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How can I remove rest of file from string for all files?

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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty
margin-bottom:0;

9

1

How can I remove rest of file from string for all files?

For example, input files 1 and 2, string is ddd.

Input file 1.

aaa
bbb
ccc
ddfbbd dddaaa
eee

Output file 1.

aaa
bbb
ccc
ddfbbd 

Input file 2.

ccc
aergddd
dasdvsdb

Output file 2.

ccc
aerg

text-processing sed

share|improve this question

edited Oct 1 at 15:06

Solomon Ucko

10511 silver badge55 bronze badges

asked Sep 30 at 14:31

genderbeegenderbee

54299 bronze badges

add a comment
 | 

9

1

How can I remove rest of file from string for all files?

For example, input files 1 and 2, string is ddd.

Input file 1.

aaa
bbb
ccc
ddfbbd dddaaa
eee

Output file 1.

aaa
bbb
ccc
ddfbbd 

Input file 2.

ccc
aergddd
dasdvsdb

Output file 2.

ccc
aerg

text-processing sed

share|improve this question

edited Oct 1 at 15:06

Solomon Ucko

10511 silver badge55 bronze badges

asked Sep 30 at 14:31

genderbeegenderbee

54299 bronze badges

add a comment
 | 

How can I remove rest of file from string for all files?

For example, input files 1 and 2, string is ddd.

Input file 1.

aaa
bbb
ccc
ddfbbd dddaaa
eee

Output file 1.

aaa
bbb
ccc
ddfbbd 

Input file 2.

ccc
aergddd
dasdvsdb

Output file 2.

ccc
aerg

text-processing sed

share|improve this question

edited Oct 1 at 15:06

Solomon Ucko

10511 silver badge55 bronze badges

asked Sep 30 at 14:31

genderbeegenderbee

54299 bronze badges

aaa
bbb
ccc
ddfbbd dddaaa
eee

aaa
bbb
ccc
ddfbbd 

ccc
aergddd
dasdvsdb

ccc
aerg

share|improve this question

edited Oct 1 at 15:06

Solomon Ucko

10511 silver badge55 bronze badges

asked Sep 30 at 14:31

genderbeegenderbee

54299 bronze badges

share|improve this question

edited Oct 1 at 15:06

Solomon Ucko

10511 silver badge55 bronze badges

asked Sep 30 at 14:31

genderbeegenderbee

54299 bronze badges

edited Oct 1 at 15:06

Solomon Ucko

10511 silver badge55 bronze badges

edited Oct 1 at 15:06

Solomon Ucko

10511 silver badge55 bronze badges

asked Sep 30 at 14:31

genderbeegenderbee

54299 bronze badges

asked Sep 30 at 14:31

genderbeegenderbee

54299 bronze badges

3 Answers
3

active

oldest

votes

11

With GNU sed:

str="ddd"
for file in 1 2; do
 sed -i "/$str/ s/$str.*//; q" "$file"
done

This needs to be in a loop: otherwise the q command would abort the whole process after processing only the first file.

share|improve this answer

edited Sep 30 at 15:29

dessert

30.5k77 gold badges8989 silver badges123123 bronze badges

answered Sep 30 at 15:09

glenn jackmanglenn jackman

14k11 gold badge2828 silver badges4848 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Found it interesting you answered a similar question in Unix & LInux 8 years ago: unix.stackexchange.com/a/11323/200094
  
  – WinEunuuchs2Unix
  Oct 1 at 10:56
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I wonder if you could just d instead of q
  
  – D. Ben Knoble
  Oct 1 at 18:31
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You're welcome to try. sed is not a go-to tool for me once things get more complicated that what I did.
  
  – glenn jackman
  Oct 1 at 19:08
  

  
  
  
  

add a comment
 | 

7

With Perl:

perl -i -0777 -pe 's/ddd[sS]*//' file

or

perl -i -0777 -pe 's/ddd.*//s' file

• -i: modify the file in place.




• -0777: force Perl to slurp the file as whole, not line by line.



• 
  

  -pe:

  
  
  
  • 
    -p: loop Perl code.
  
  
  • 
    -e: execute Perl code.
  
  



• 's/ddd[sS]*//': replace everything (every whitespace (s) and non-whitespace (S) character) after ddd (including it) with an empty string.




• 's/ddd.*//s': replace everything (.*) after ddd (including it) with an empty string. The s flag at the end makes .* also match newlines (thanks @glennjackman).

More about Perl flags can be found here.

share|improve this answer

edited Oct 1 at 12:40

answered Sep 30 at 15:57

user3140225user3140225

2,71044 gold badges1212 silver badges2424 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Why not just s/ddd.*//?
  
  – dessert
  Sep 30 at 16:41
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @dessert .* stops matching at newline.
  
  – user3140225
  Sep 30 at 16:53
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You can use..* if you add the m or s flag to the s/// command (I forget which one)
  
  – glenn jackman
  Sep 30 at 21:23
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @glennjackman It's the s flag. Thanks!
  
  – user3140225
  Oct 1 at 7:33
  

  
  
  
  

add a comment
 | 

4

with GNU awk, we can do:

awk 'function output() print >>FILENAME".out" 
 /ddd/ sub(/ddd.*/,""); output(); nextfile 
 output() ' file[12]

to change inplace, which it makes command even simple:

gawk -i inplace '/ddd/ sub(/ddd.*/,""); print ; nextfile 1' file[12]

share|improve this answer

edited Oct 1 at 10:05

answered Sep 30 at 15:39

αғsнιηαғsнιη

28.8k2323 gold badges107107 silver badges170170 bronze badges

add a comment
 | 

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11

With GNU sed:

str="ddd"
for file in 1 2; do
 sed -i "/$str/ s/$str.*//; q" "$file"
done

This needs to be in a loop: otherwise the q command would abort the whole process after processing only the first file.

share|improve this answer

edited Sep 30 at 15:29

dessert

30.5k77 gold badges8989 silver badges123123 bronze badges

answered Sep 30 at 15:09

glenn jackmanglenn jackman

14k11 gold badge2828 silver badges4848 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Found it interesting you answered a similar question in Unix & LInux 8 years ago: unix.stackexchange.com/a/11323/200094
  
  – WinEunuuchs2Unix
  Oct 1 at 10:56
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I wonder if you could just d instead of q
  
  – D. Ben Knoble
  Oct 1 at 18:31
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You're welcome to try. sed is not a go-to tool for me once things get more complicated that what I did.
  
  – glenn jackman
  Oct 1 at 19:08
  

  
  
  
  

add a comment
 | 

11

With GNU sed:

str="ddd"
for file in 1 2; do
 sed -i "/$str/ s/$str.*//; q" "$file"
done

This needs to be in a loop: otherwise the q command would abort the whole process after processing only the first file.

share|improve this answer

edited Sep 30 at 15:29

dessert

30.5k77 gold badges8989 silver badges123123 bronze badges

answered Sep 30 at 15:09

glenn jackmanglenn jackman

14k11 gold badge2828 silver badges4848 bronze badges

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Found it interesting you answered a similar question in Unix & LInux 8 years ago: unix.stackexchange.com/a/11323/200094
  
  – WinEunuuchs2Unix
  Oct 1 at 10:56
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I wonder if you could just d instead of q
  
  – D. Ben Knoble
  Oct 1 at 18:31
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You're welcome to try. sed is not a go-to tool for me once things get more complicated that what I did.
  
  – glenn jackman
  Oct 1 at 19:08
  

  
  
  
  

add a comment
 | 

With GNU sed:

str="ddd"
for file in 1 2; do
 sed -i "/$str/ s/$str.*//; q" "$file"
done

This needs to be in a loop: otherwise the q command would abort the whole process after processing only the first file.

share|improve this answer

edited Sep 30 at 15:29

dessert

30.5k77 gold badges8989 silver badges123123 bronze badges

answered Sep 30 at 15:09

glenn jackmanglenn jackman

14k11 gold badge2828 silver badges4848 bronze badges

str="ddd"
for file in 1 2; do
 sed -i "/$str/ s/$str.*//; q" "$file"
done

share|improve this answer

edited Sep 30 at 15:29

dessert

30.5k77 gold badges8989 silver badges123123 bronze badges

answered Sep 30 at 15:09

glenn jackmanglenn jackman

14k11 gold badge2828 silver badges4848 bronze badges

edited Sep 30 at 15:29

dessert

30.5k77 gold badges8989 silver badges123123 bronze badges

edited Sep 30 at 15:29

dessert

30.5k77 gold badges8989 silver badges123123 bronze badges

answered Sep 30 at 15:09

glenn jackmanglenn jackman

14k11 gold badge2828 silver badges4848 bronze badges

answered Sep 30 at 15:09

glenn jackmanglenn jackman

14k11 gold badge2828 silver badges4848 bronze badges

7

With Perl:

perl -i -0777 -pe 's/ddd[sS]*//' file

or

perl -i -0777 -pe 's/ddd.*//s' file

• -i: modify the file in place.




• -0777: force Perl to slurp the file as whole, not line by line.



• 
  

  -pe:

  
  
  
  • 
    -p: loop Perl code.
  
  
  • 
    -e: execute Perl code.
  
  



• 's/ddd[sS]*//': replace everything (every whitespace (s) and non-whitespace (S) character) after ddd (including it) with an empty string.




• 's/ddd.*//s': replace everything (.*) after ddd (including it) with an empty string. The s flag at the end makes .* also match newlines (thanks @glennjackman).

More about Perl flags can be found here.

share|improve this answer

edited Oct 1 at 12:40

answered Sep 30 at 15:57

user3140225user3140225

2,71044 gold badges1212 silver badges2424 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Why not just s/ddd.*//?
  
  – dessert
  Sep 30 at 16:41
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @dessert .* stops matching at newline.
  
  – user3140225
  Sep 30 at 16:53
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You can use..* if you add the m or s flag to the s/// command (I forget which one)
  
  – glenn jackman
  Sep 30 at 21:23
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @glennjackman It's the s flag. Thanks!
  
  – user3140225
  Oct 1 at 7:33
  

  
  
  
  

add a comment
 | 

7

With Perl:

perl -i -0777 -pe 's/ddd[sS]*//' file

or

perl -i -0777 -pe 's/ddd.*//s' file

• -i: modify the file in place.




• -0777: force Perl to slurp the file as whole, not line by line.



• 
  

  -pe:

  
  
  
  • 
    -p: loop Perl code.
  
  
  • 
    -e: execute Perl code.
  
  



• 's/ddd[sS]*//': replace everything (every whitespace (s) and non-whitespace (S) character) after ddd (including it) with an empty string.




• 's/ddd.*//s': replace everything (.*) after ddd (including it) with an empty string. The s flag at the end makes .* also match newlines (thanks @glennjackman).

More about Perl flags can be found here.

share|improve this answer

edited Oct 1 at 12:40

answered Sep 30 at 15:57

user3140225user3140225

2,71044 gold badges1212 silver badges2424 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Why not just s/ddd.*//?
  
  – dessert
  Sep 30 at 16:41
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @dessert .* stops matching at newline.
  
  – user3140225
  Sep 30 at 16:53
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You can use..* if you add the m or s flag to the s/// command (I forget which one)
  
  – glenn jackman
  Sep 30 at 21:23
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @glennjackman It's the s flag. Thanks!
  
  – user3140225
  Oct 1 at 7:33
  

  
  
  
  

add a comment
 | 

With Perl:

perl -i -0777 -pe 's/ddd[sS]*//' file

or

perl -i -0777 -pe 's/ddd.*//s' file

• -i: modify the file in place.




• -0777: force Perl to slurp the file as whole, not line by line.



• 
  

  -pe:

  
  
  
  • 
    -p: loop Perl code.
  
  
  • 
    -e: execute Perl code.
  
  



• 's/ddd[sS]*//': replace everything (every whitespace (s) and non-whitespace (S) character) after ddd (including it) with an empty string.




• 's/ddd.*//s': replace everything (.*) after ddd (including it) with an empty string. The s flag at the end makes .* also match newlines (thanks @glennjackman).

More about Perl flags can be found here.

share|improve this answer

edited Oct 1 at 12:40

answered Sep 30 at 15:57

user3140225user3140225

2,71044 gold badges1212 silver badges2424 bronze badges

perl -i -0777 -pe 's/ddd[sS]*//' file

perl -i -0777 -pe 's/ddd.*//s' file

share|improve this answer

edited Oct 1 at 12:40

answered Sep 30 at 15:57

user3140225user3140225

2,71044 gold badges1212 silver badges2424 bronze badges

answered Sep 30 at 15:57

user3140225user3140225

2,71044 gold badges1212 silver badges2424 bronze badges

answered Sep 30 at 15:57

user3140225user3140225

2,71044 gold badges1212 silver badges2424 bronze badges

4

with GNU awk, we can do:

awk 'function output() print >>FILENAME".out" 
 /ddd/ sub(/ddd.*/,""); output(); nextfile 
 output() ' file[12]

to change inplace, which it makes command even simple:

gawk -i inplace '/ddd/ sub(/ddd.*/,""); print ; nextfile 1' file[12]

share|improve this answer

edited Oct 1 at 10:05

answered Sep 30 at 15:39

αғsнιηαғsнιη

28.8k2323 gold badges107107 silver badges170170 bronze badges

add a comment
 | 

4

with GNU awk, we can do:

awk 'function output() print >>FILENAME".out" 
 /ddd/ sub(/ddd.*/,""); output(); nextfile 
 output() ' file[12]

to change inplace, which it makes command even simple:

gawk -i inplace '/ddd/ sub(/ddd.*/,""); print ; nextfile 1' file[12]

share|improve this answer

edited Oct 1 at 10:05

answered Sep 30 at 15:39

αғsнιηαғsнιη

28.8k2323 gold badges107107 silver badges170170 bronze badges

add a comment
 | 

with GNU awk, we can do:

awk 'function output() print >>FILENAME".out" 
 /ddd/ sub(/ddd.*/,""); output(); nextfile 
 output() ' file[12]

to change inplace, which it makes command even simple:

gawk -i inplace '/ddd/ sub(/ddd.*/,""); print ; nextfile 1' file[12]

share|improve this answer

edited Oct 1 at 10:05

answered Sep 30 at 15:39

αғsнιηαғsнιη

28.8k2323 gold badges107107 silver badges170170 bronze badges

awk 'function output() print >>FILENAME".out" 
 /ddd/ sub(/ddd.*/,""); output(); nextfile 
 output() ' file[12]

gawk -i inplace '/ddd/ sub(/ddd.*/,""); print ; nextfile 1' file[12]

share|improve this answer

edited Oct 1 at 10:05

answered Sep 30 at 15:39

αғsнιηαғsнιη

28.8k2323 gold badges107107 silver badges170170 bronze badges

answered Sep 30 at 15:39

αғsнιηαғsнιη

28.8k2323 gold badges107107 silver badges170170 bronze badges

answered Sep 30 at 15:39

αғsнιηαғsнιη

28.8k2323 gold badges107107 silver badges170170 bronze badges