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Plot, sampling, and why it does not display for some ranges
Why does plot not show where Piecewise function is not zero?Problem with Piecewise functionPlot does not plot over the specified rangeHow specify PlotRange and display bitmap over plot in DateListPlot?How to plot the contour of f[x,y]==0 if always f[x,y]>=0Why does piecewise plot have a discontinuity when the function, first and second derivatives are equal?Can I make a smooth contour plot with Mathematica?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty
margin-bottom:0;
.everyonelovesstackoverflowposition:absolute;height:1px;width:1px;opacity:0;top:0;left:0;pointer-events:none;
$begingroup$
The following gives an empty plot on V12 under Windows 10:
f[x_, n_] := Piecewise[1, n < x < n + 1, 0, True]
Plot[f[x, 7], x, -30, 30 , PlotRange -> All, -1, 1, Exclusions -> None]
Changing the range to make it little smaller, now shows it as:
Plot[f[x, 7], x, -20, 20 , PlotRange -> All, -1, 1, Exclusions -> None]
Also increasing Plot points and using the longer range, it now shows as:
Plot[f[x, 7], x, -30, 30 , PlotRange -> All, -1, 1,
Exclusions -> None, PlotPoints -> 20]
OK, so I thought I needed more PlotPoints and that was all. But changing f[x, 7] to f[x,8] now shows it using the longer range and without changing the PlotPints:
Plot[f[x, 8], x, -30, 30 , PlotRange -> All, -1, 1, Exclusions -> None]
So there must be something else. It can't be the PlotPoints. Why would f[x, 7] need more points than f[x,8]?
The function only generates this:
Table[f[x, 7], x, 7, 8, .1]
Table[f[x, 8], x, 8, 9, .1]
BTW, this has nothing to do with odd or even numbers. It seems random. For example,
Plot[f[x, 2], x, -30, 30, PlotRange -> All, -1, 1, Exclusions -> None]
It also gives an empty plot.
The sampling algorithm for Plot seems to miss all the points from f[x, 7], but not from f[x, 8]. Why is that?
plotting sampling
edited Sep 30 at 15:56
Peter Mortensen
3622 silver badges7 bronze badges
asked Sep 30 at 2:24
NasserNasser
73k4 gold badges95 silver badges220 bronze badges
$endgroup$
add a comment
|
$begingroup$
The following gives an empty plot on V12 under Windows 10:
f[x_, n_] := Piecewise[1, n < x < n + 1, 0, True]
Plot[f[x, 7], x, -30, 30 , PlotRange -> All, -1, 1, Exclusions -> None]
Changing the range to make it little smaller, now shows it as:
Plot[f[x, 7], x, -20, 20 , PlotRange -> All, -1, 1, Exclusions -> None]
Also increasing Plot points and using the longer range, it now shows as:
Plot[f[x, 7], x, -30, 30 , PlotRange -> All, -1, 1,
Exclusions -> None, PlotPoints -> 20]
OK, so I thought I needed more PlotPoints and that was all. But changing f[x, 7] to f[x,8] now shows it using the longer range and without changing the PlotPints:
Plot[f[x, 8], x, -30, 30 , PlotRange -> All, -1, 1, Exclusions -> None]
So there must be something else. It can't be the PlotPoints. Why would f[x, 7] need more points than f[x,8]?
The function only generates this:
Table[f[x, 7], x, 7, 8, .1]
Table[f[x, 8], x, 8, 9, .1]
BTW, this has nothing to do with odd or even numbers. It seems random. For example,
Plot[f[x, 2], x, -30, 30, PlotRange -> All, -1, 1, Exclusions -> None]
It also gives an empty plot.
The sampling algorithm for Plot seems to miss all the points from f[x, 7], but not from f[x, 8]. Why is that?
plotting sampling
edited Sep 30 at 15:56
Peter Mortensen
3622 silver badges7 bronze badges
asked Sep 30 at 2:24
NasserNasser
73k4 gold badges95 silver badges220 bronze badges
$endgroup$
$begingroup$
Related: mathematica.stackexchange.com/q/182993/1871 There should be more.
$endgroup$
– xzczd
Sep 30 at 4:40
add a comment
|
$begingroup$
The following gives an empty plot on V12 under Windows 10:
f[x_, n_] := Piecewise[1, n < x < n + 1, 0, True]
Plot[f[x, 7], x, -30, 30 , PlotRange -> All, -1, 1, Exclusions -> None]
Changing the range to make it little smaller, now shows it as:
Plot[f[x, 7], x, -20, 20 , PlotRange -> All, -1, 1, Exclusions -> None]
Also increasing Plot points and using the longer range, it now shows as:
Plot[f[x, 7], x, -30, 30 , PlotRange -> All, -1, 1,
Exclusions -> None, PlotPoints -> 20]
OK, so I thought I needed more PlotPoints and that was all. But changing f[x, 7] to f[x,8] now shows it using the longer range and without changing the PlotPints:
Plot[f[x, 8], x, -30, 30 , PlotRange -> All, -1, 1, Exclusions -> None]
So there must be something else. It can't be the PlotPoints. Why would f[x, 7] need more points than f[x,8]?
The function only generates this:
Table[f[x, 7], x, 7, 8, .1]
Table[f[x, 8], x, 8, 9, .1]
BTW, this has nothing to do with odd or even numbers. It seems random. For example,
Plot[f[x, 2], x, -30, 30, PlotRange -> All, -1, 1, Exclusions -> None]
It also gives an empty plot.
The sampling algorithm for Plot seems to miss all the points from f[x, 7], but not from f[x, 8]. Why is that?
plotting sampling
edited Sep 30 at 15:56
Peter Mortensen
3622 silver badges7 bronze badges
asked Sep 30 at 2:24
NasserNasser
73k4 gold badges95 silver badges220 bronze badges
$endgroup$
The following gives an empty plot on V12 under Windows 10:
f[x_, n_] := Piecewise[1, n < x < n + 1, 0, True]
Plot[f[x, 7], x, -30, 30 , PlotRange -> All, -1, 1, Exclusions -> None]
Changing the range to make it little smaller, now shows it as:
Plot[f[x, 7], x, -20, 20 , PlotRange -> All, -1, 1, Exclusions -> None]
Also increasing Plot points and using the longer range, it now shows as:
Plot[f[x, 7], x, -30, 30 , PlotRange -> All, -1, 1,
Exclusions -> None, PlotPoints -> 20]
OK, so I thought I needed more PlotPoints and that was all. But changing f[x, 7] to f[x,8] now shows it using the longer range and without changing the PlotPints:
Plot[f[x, 8], x, -30, 30 , PlotRange -> All, -1, 1, Exclusions -> None]
So there must be something else. It can't be the PlotPoints. Why would f[x, 7] need more points than f[x,8]?
The function only generates this:
Table[f[x, 7], x, 7, 8, .1]
Table[f[x, 8], x, 8, 9, .1]
BTW, this has nothing to do with odd or even numbers. It seems random. For example,
Plot[f[x, 2], x, -30, 30, PlotRange -> All, -1, 1, Exclusions -> None]
It also gives an empty plot.
The sampling algorithm for Plot seems to miss all the points from f[x, 7], but not from f[x, 8]. Why is that?
plotting sampling
plotting sampling
edited Sep 30 at 15:56
Peter Mortensen
3622 silver badges7 bronze badges
asked Sep 30 at 2:24
NasserNasser
73k4 gold badges95 silver badges220 bronze badges
edited Sep 30 at 15:56
Peter Mortensen
3622 silver badges7 bronze badges
asked Sep 30 at 2:24
NasserNasser
73k4 gold badges95 silver badges220 bronze badges
edited Sep 30 at 15:56
Peter Mortensen
3622 silver badges7 bronze badges
edited Sep 30 at 15:56
Peter Mortensen
3622 silver badges7 bronze badges
edited Sep 30 at 15:56
Peter Mortensen
3622 silver badges7 bronze badges
3622 silver badges7 bronze badges
asked Sep 30 at 2:24
NasserNasser
73k4 gold badges95 silver badges220 bronze badges
asked Sep 30 at 2:24
NasserNasser
73k4 gold badges95 silver badges220 bronze badges
asked Sep 30 at 2:24
NasserNasser
73k4 gold badges95 silver badges220 bronze badges
73k4 gold badges95 silver badges220 bronze badges
$begingroup$
Related: mathematica.stackexchange.com/q/182993/1871 There should be more.
$endgroup$
– xzczd
Sep 30 at 4:40
add a comment
|
$begingroup$
Related: mathematica.stackexchange.com/q/182993/1871 There should be more.
$endgroup$
– xzczd
Sep 30 at 4:40
$begingroup$
Related: mathematica.stackexchange.com/q/182993/1871 There should be more.
$endgroup$
– xzczd
Sep 30 at 4:40
$begingroup$
Related: mathematica.stackexchange.com/q/182993/1871 There should be more.
$endgroup$
– xzczd
Sep 30 at 4:40
add a comment
|
2 Answers
2
active
oldest
votes
$begingroup$
Your plots aren't empty: they have a line along the x axis.
Plot uses PlotPoints -> 50 by default, and since you go from -30 to 30, there will be some $n$ to $n+1$ intervals that don't get sampled:
In[66]:= Reap[
Plot[x, x, -30, 30, MaxRecursion -> 0,
EvaluationMonitor :> Sow[x]];]
Out[66]= Null, -30., -28.8223, -27.5455, -26.3533, -25.1845,
-23.9167, -22.7335, -21.4512, -20.1922, -19.0179, -17.7446, -16.5558,
-15.3904, -14.126, -12.9462, -11.6673, -10.4118, -9.24087, -7.97091,
-6.78556, -5.50115, -4.24013, -3.06371, -1.78823, -0.597365, 0.570117,
1.83666, 3.0186, 4.2996, 5.55721, 6.73021, 8.00228, 9.18974,
10.3538, 11.6169, 12.7955, 14.0731, 15.266, 16.4356, 17.7043,
18.8883, 20.1714, 21.4312, 22.6063, 23.8804, 25.07, 26.2362,
27.5014, 28.6821, 30.
7 to 8, corresponding to f[x, 7] is one such interval. Since we don't sample between those values, we never see f[x,7] == 1 and the resulting plot is zero everywhere.
answered Sep 30 at 4:23
Brett ChampionBrett Champion
18.4k2 gold badges52 silver badges118 bronze badges
$endgroup$
$begingroup$
But this does not really explain why it shows the pulse when using other values ofnfor same range and same plot points? For examplef[x, 2]it misses it, butf[x, 8]it does not. Same range. So is it hit and miss type of thing? ps. I know the plot is not empty, (I see the line y=0 there) I was lazy :) and just meant the pulse itself is not showing. I should be more clear.
$endgroup$
– Nasser
Sep 30 at 4:48
4
$begingroup$
@Nasser Essentially, you see the pulse if the initial set of sampling points ofPlotcontains the pulse (if not,Plothas no reason to increase the sampling). If you look at the sampled points, you'll see that there are no points in $[2,3],[7,8],[13,14],[19,20],[24,25],[29,30]$, so if the pulse is in any of those intervals,Plotwill miss it, otherwise it will find it
$endgroup$
– Lukas Lang
Sep 30 at 12:45
add a comment
|
$begingroup$
Brett's answer explains the why.
To force sampling at specified points you can use an undocumented form of PlotPoints (see this answer by Ullrich Neumann) :
f[x_, n_] := Piecewise[1, n < x < n + 1, 0, True]
Plot[f[x, 7], x, -30, 30,
PlotPoints -> 50, 7,
PlotStyle -> CapForm["Butt"],
Axes -> False, Frame -> True,
PlotRange -> -1, 1,
PlotRangePadding -> Scaled[.05]]
Add Exclusions -> None to get the vertical portions:
answered Sep 30 at 15:28
kglrkglr
229k10 gold badges259 silver badges523 bronze badges
$endgroup$
add a comment
|
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Your plots aren't empty: they have a line along the x axis.
Plot uses PlotPoints -> 50 by default, and since you go from -30 to 30, there will be some $n$ to $n+1$ intervals that don't get sampled:
In[66]:= Reap[
Plot[x, x, -30, 30, MaxRecursion -> 0,
EvaluationMonitor :> Sow[x]];]
Out[66]= Null, -30., -28.8223, -27.5455, -26.3533, -25.1845,
-23.9167, -22.7335, -21.4512, -20.1922, -19.0179, -17.7446, -16.5558,
-15.3904, -14.126, -12.9462, -11.6673, -10.4118, -9.24087, -7.97091,
-6.78556, -5.50115, -4.24013, -3.06371, -1.78823, -0.597365, 0.570117,
1.83666, 3.0186, 4.2996, 5.55721, 6.73021, 8.00228, 9.18974,
10.3538, 11.6169, 12.7955, 14.0731, 15.266, 16.4356, 17.7043,
18.8883, 20.1714, 21.4312, 22.6063, 23.8804, 25.07, 26.2362,
27.5014, 28.6821, 30.
7 to 8, corresponding to f[x, 7] is one such interval. Since we don't sample between those values, we never see f[x,7] == 1 and the resulting plot is zero everywhere.
answered Sep 30 at 4:23
Brett ChampionBrett Champion
18.4k2 gold badges52 silver badges118 bronze badges
$endgroup$
$begingroup$
But this does not really explain why it shows the pulse when using other values ofnfor same range and same plot points? For examplef[x, 2]it misses it, butf[x, 8]it does not. Same range. So is it hit and miss type of thing? ps. I know the plot is not empty, (I see the line y=0 there) I was lazy :) and just meant the pulse itself is not showing. I should be more clear.
$endgroup$
– Nasser
Sep 30 at 4:48
4
$begingroup$
@Nasser Essentially, you see the pulse if the initial set of sampling points ofPlotcontains the pulse (if not,Plothas no reason to increase the sampling). If you look at the sampled points, you'll see that there are no points in $[2,3],[7,8],[13,14],[19,20],[24,25],[29,30]$, so if the pulse is in any of those intervals,Plotwill miss it, otherwise it will find it
$endgroup$
– Lukas Lang
Sep 30 at 12:45
add a comment
|
$begingroup$
Your plots aren't empty: they have a line along the x axis.
Plot uses PlotPoints -> 50 by default, and since you go from -30 to 30, there will be some $n$ to $n+1$ intervals that don't get sampled:
In[66]:= Reap[
Plot[x, x, -30, 30, MaxRecursion -> 0,
EvaluationMonitor :> Sow[x]];]
Out[66]= Null, -30., -28.8223, -27.5455, -26.3533, -25.1845,
-23.9167, -22.7335, -21.4512, -20.1922, -19.0179, -17.7446, -16.5558,
-15.3904, -14.126, -12.9462, -11.6673, -10.4118, -9.24087, -7.97091,
-6.78556, -5.50115, -4.24013, -3.06371, -1.78823, -0.597365, 0.570117,
1.83666, 3.0186, 4.2996, 5.55721, 6.73021, 8.00228, 9.18974,
10.3538, 11.6169, 12.7955, 14.0731, 15.266, 16.4356, 17.7043,
18.8883, 20.1714, 21.4312, 22.6063, 23.8804, 25.07, 26.2362,
27.5014, 28.6821, 30.
7 to 8, corresponding to f[x, 7] is one such interval. Since we don't sample between those values, we never see f[x,7] == 1 and the resulting plot is zero everywhere.
answered Sep 30 at 4:23
Brett ChampionBrett Champion
18.4k2 gold badges52 silver badges118 bronze badges
$endgroup$
$begingroup$
But this does not really explain why it shows the pulse when using other values ofnfor same range and same plot points? For examplef[x, 2]it misses it, butf[x, 8]it does not. Same range. So is it hit and miss type of thing? ps. I know the plot is not empty, (I see the line y=0 there) I was lazy :) and just meant the pulse itself is not showing. I should be more clear.
$endgroup$
– Nasser
Sep 30 at 4:48
4
$begingroup$
@Nasser Essentially, you see the pulse if the initial set of sampling points ofPlotcontains the pulse (if not,Plothas no reason to increase the sampling). If you look at the sampled points, you'll see that there are no points in $[2,3],[7,8],[13,14],[19,20],[24,25],[29,30]$, so if the pulse is in any of those intervals,Plotwill miss it, otherwise it will find it
$endgroup$
– Lukas Lang
Sep 30 at 12:45
add a comment
|
$begingroup$
Your plots aren't empty: they have a line along the x axis.
Plot uses PlotPoints -> 50 by default, and since you go from -30 to 30, there will be some $n$ to $n+1$ intervals that don't get sampled:
In[66]:= Reap[
Plot[x, x, -30, 30, MaxRecursion -> 0,
EvaluationMonitor :> Sow[x]];]
Out[66]= Null, -30., -28.8223, -27.5455, -26.3533, -25.1845,
-23.9167, -22.7335, -21.4512, -20.1922, -19.0179, -17.7446, -16.5558,
-15.3904, -14.126, -12.9462, -11.6673, -10.4118, -9.24087, -7.97091,
-6.78556, -5.50115, -4.24013, -3.06371, -1.78823, -0.597365, 0.570117,
1.83666, 3.0186, 4.2996, 5.55721, 6.73021, 8.00228, 9.18974,
10.3538, 11.6169, 12.7955, 14.0731, 15.266, 16.4356, 17.7043,
18.8883, 20.1714, 21.4312, 22.6063, 23.8804, 25.07, 26.2362,
27.5014, 28.6821, 30.
7 to 8, corresponding to f[x, 7] is one such interval. Since we don't sample between those values, we never see f[x,7] == 1 and the resulting plot is zero everywhere.
answered Sep 30 at 4:23
Brett ChampionBrett Champion
18.4k2 gold badges52 silver badges118 bronze badges
$endgroup$
Your plots aren't empty: they have a line along the x axis.
Plot uses PlotPoints -> 50 by default, and since you go from -30 to 30, there will be some $n$ to $n+1$ intervals that don't get sampled:
In[66]:= Reap[
Plot[x, x, -30, 30, MaxRecursion -> 0,
EvaluationMonitor :> Sow[x]];]
Out[66]= Null, -30., -28.8223, -27.5455, -26.3533, -25.1845,
-23.9167, -22.7335, -21.4512, -20.1922, -19.0179, -17.7446, -16.5558,
-15.3904, -14.126, -12.9462, -11.6673, -10.4118, -9.24087, -7.97091,
-6.78556, -5.50115, -4.24013, -3.06371, -1.78823, -0.597365, 0.570117,
1.83666, 3.0186, 4.2996, 5.55721, 6.73021, 8.00228, 9.18974,
10.3538, 11.6169, 12.7955, 14.0731, 15.266, 16.4356, 17.7043,
18.8883, 20.1714, 21.4312, 22.6063, 23.8804, 25.07, 26.2362,
27.5014, 28.6821, 30.
7 to 8, corresponding to f[x, 7] is one such interval. Since we don't sample between those values, we never see f[x,7] == 1 and the resulting plot is zero everywhere.
answered Sep 30 at 4:23
Brett ChampionBrett Champion
18.4k2 gold badges52 silver badges118 bronze badges
answered Sep 30 at 4:23
Brett ChampionBrett Champion
18.4k2 gold badges52 silver badges118 bronze badges
answered Sep 30 at 4:23
Brett ChampionBrett Champion
18.4k2 gold badges52 silver badges118 bronze badges
answered Sep 30 at 4:23
Brett ChampionBrett Champion
18.4k2 gold badges52 silver badges118 bronze badges
18.4k2 gold badges52 silver badges118 bronze badges
$begingroup$
But this does not really explain why it shows the pulse when using other values ofnfor same range and same plot points? For examplef[x, 2]it misses it, butf[x, 8]it does not. Same range. So is it hit and miss type of thing? ps. I know the plot is not empty, (I see the line y=0 there) I was lazy :) and just meant the pulse itself is not showing. I should be more clear.
$endgroup$
– Nasser
Sep 30 at 4:48
4
$begingroup$
@Nasser Essentially, you see the pulse if the initial set of sampling points ofPlotcontains the pulse (if not,Plothas no reason to increase the sampling). If you look at the sampled points, you'll see that there are no points in $[2,3],[7,8],[13,14],[19,20],[24,25],[29,30]$, so if the pulse is in any of those intervals,Plotwill miss it, otherwise it will find it
$endgroup$
– Lukas Lang
Sep 30 at 12:45
add a comment
|
$begingroup$
But this does not really explain why it shows the pulse when using other values ofnfor same range and same plot points? For examplef[x, 2]it misses it, butf[x, 8]it does not. Same range. So is it hit and miss type of thing? ps. I know the plot is not empty, (I see the line y=0 there) I was lazy :) and just meant the pulse itself is not showing. I should be more clear.
$endgroup$
– Nasser
Sep 30 at 4:48
4
$begingroup$
@Nasser Essentially, you see the pulse if the initial set of sampling points ofPlotcontains the pulse (if not,Plothas no reason to increase the sampling). If you look at the sampled points, you'll see that there are no points in $[2,3],[7,8],[13,14],[19,20],[24,25],[29,30]$, so if the pulse is in any of those intervals,Plotwill miss it, otherwise it will find it
$endgroup$
– Lukas Lang
Sep 30 at 12:45
$begingroup$
But this does not really explain why it shows the pulse when using other values of
n for same range and same plot points? For example f[x, 2] it misses it, but f[x, 8] it does not. Same range. So is it hit and miss type of thing? ps. I know the plot is not empty, (I see the line y=0 there) I was lazy :) and just meant the pulse itself is not showing. I should be more clear.$endgroup$
– Nasser
Sep 30 at 4:48
$begingroup$
But this does not really explain why it shows the pulse when using other values of
n for same range and same plot points? For example f[x, 2] it misses it, but f[x, 8] it does not. Same range. So is it hit and miss type of thing? ps. I know the plot is not empty, (I see the line y=0 there) I was lazy :) and just meant the pulse itself is not showing. I should be more clear.$endgroup$
– Nasser
Sep 30 at 4:48
4
4
$begingroup$
@Nasser Essentially, you see the pulse if the initial set of sampling points of
Plot contains the pulse (if not, Plot has no reason to increase the sampling). If you look at the sampled points, you'll see that there are no points in $[2,3],[7,8],[13,14],[19,20],[24,25],[29,30]$, so if the pulse is in any of those intervals, Plot will miss it, otherwise it will find it$endgroup$
– Lukas Lang
Sep 30 at 12:45
$begingroup$
@Nasser Essentially, you see the pulse if the initial set of sampling points of
Plot contains the pulse (if not, Plot has no reason to increase the sampling). If you look at the sampled points, you'll see that there are no points in $[2,3],[7,8],[13,14],[19,20],[24,25],[29,30]$, so if the pulse is in any of those intervals, Plot will miss it, otherwise it will find it$endgroup$
– Lukas Lang
Sep 30 at 12:45
add a comment
|
$begingroup$
Brett's answer explains the why.
To force sampling at specified points you can use an undocumented form of PlotPoints (see this answer by Ullrich Neumann) :
f[x_, n_] := Piecewise[1, n < x < n + 1, 0, True]
Plot[f[x, 7], x, -30, 30,
PlotPoints -> 50, 7,
PlotStyle -> CapForm["Butt"],
Axes -> False, Frame -> True,
PlotRange -> -1, 1,
PlotRangePadding -> Scaled[.05]]
Add Exclusions -> None to get the vertical portions:
answered Sep 30 at 15:28
kglrkglr
229k10 gold badges259 silver badges523 bronze badges
$endgroup$
add a comment
|
$begingroup$
Brett's answer explains the why.
To force sampling at specified points you can use an undocumented form of PlotPoints (see this answer by Ullrich Neumann) :
f[x_, n_] := Piecewise[1, n < x < n + 1, 0, True]
Plot[f[x, 7], x, -30, 30,
PlotPoints -> 50, 7,
PlotStyle -> CapForm["Butt"],
Axes -> False, Frame -> True,
PlotRange -> -1, 1,
PlotRangePadding -> Scaled[.05]]
Add Exclusions -> None to get the vertical portions:
answered Sep 30 at 15:28
kglrkglr
229k10 gold badges259 silver badges523 bronze badges
$endgroup$
add a comment
|
$begingroup$
Brett's answer explains the why.
To force sampling at specified points you can use an undocumented form of PlotPoints (see this answer by Ullrich Neumann) :
f[x_, n_] := Piecewise[1, n < x < n + 1, 0, True]
Plot[f[x, 7], x, -30, 30,
PlotPoints -> 50, 7,
PlotStyle -> CapForm["Butt"],
Axes -> False, Frame -> True,
PlotRange -> -1, 1,
PlotRangePadding -> Scaled[.05]]
Add Exclusions -> None to get the vertical portions:
answered Sep 30 at 15:28
kglrkglr
229k10 gold badges259 silver badges523 bronze badges
$endgroup$
Brett's answer explains the why.
To force sampling at specified points you can use an undocumented form of PlotPoints (see this answer by Ullrich Neumann) :
f[x_, n_] := Piecewise[1, n < x < n + 1, 0, True]
Plot[f[x, 7], x, -30, 30,
PlotPoints -> 50, 7,
PlotStyle -> CapForm["Butt"],
Axes -> False, Frame -> True,
PlotRange -> -1, 1,
PlotRangePadding -> Scaled[.05]]
Add Exclusions -> None to get the vertical portions:
answered Sep 30 at 15:28
kglrkglr
229k10 gold badges259 silver badges523 bronze badges
edited Sep 30 at 15:34
answered Sep 30 at 15:28
kglrkglr
229k10 gold badges259 silver badges523 bronze badges
answered Sep 30 at 15:28
kglrkglr
229k10 gold badges259 silver badges523 bronze badges
answered Sep 30 at 15:28
kglrkglr
229k10 gold badges259 silver badges523 bronze badges
229k10 gold badges259 silver badges523 bronze badges
add a comment
|
add a comment
|
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$begingroup$
Related: mathematica.stackexchange.com/q/182993/1871 There should be more.
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– xzczd
Sep 30 at 4:40