter Mortensen

22411 silver badge1010 bronze badges

asked May 19 at 12:08

Dirk BruereDirk Bruere

63255 silver badges1414 bronze badges

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  What alternative would you suggest ? E.g.a methane-air flame in FID would be like e.g using methylchloride as the makeup gas in ECD.
  $endgroup$
  – Poutnik
  May 19 at 12:43
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @Poutnik One alternative would be electric arc ionization. Another extreme UV. What is special about H2?
  $endgroup$
  – Dirk Bruere
  May 19 at 13:21
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  $begingroup$
  It would be even much worse than methane. The key is to keep as low baseline ionisation as possible. That does not happen with methane flame and definitely not with arc or UV ionisation. With the arc, there would be additionally very high noise, several orders higher than useful signal.
  $endgroup$
  – Poutnik
  May 19 at 13:26
  

  
  
  
  

add a comment
 | 

$begingroup$

Why is $ceH2$ used in an FID, apart from the fact its combustion does not contaminate the flame?

In other words, is the temperature of the flame important or critical? Is the stability of the temperature?

hydrogen chromatography

share|improve this question

edited May 19 at 19:32

Peter Mortensen

22411 silver badge1010 bronze badges

asked May 19 at 12:08

Dirk BruereDirk Bruere

63255 silver badges1414 bronze badges

$endgroup$

share|improve this question

edited May 19 at 19:32

Peter Mortensen

22411 silver badge1010 bronze badges

asked May 19 at 12:08

Dirk BruereDirk Bruere

63255 silver badges1414 bronze badges

share|improve this question

edited May 19 at 19:32

Peter Mortensen

22411 silver badge1010 bronze badges

asked May 19 at 12:08

Dirk BruereDirk Bruere

63255 silver badges1414 bronze badges

edited May 19 at 19:32

Peter Mortensen

22411 silver badge1010 bronze badges

edited May 19 at 19:32

Peter Mortensen

22411 silver badge1010 bronze badges

asked May 19 at 12:08

Dirk BruereDirk Bruere

63255 silver badges1414 bronze badges

asked May 19 at 12:08

Dirk BruereDirk Bruere

63255 silver badges1414 bronze badges

2 Answers
2

active

oldest

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6

$begingroup$

The key to the answer is understanding how FID works.

The hydrogen flame has a minimal flame ionisation, what is needed for the low signal baseline.

Incoming organic molecules from the HPGC column create in the flame a lot of ions and increase the flame electric conductivity.

Using alternatives causing higher ionisation would decrease FID sensitivity that is not great even at ideal conditions, compared to e.g. ECD.

share|improve this answer

edited May 23 at 0:38

Melanie Shebel♦

3,50577 gold badges3535 silver badges7474 bronze badges

answered May 19 at 13:59

PoutnikPoutnik

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$endgroup$

add a comment
 | 

2

$begingroup$

Another fundamental aspect of using hydrogen in gas chromatography is the so-called van Deemter curve. The curve shows the linear velocity of the gas on the x-axis and plate heights on the y-axis. It can be shown that by using hydrogen one can obtain the best efficiency as compared to any other gas.

And of course, hydrogen is required for burning the organic molecules exiting the column. It is a clean flame (no carbon background).

share|improve this answer

edited May 23 at 0:38

Melanie Shebel♦

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answered May 19 at 22:40

M. FarooqM. Farooq

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add a comment
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6

$begingroup$

The key to the answer is understanding how FID works.

The hydrogen flame has a minimal flame ionisation, what is needed for the low signal baseline.

Incoming organic molecules from the HPGC column create in the flame a lot of ions and increase the flame electric conductivity.

Using alternatives causing higher ionisation would decrease FID sensitivity that is not great even at ideal conditions, compared to e.g. ECD.

share|improve this answer

edited May 23 at 0:38

Melanie Shebel♦

3,50577 gold badges3535 silver badges7474 bronze badges

answered May 19 at 13:59

PoutnikPoutnik

5,51511 gold badge77 silver badges2626 bronze badges

$endgroup$

add a comment
 | 

6

$begingroup$

The key to the answer is understanding how FID works.

The hydrogen flame has a minimal flame ionisation, what is needed for the low signal baseline.

Incoming organic molecules from the HPGC column create in the flame a lot of ions and increase the flame electric conductivity.

Using alternatives causing higher ionisation would decrease FID sensitivity that is not great even at ideal conditions, compared to e.g. ECD.

share|improve this answer

edited May 23 at 0:38

Melanie Shebel♦

3,50577 gold badges3535 silver badges7474 bronze badges

answered May 19 at 13:59

PoutnikPoutnik

5,51511 gold badge77 silver badges2626 bronze badges

$endgroup$

add a comment
 | 

$begingroup$

The key to the answer is understanding how FID works.

The hydrogen flame has a minimal flame ionisation, what is needed for the low signal baseline.

Incoming organic molecules from the HPGC column create in the flame a lot of ions and increase the flame electric conductivity.

Using alternatives causing higher ionisation would decrease FID sensitivity that is not great even at ideal conditions, compared to e.g. ECD.

share|improve this answer

edited May 23 at 0:38

Melanie Shebel♦

3,50577 gold badges3535 silver badges7474 bronze badges

answered May 19 at 13:59

PoutnikPoutnik

5,51511 gold badge77 silver badges2626 bronze badges

$endgroup$

share|improve this answer

edited May 23 at 0:38

Melanie Shebel♦

3,50577 gold badges3535 silver badges7474 bronze badges

answered May 19 at 13:59

PoutnikPoutnik

5,51511 gold badge77 silver badges2626 bronze badges

edited May 23 at 0:38

Melanie Shebel♦

3,50577 gold badges3535 silver badges7474 bronze badges

edited May 23 at 0:38

Melanie Shebel♦

3,50577 gold badges3535 silver badges7474 bronze badges

answered May 19 at 13:59

PoutnikPoutnik

5,51511 gold badge77 silver badges2626 bronze badges

answered May 19 at 13:59

PoutnikPoutnik

5,51511 gold badge77 silver badges2626 bronze badges

2

$begingroup$

Another fundamental aspect of using hydrogen in gas chromatography is the so-called van Deemter curve. The curve shows the linear velocity of the gas on the x-axis and plate heights on the y-axis. It can be shown that by using hydrogen one can obtain the best efficiency as compared to any other gas.

And of course, hydrogen is required for burning the organic molecules exiting the column. It is a clean flame (no carbon background).

share|improve this answer

edited May 23 at 0:38

Melanie Shebel♦

3,50577 gold badges3535 silver badges7474 bronze badges

answered May 19 at 22:40

M. FarooqM. Farooq

7,4831010 silver badges2828 bronze badges

$endgroup$

add a comment
 | 

2

$begingroup$

Another fundamental aspect of using hydrogen in gas chromatography is the so-called van Deemter curve. The curve shows the linear velocity of the gas on the x-axis and plate heights on the y-axis. It can be shown that by using hydrogen one can obtain the best efficiency as compared to any other gas.

And of course, hydrogen is required for burning the organic molecules exiting the column. It is a clean flame (no carbon background).

share|improve this answer

edited May 23 at 0:38

Melanie Shebel♦

3,50577 gold badges3535 silver badges7474 bronze badges

answered May 19 at 22:40

M. FarooqM. Farooq

7,4831010 silver badges2828 bronze badges

$endgroup$

add a comment
 | 

$begingroup$

Another fundamental aspect of using hydrogen in gas chromatography is the so-called van Deemter curve. The curve shows the linear velocity of the gas on the x-axis and plate heights on the y-axis. It can be shown that by using hydrogen one can obtain the best efficiency as compared to any other gas.

And of course, hydrogen is required for burning the organic molecules exiting the column. It is a clean flame (no carbon background).

share|improve this answer

edited May 23 at 0:38

Melanie Shebel♦

3,50577 gold badges3535 silver badges7474 bronze badges

answered May 19 at 22:40

M. FarooqM. Farooq

7,4831010 silver badges2828 bronze badges

$endgroup$

share|improve this answer

edited May 23 at 0:38

Melanie Shebel♦

3,50577 gold badges3535 silver badges7474 bronze badges

answered May 19 at 22:40

M. FarooqM. Farooq

7,4831010 silver badges2828 bronze badges

edited May 23 at 0:38

Melanie Shebel♦

3,50577 gold badges3535 silver badges7474 bronze badges

edited May 23 at 0:38

Melanie Shebel♦

3,50577 gold badges3535 silver badges7474 bronze badges

answered May 19 at 22:40

M. FarooqM. Farooq

7,4831010 silver badges2828 bronze badges

answered May 19 at 22:40

M. FarooqM. Farooq

7,4831010 silver badges2828 bronze badges