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How much current can Baofeng UV-5R provide on +V pin?


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7














$begingroup$


I noticed that the pinout for cheap Baofeng connectors has +V available. I'm interested in powering some electronics directly from this connector.



When unloaded, this seems to have about 3.3V on it, but when I try to power my load (an ESP32), the voltage drops to 0.8V.



How much current can this pin actually provide without significant voltage drop? Or, what does the voltage/current curve look like?










share|improve this question










$endgroup$










  • 1




    $begingroup$
    Have you measured the current draw of your ESP32 to rule out a fault?
    $endgroup$
    – Phil Frost - W8II
    May 29 at 17:42






  • 3




    $begingroup$
    The voltage is probably meant to bias an electret microphone, so I wouldn't be surprised to hear that that terminal can't source much current.
    $endgroup$
    – rclocher3
    May 29 at 19:48










  • $begingroup$
    3.3v is a common level for logic signals in electronics. This page linked in the other question seems to indicate V+ can be used for PTT 2 - is that not the case?
    $endgroup$
    – JPhi1618
    May 30 at 18:16

















7














$begingroup$


I noticed that the pinout for cheap Baofeng connectors has +V available. I'm interested in powering some electronics directly from this connector.



When unloaded, this seems to have about 3.3V on it, but when I try to power my load (an ESP32), the voltage drops to 0.8V.



How much current can this pin actually provide without significant voltage drop? Or, what does the voltage/current curve look like?










share|improve this question










$endgroup$










  • 1




    $begingroup$
    Have you measured the current draw of your ESP32 to rule out a fault?
    $endgroup$
    – Phil Frost - W8II
    May 29 at 17:42






  • 3




    $begingroup$
    The voltage is probably meant to bias an electret microphone, so I wouldn't be surprised to hear that that terminal can't source much current.
    $endgroup$
    – rclocher3
    May 29 at 19:48










  • $begingroup$
    3.3v is a common level for logic signals in electronics. This page linked in the other question seems to indicate V+ can be used for PTT 2 - is that not the case?
    $endgroup$
    – JPhi1618
    May 30 at 18:16













7












7








7


1



$begingroup$


I noticed that the pinout for cheap Baofeng connectors has +V available. I'm interested in powering some electronics directly from this connector.



When unloaded, this seems to have about 3.3V on it, but when I try to power my load (an ESP32), the voltage drops to 0.8V.



How much current can this pin actually provide without significant voltage drop? Or, what does the voltage/current curve look like?










share|improve this question










$endgroup$




I noticed that the pinout for cheap Baofeng connectors has +V available. I'm interested in powering some electronics directly from this connector.



When unloaded, this seems to have about 3.3V on it, but when I try to power my load (an ESP32), the voltage drops to 0.8V.



How much current can this pin actually provide without significant voltage drop? Or, what does the voltage/current curve look like?







baofeng audio-interface






share|improve this question














share|improve this question











share|improve this question




share|improve this question










asked May 29 at 17:10









Evan KrallEvan Krall

2211 silver badge4 bronze badges




2211 silver badge4 bronze badges










  • 1




    $begingroup$
    Have you measured the current draw of your ESP32 to rule out a fault?
    $endgroup$
    – Phil Frost - W8II
    May 29 at 17:42






  • 3




    $begingroup$
    The voltage is probably meant to bias an electret microphone, so I wouldn't be surprised to hear that that terminal can't source much current.
    $endgroup$
    – rclocher3
    May 29 at 19:48










  • $begingroup$
    3.3v is a common level for logic signals in electronics. This page linked in the other question seems to indicate V+ can be used for PTT 2 - is that not the case?
    $endgroup$
    – JPhi1618
    May 30 at 18:16












  • 1




    $begingroup$
    Have you measured the current draw of your ESP32 to rule out a fault?
    $endgroup$
    – Phil Frost - W8II
    May 29 at 17:42






  • 3




    $begingroup$
    The voltage is probably meant to bias an electret microphone, so I wouldn't be surprised to hear that that terminal can't source much current.
    $endgroup$
    – rclocher3
    May 29 at 19:48










  • $begingroup$
    3.3v is a common level for logic signals in electronics. This page linked in the other question seems to indicate V+ can be used for PTT 2 - is that not the case?
    $endgroup$
    – JPhi1618
    May 30 at 18:16







1




1




$begingroup$
Have you measured the current draw of your ESP32 to rule out a fault?
$endgroup$
– Phil Frost - W8II
May 29 at 17:42




$begingroup$
Have you measured the current draw of your ESP32 to rule out a fault?
$endgroup$
– Phil Frost - W8II
May 29 at 17:42




3




3




$begingroup$
The voltage is probably meant to bias an electret microphone, so I wouldn't be surprised to hear that that terminal can't source much current.
$endgroup$
– rclocher3
May 29 at 19:48




$begingroup$
The voltage is probably meant to bias an electret microphone, so I wouldn't be surprised to hear that that terminal can't source much current.
$endgroup$
– rclocher3
May 29 at 19:48












$begingroup$
3.3v is a common level for logic signals in electronics. This page linked in the other question seems to indicate V+ can be used for PTT 2 - is that not the case?
$endgroup$
– JPhi1618
May 30 at 18:16




$begingroup$
3.3v is a common level for logic signals in electronics. This page linked in the other question seems to indicate V+ can be used for PTT 2 - is that not the case?
$endgroup$
– JPhi1618
May 30 at 18:16










2 Answers
2






active

oldest

votes


















7
















$begingroup$

I would first measure the current draw of your ESP32 to rule out a fault there.



The +V pin on the Baofeng microphone connection is probably intended to bias an electret microphone. These are essentially a capacitor, with sound pressure changing the spacing between the plates and thus the voltage. They contain a FET buffer since the capacitor could not drive a cable directly. The buffer requires power, but very little: the bias current is probably far less than 1 mA.



Thus it's quite likely the +V pin is unable to supply even a small current. Adding a series resistance on such a pin would have no impact to the intended use of biasing a microphone, but is a cheap and effective way to protect the radio from all kinds of faults that could happen on such a connector.






share|improve this answer










$endgroup$














  • $begingroup$
    Almost certainly an electret mic. The only other possibility would be for the PTT; pressing it might feed 3.3 volts back to the main board.
    $endgroup$
    – Mike Waters
    May 30 at 15:39



















7
















$begingroup$

  • With no load, I measure 3.17V

  • With 100kΩ load, 2.91V

  • With 10kΩ load, 1.59V

  • With 1kΩ load, 0.29V

The math works out to a 10kΩ series resistance between +V and ground.



As such the maximum power that can be drawn is at 1.59V/10kΩ load, or 0.25mW max power. Short circuit current would be about 0.3mA.






share|improve this answer












$endgroup$
















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    2 Answers
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    oldest

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    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    7
















    $begingroup$

    I would first measure the current draw of your ESP32 to rule out a fault there.



    The +V pin on the Baofeng microphone connection is probably intended to bias an electret microphone. These are essentially a capacitor, with sound pressure changing the spacing between the plates and thus the voltage. They contain a FET buffer since the capacitor could not drive a cable directly. The buffer requires power, but very little: the bias current is probably far less than 1 mA.



    Thus it's quite likely the +V pin is unable to supply even a small current. Adding a series resistance on such a pin would have no impact to the intended use of biasing a microphone, but is a cheap and effective way to protect the radio from all kinds of faults that could happen on such a connector.






    share|improve this answer










    $endgroup$














    • $begingroup$
      Almost certainly an electret mic. The only other possibility would be for the PTT; pressing it might feed 3.3 volts back to the main board.
      $endgroup$
      – Mike Waters
      May 30 at 15:39
















    7
















    $begingroup$

    I would first measure the current draw of your ESP32 to rule out a fault there.



    The +V pin on the Baofeng microphone connection is probably intended to bias an electret microphone. These are essentially a capacitor, with sound pressure changing the spacing between the plates and thus the voltage. They contain a FET buffer since the capacitor could not drive a cable directly. The buffer requires power, but very little: the bias current is probably far less than 1 mA.



    Thus it's quite likely the +V pin is unable to supply even a small current. Adding a series resistance on such a pin would have no impact to the intended use of biasing a microphone, but is a cheap and effective way to protect the radio from all kinds of faults that could happen on such a connector.






    share|improve this answer










    $endgroup$














    • $begingroup$
      Almost certainly an electret mic. The only other possibility would be for the PTT; pressing it might feed 3.3 volts back to the main board.
      $endgroup$
      – Mike Waters
      May 30 at 15:39














    7














    7










    7







    $begingroup$

    I would first measure the current draw of your ESP32 to rule out a fault there.



    The +V pin on the Baofeng microphone connection is probably intended to bias an electret microphone. These are essentially a capacitor, with sound pressure changing the spacing between the plates and thus the voltage. They contain a FET buffer since the capacitor could not drive a cable directly. The buffer requires power, but very little: the bias current is probably far less than 1 mA.



    Thus it's quite likely the +V pin is unable to supply even a small current. Adding a series resistance on such a pin would have no impact to the intended use of biasing a microphone, but is a cheap and effective way to protect the radio from all kinds of faults that could happen on such a connector.






    share|improve this answer










    $endgroup$



    I would first measure the current draw of your ESP32 to rule out a fault there.



    The +V pin on the Baofeng microphone connection is probably intended to bias an electret microphone. These are essentially a capacitor, with sound pressure changing the spacing between the plates and thus the voltage. They contain a FET buffer since the capacitor could not drive a cable directly. The buffer requires power, but very little: the bias current is probably far less than 1 mA.



    Thus it's quite likely the +V pin is unable to supply even a small current. Adding a series resistance on such a pin would have no impact to the intended use of biasing a microphone, but is a cheap and effective way to protect the radio from all kinds of faults that could happen on such a connector.







    share|improve this answer













    share|improve this answer




    share|improve this answer










    answered May 29 at 22:01









    Phil Frost - W8IIPhil Frost - W8II

    32.3k1 gold badge49 silver badges127 bronze badges




    32.3k1 gold badge49 silver badges127 bronze badges














    • $begingroup$
      Almost certainly an electret mic. The only other possibility would be for the PTT; pressing it might feed 3.3 volts back to the main board.
      $endgroup$
      – Mike Waters
      May 30 at 15:39

















    • $begingroup$
      Almost certainly an electret mic. The only other possibility would be for the PTT; pressing it might feed 3.3 volts back to the main board.
      $endgroup$
      – Mike Waters
      May 30 at 15:39
















    $begingroup$
    Almost certainly an electret mic. The only other possibility would be for the PTT; pressing it might feed 3.3 volts back to the main board.
    $endgroup$
    – Mike Waters
    May 30 at 15:39





    $begingroup$
    Almost certainly an electret mic. The only other possibility would be for the PTT; pressing it might feed 3.3 volts back to the main board.
    $endgroup$
    – Mike Waters
    May 30 at 15:39














    7
















    $begingroup$

    • With no load, I measure 3.17V

    • With 100kΩ load, 2.91V

    • With 10kΩ load, 1.59V

    • With 1kΩ load, 0.29V

    The math works out to a 10kΩ series resistance between +V and ground.



    As such the maximum power that can be drawn is at 1.59V/10kΩ load, or 0.25mW max power. Short circuit current would be about 0.3mA.






    share|improve this answer












    $endgroup$



















      7
















      $begingroup$

      • With no load, I measure 3.17V

      • With 100kΩ load, 2.91V

      • With 10kΩ load, 1.59V

      • With 1kΩ load, 0.29V

      The math works out to a 10kΩ series resistance between +V and ground.



      As such the maximum power that can be drawn is at 1.59V/10kΩ load, or 0.25mW max power. Short circuit current would be about 0.3mA.






      share|improve this answer












      $endgroup$

















        7














        7










        7







        $begingroup$

        • With no load, I measure 3.17V

        • With 100kΩ load, 2.91V

        • With 10kΩ load, 1.59V

        • With 1kΩ load, 0.29V

        The math works out to a 10kΩ series resistance between +V and ground.



        As such the maximum power that can be drawn is at 1.59V/10kΩ load, or 0.25mW max power. Short circuit current would be about 0.3mA.






        share|improve this answer












        $endgroup$



        • With no load, I measure 3.17V

        • With 100kΩ load, 2.91V

        • With 10kΩ load, 1.59V

        • With 1kΩ load, 0.29V

        The math works out to a 10kΩ series resistance between +V and ground.



        As such the maximum power that can be drawn is at 1.59V/10kΩ load, or 0.25mW max power. Short circuit current would be about 0.3mA.







        share|improve this answer















        share|improve this answer




        share|improve this answer








        edited May 30 at 21:55









        rclocher3

        3,6381 gold badge6 silver badges26 bronze badges




        3,6381 gold badge6 silver badges26 bronze badges










        answered May 30 at 2:55









        Evan KrallEvan Krall

        2211 silver badge4 bronze badges




        2211 silver badge4 bronze badges































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