Is it true that, “just ten trading days represent 63 per cent of the returns of the past 50 years”?Should a middle class person emulate a very wealthy investor for % of cash hold?What is the technical name for the type of security whose price updates once per trading day?Do common stocks and preferred stocks have any differences in terms of percentage of the company per unit they represent?Is there any data that shows how diversifying results in better returns than just sticking to an all-stock portfolio?Is it true that more than 99% of active traders cannot beat the index?Why is AT&T's stock price declining, during the days that they announced the acquisition of Time Warner inc.?How many trading days are there in the U.S stock market for the year 2016?Does news that is released during after hours trading still affect the stock the following day?The rule of thumb that if the growth of a company is 20% per year, then the P/E should be 20, what is this rule based on?

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Is it true that, “just ten trading days represent 63 per cent of the returns of the past 50 years”?


Should a middle class person emulate a very wealthy investor for % of cash hold?What is the technical name for the type of security whose price updates once per trading day?Do common stocks and preferred stocks have any differences in terms of percentage of the company per unit they represent?Is there any data that shows how diversifying results in better returns than just sticking to an all-stock portfolio?Is it true that more than 99% of active traders cannot beat the index?Why is AT&T's stock price declining, during the days that they announced the acquisition of Time Warner inc.?How many trading days are there in the U.S stock market for the year 2016?Does news that is released during after hours trading still affect the stock the following day?The rule of thumb that if the growth of a company is 20% per year, then the P/E should be 20, what is this rule based on?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty
margin-bottom:0;









54


















I have fallen down a Wikipedia rabbit hole and landed on the page titled Seven States of Randomness. I can't explain in a single sentence what it is talking about, but my question is about an odd quote at the end of the History section (with my emphasis)




Mandelbrot and Taleb pointed out that although one can assume that the
odds of finding a person who is several miles tall are extremely low,
similar excessive observations can not be excluded in other areas of
application. They argued that while traditional bell curves may
provide a satisfactory representation of height and weight in the
population, they do not provide a suitable modeling mechanism for
market risks or returns, where just ten trading days represent 63 per
cent of the returns of the past 50 years.




Is this true? Or is it even fair to ask if this is true? Does anyone know where this quote originated from or is this just the made up "fact" of whoever wrote this Wikipedia page? If it is true, is there a better less technical explanation of it somewhere?










share|improve this question






















  • 1





    Please read The Intent and Purpose of Comments. If you have a request for the OP to clarify the question or order more details, that's the purpose. 5 lengthy answers have been posted now, and they address this pretty well.

    – JTP - Apologise to Monica
    Sep 18 at 15:56







  • 1





    I have seen many claims of this nature. I suspect that most of them have done the arithmetic correctly. What it is being used for here is to claim that the normal distribution is a bad model of reality far from the mean, because events many standard deviations out are much more common than the normal distribution would claim. The normal distribution is very convenient because we have lots of theorems about what happens when things are normally distributed. As long as you stay close to the mean it doesn't matter much which

    – Ross Millikan
    Sep 20 at 2:29











  • bell shaped curve you use. When you go far out it matters a lot. In real life the tails are always greater than a normal distribution will say.

    – Ross Millikan
    Sep 20 at 2:31











  • @RossMillikan - your comments can be copied and edited to an answer. You beautifully summarize much of Taleb’s intent in his brief discussion of this phenomenon. Trying to be positive and not a comment cop.....

    – JTP - Apologise to Monica
    Sep 20 at 18:41

















54


















I have fallen down a Wikipedia rabbit hole and landed on the page titled Seven States of Randomness. I can't explain in a single sentence what it is talking about, but my question is about an odd quote at the end of the History section (with my emphasis)




Mandelbrot and Taleb pointed out that although one can assume that the
odds of finding a person who is several miles tall are extremely low,
similar excessive observations can not be excluded in other areas of
application. They argued that while traditional bell curves may
provide a satisfactory representation of height and weight in the
population, they do not provide a suitable modeling mechanism for
market risks or returns, where just ten trading days represent 63 per
cent of the returns of the past 50 years.




Is this true? Or is it even fair to ask if this is true? Does anyone know where this quote originated from or is this just the made up "fact" of whoever wrote this Wikipedia page? If it is true, is there a better less technical explanation of it somewhere?










share|improve this question






















  • 1





    Please read The Intent and Purpose of Comments. If you have a request for the OP to clarify the question or order more details, that's the purpose. 5 lengthy answers have been posted now, and they address this pretty well.

    – JTP - Apologise to Monica
    Sep 18 at 15:56







  • 1





    I have seen many claims of this nature. I suspect that most of them have done the arithmetic correctly. What it is being used for here is to claim that the normal distribution is a bad model of reality far from the mean, because events many standard deviations out are much more common than the normal distribution would claim. The normal distribution is very convenient because we have lots of theorems about what happens when things are normally distributed. As long as you stay close to the mean it doesn't matter much which

    – Ross Millikan
    Sep 20 at 2:29











  • bell shaped curve you use. When you go far out it matters a lot. In real life the tails are always greater than a normal distribution will say.

    – Ross Millikan
    Sep 20 at 2:31











  • @RossMillikan - your comments can be copied and edited to an answer. You beautifully summarize much of Taleb’s intent in his brief discussion of this phenomenon. Trying to be positive and not a comment cop.....

    – JTP - Apologise to Monica
    Sep 20 at 18:41













54













54









54


13






I have fallen down a Wikipedia rabbit hole and landed on the page titled Seven States of Randomness. I can't explain in a single sentence what it is talking about, but my question is about an odd quote at the end of the History section (with my emphasis)




Mandelbrot and Taleb pointed out that although one can assume that the
odds of finding a person who is several miles tall are extremely low,
similar excessive observations can not be excluded in other areas of
application. They argued that while traditional bell curves may
provide a satisfactory representation of height and weight in the
population, they do not provide a suitable modeling mechanism for
market risks or returns, where just ten trading days represent 63 per
cent of the returns of the past 50 years.




Is this true? Or is it even fair to ask if this is true? Does anyone know where this quote originated from or is this just the made up "fact" of whoever wrote this Wikipedia page? If it is true, is there a better less technical explanation of it somewhere?










share|improve this question
















I have fallen down a Wikipedia rabbit hole and landed on the page titled Seven States of Randomness. I can't explain in a single sentence what it is talking about, but my question is about an odd quote at the end of the History section (with my emphasis)




Mandelbrot and Taleb pointed out that although one can assume that the
odds of finding a person who is several miles tall are extremely low,
similar excessive observations can not be excluded in other areas of
application. They argued that while traditional bell curves may
provide a satisfactory representation of height and weight in the
population, they do not provide a suitable modeling mechanism for
market risks or returns, where just ten trading days represent 63 per
cent of the returns of the past 50 years.




Is this true? Or is it even fair to ask if this is true? Does anyone know where this quote originated from or is this just the made up "fact" of whoever wrote this Wikipedia page? If it is true, is there a better less technical explanation of it somewhere?







stocks stock-analysis technical-analysis






share|improve this question















share|improve this question













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share|improve this question








edited Sep 18 at 15:50









JTP - Apologise to Monica

156k25 gold badges257 silver badges500 bronze badges




156k25 gold badges257 silver badges500 bronze badges










asked Sep 17 at 19:15









KDeckerKDecker

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9281 gold badge6 silver badges9 bronze badges










  • 1





    Please read The Intent and Purpose of Comments. If you have a request for the OP to clarify the question or order more details, that's the purpose. 5 lengthy answers have been posted now, and they address this pretty well.

    – JTP - Apologise to Monica
    Sep 18 at 15:56







  • 1





    I have seen many claims of this nature. I suspect that most of them have done the arithmetic correctly. What it is being used for here is to claim that the normal distribution is a bad model of reality far from the mean, because events many standard deviations out are much more common than the normal distribution would claim. The normal distribution is very convenient because we have lots of theorems about what happens when things are normally distributed. As long as you stay close to the mean it doesn't matter much which

    – Ross Millikan
    Sep 20 at 2:29











  • bell shaped curve you use. When you go far out it matters a lot. In real life the tails are always greater than a normal distribution will say.

    – Ross Millikan
    Sep 20 at 2:31











  • @RossMillikan - your comments can be copied and edited to an answer. You beautifully summarize much of Taleb’s intent in his brief discussion of this phenomenon. Trying to be positive and not a comment cop.....

    – JTP - Apologise to Monica
    Sep 20 at 18:41












  • 1





    Please read The Intent and Purpose of Comments. If you have a request for the OP to clarify the question or order more details, that's the purpose. 5 lengthy answers have been posted now, and they address this pretty well.

    – JTP - Apologise to Monica
    Sep 18 at 15:56







  • 1





    I have seen many claims of this nature. I suspect that most of them have done the arithmetic correctly. What it is being used for here is to claim that the normal distribution is a bad model of reality far from the mean, because events many standard deviations out are much more common than the normal distribution would claim. The normal distribution is very convenient because we have lots of theorems about what happens when things are normally distributed. As long as you stay close to the mean it doesn't matter much which

    – Ross Millikan
    Sep 20 at 2:29











  • bell shaped curve you use. When you go far out it matters a lot. In real life the tails are always greater than a normal distribution will say.

    – Ross Millikan
    Sep 20 at 2:31











  • @RossMillikan - your comments can be copied and edited to an answer. You beautifully summarize much of Taleb’s intent in his brief discussion of this phenomenon. Trying to be positive and not a comment cop.....

    – JTP - Apologise to Monica
    Sep 20 at 18:41







1




1





Please read The Intent and Purpose of Comments. If you have a request for the OP to clarify the question or order more details, that's the purpose. 5 lengthy answers have been posted now, and they address this pretty well.

– JTP - Apologise to Monica
Sep 18 at 15:56






Please read The Intent and Purpose of Comments. If you have a request for the OP to clarify the question or order more details, that's the purpose. 5 lengthy answers have been posted now, and they address this pretty well.

– JTP - Apologise to Monica
Sep 18 at 15:56





1




1





I have seen many claims of this nature. I suspect that most of them have done the arithmetic correctly. What it is being used for here is to claim that the normal distribution is a bad model of reality far from the mean, because events many standard deviations out are much more common than the normal distribution would claim. The normal distribution is very convenient because we have lots of theorems about what happens when things are normally distributed. As long as you stay close to the mean it doesn't matter much which

– Ross Millikan
Sep 20 at 2:29





I have seen many claims of this nature. I suspect that most of them have done the arithmetic correctly. What it is being used for here is to claim that the normal distribution is a bad model of reality far from the mean, because events many standard deviations out are much more common than the normal distribution would claim. The normal distribution is very convenient because we have lots of theorems about what happens when things are normally distributed. As long as you stay close to the mean it doesn't matter much which

– Ross Millikan
Sep 20 at 2:29













bell shaped curve you use. When you go far out it matters a lot. In real life the tails are always greater than a normal distribution will say.

– Ross Millikan
Sep 20 at 2:31





bell shaped curve you use. When you go far out it matters a lot. In real life the tails are always greater than a normal distribution will say.

– Ross Millikan
Sep 20 at 2:31













@RossMillikan - your comments can be copied and edited to an answer. You beautifully summarize much of Taleb’s intent in his brief discussion of this phenomenon. Trying to be positive and not a comment cop.....

– JTP - Apologise to Monica
Sep 20 at 18:41





@RossMillikan - your comments can be copied and edited to an answer. You beautifully summarize much of Taleb’s intent in his brief discussion of this phenomenon. Trying to be positive and not a comment cop.....

– JTP - Apologise to Monica
Sep 20 at 18:41










9 Answers
9






active

oldest

votes


















43



















Mild vs. Wild Randomness:
Focusing on those Risks that
Matter and A focus on the exceptions
that prove the rule are copies of the original article referenced by the Wikipedia page. The authors are well respected academics so I assume that they have some support for the statement but the article doesn't appear to explain exactly what they assumed.



For a plausibility check, according to this chart the total compound increase in the S&P 500 index from 1970-01-01 to on 2018-12-31 (48 years so close to the 50 years they quote though obviously a different 50 year period) is 2622.25% (I'm using the Change in Index rather than including dividends because that requires actual research). I'm also too lazy to find a quick source of the top 60 days by percentage change since 1970 but Wikipedia does have a list of the best day each year so we can ask "If you had been invested in the S&P 500 since 1970-01-01 (ignoring dividends) but missed the best day each year, how much would you have lost overall?" If we take the best single-day returns for every year since 1970 that would produce 440.05% growth. If we exclude those 48 days, the other 364 days must have produced 467.04% growth-- (1+4.4005)*(1+4.6704)-1 = 26.2225). So (rather approximately) half the growth in the index has come from the best single day in each year which is roughly in line with the claim.



I assume that Prof. Mandelbrot and Taleb did a much more thorough analysis than I did here. Clearly they were looking at a different time period than I am, they were probably looking at a different index, they weren't limiting themselves to the data they could easily grab from Wikipedia, etc. But it's interesting that you can get reasonably close to their number doing a back of the envelope calculation using a much different data set than they were working with.



Compounding the best day of S&P 500 returns every year



Compounding the annual return of the S&P 500 since 1970






share|improve this answer





















  • 11





    @RonJohn - Percentages of percentages don't really make sense (the statement in the article isn't as precise on that point as I would prefer). The best day produced roughly the same total return as the other 364 days (440% vs 467%). If you converted that to an annualized rate of return, the best day would account for roughly half of the total growth over 50 years. My expectation is that the article was actually comparing relative annual rates of return. I'm cheating and just making a rough comparison of the two components and saying they're roughly equal.

    – Justin Cave
    Sep 18 at 3:04






  • 3





    If percentages of percentages don't really make sense, then the statement in question (which is nothing but about a percentage of a percentage) doesn't make sense.

    – RonJohn
    Sep 18 at 3:16






  • 4





    Maybe they meant, in each of the past 50 years, that year's best ten days provided 63% of that year's return, on average.

    – AakashM
    Sep 18 at 9:56






  • 4





    Possibly it is easier if you use ln-scale returns. ln(100%+X%) is the ln-scale return of an X% profit. So a 0% profit is 0 on ln-scale. 440% is 1.686, 2622% is 3.303; here, ln-scale 440% is more than half of 2622%. The difference, 1.617 is the ln-scale of 404%, which is the cumulative return of every other day. In particular, (100%+440%)*(100%+404%)=(100%+2622%); if we take the log of everything we get ln(5.4)+ln(5.04)=ln(27.22); on ln-scale, returns add instead of multiply. Thus "half of the returns" on ln-scale is halving the value; without it, "half the returns" is square root.

    – Yakk
    Sep 18 at 14:02







  • 7





    @NuclearWang - It's at least plausible that if you could replace the returns of several "best days of a year" from a low-volatility year with a single second- or third-best day from one of the more volatile years. '87 had a 9.1% return day, if there were a few 7 or 8% days in there as well, that would easily balance several of the < 2% years that were included. But you'd need to pull more daily-level information to confirm that supposition.

    – Justin Cave
    Sep 18 at 14:37


















29



















Nassim Taleb is remarkably brilliant. It's his work that's cited in the article. In my opinion, there are 2 choices, a misquote, if the article is wrong, or a misunderstanding on the part of the reader. There are a few things going on. Thanks to member Justin, I fixed the Wikipedia article link. I recall his assertion from the book "The Black Swan" (p275). And here it is -



enter image description here



and the referenced chart -



enter image description here



Now, with thanks to member Money Ann, who actually noted that the product of the 10 best days, was, in fact 64%.



Putting on my math hat, those ten days, cumulatively, multiplied one's wealth by 1.64. Game over. Had you 'not' been in the market the full ten days, it doesn't matter how far back you go, nor how far forward. Pull those numbers out and you have to divide your wealth by 1.64. (The only argument one might have is that, for example, deposits are made along the way, I, for instance, only started investing in 1984, so earlier numbers don't matter. That's a distraction, not the point of the long term observation).



To simplify my examples, say there was one day that the S&P went up 10% (for easy math). And we have the 4300% return long term that Money Ann cites. Remove that one day and you'd have only 3909% return. Not 4290%.



So, in fact, no surprise, the citation is accurate, although in the book, Taleb is more vague.



If my answer here needs any clarification, I am happy to do so. Please comment and I'll return, edit, and clean up comments.



Edit - in response to Dennis’ comment. Say there were a crash, and right after, the market recovered 50% in just one day. In a history of daily returns, we’d now have 1.5 as a factor. Now, over a long period of time, decades, we see the market up 1900%, i.e. the multiplication result is 20, as we flip from percents to factors. Remove the 1.5, and the result is simply 10, or growth of 900%. That one day, in or out, made a huge difference. It’s for the reader to keep an open mind, and realize it doesn’t take too many days to multiply to get that 50%. In fact, it’s not even 10. The moral of Taleb’s story is simply that trading, getting in and out of the market is a greater risk than staying in for the long term. (And note to Dennis - mhoran already made the same 50% math example. This is just the same in my own words.)






share|improve this answer























  • 1





    So, the paraphrase is NOT accurate. Those 10 days represent a 64% return. Standalone statement. It is completely unrelated to the return of the other 49.95 years, so phrasing it as "64% of the returns of the last 50 years" serves no purpose except to mislead.

    – Ben Voigt
    Sep 19 at 14:26







  • 1





    Ben - are you suggesting Taleb is misleading or that my explanation of his statement is flawed?

    – JTP - Apologise to Monica
    Sep 19 at 15:48






  • 2





    I was speaking about the quote in the question, which paraphrases Taleb. But the book snippet shown in your answer (the prose not the plot) does suggest the mistaken claim... I might have used a stronger word but there's nothing wrong with your description "vague".

    – Ben Voigt
    Sep 19 at 16:20











  • I agree with Ben - half the return should mean square root of the multiplier. Otherwise you can have a ridiculous scenario where there can be many disjoint sets of days, each set having "half the returns".

    – Reinstate Monica
    Sep 20 at 12:55






  • 1





    @DennisJaheruddin - done.

    – JTP - Apologise to Monica
    Sep 21 at 12:32


















16



















Since the book was written in 1997, the relevant period would be roughly 1947-1996. Yahoo Finance data starts from 1950, so I will look at "last 47 years" instead. Presumably, the finding by Mandelbrot and Taleb is not so trivial that it would no longer apply to even a slightly different time period.



On Jan 3, 1950 the S&P closed $16.66. On December 31, 1996, it closed $740.74. This is an increase of 4300% in total. The best days were:



1987-10-21 9.10%
1987-10-20 5.33%
1970-05-27 5.02%
1987-10-29 4.93%
1982-08-17 4.76%
1962-05-29 4.65%
1974-10-09 4.60%
1957-10-23 4.49%
1974-10-07 4.19%
1974-07-12 4.08%


This sums to 50%. Perhaps what is meant is that if you had only traded on the 10 best days you would make the lion's share of profit. To verify that we can take the product and obtain a 64% increase. So as far as I can tell, the claim as presented appears to be false. Neither Mandelbrot nor Taleb are generally considered fools or charlatans, so I'm assuming something was lost in translation. It is interesting that the 64% I got was very close to the 63% cited.



63% of 4300% is 2709% (if taking the percent of a percent confuses you, just think of making $4300 for every $100 you put in, and taking 63% of that). To obtain this profit by only trading on the best days, you would need to trade on about 115 days spanning from 1950 to 1991. Interestingly, if you traded on only the best days, your maximum gain would be about 3*10^12% from trading on 10240 of 11826 trading days in the dataset.



Incidentally, if you traded on 20 worst days, you would lose two thirds of your money. Your outlook only improves if you traded on the worst 10040 days, in which case you also lose two thirds. You can at most miss 140 of the best days if you want to at least break even, assuming you trade on every other day.



Interesting as it is to debate all this arithmetic, the second part of your question is more useful to discuss:




Or is it even fair to ask if this is true?




It doesn't really matter exactly what the numbers are. The authors' point is that there is an exponential distribution in stock market returns, where you make or lose huge sums on a minority of days, while most days don't really affect you one way or the other. Of course, the "long" or "fat" tails in market return distributions are well known. In nature, almost everything is distributed such that extreme events are rare, and common events are small. We do not have many phenomena where most values are very far away from the mean or median, the market is no exception. The debate that Mandelbrot and Taleb are addressing here is with regards to exact probability of a given unlikely event being 10^-9 vs. 10^-10 vs. 0. It may seem like it's academic, but in some cases it can make a big difference. The difference is unlikely to be apparent for a non-technically sophisticated trader.






share|improve this answer




























  • Using your figures, for the 10 best days to deliver 63% of the 4300% in returns, they would have daily increases of 46% if they were all equal. As can be seen from the data in this answer (or Justin Cave's answer), there is not a single day (or even a single year) that delivers this kind of return.

    – jcaron
    Sep 18 at 11:57






  • 12





    Hi Ann, please see my answer. You did all the heavy lifting, but came to the wrong conclusion. The key was noting that returns multiply.

    – JTP - Apologise to Monica
    Sep 18 at 12:33






  • 9





    1.0408 * 1.0419 * 1.0449 * 1.0460 * 1.0465 * 1.0476 * 1.0493 * 1.0502 * 1.0533 * 1.0910 = 1.64544351855912

    – Joshua
    Sep 18 at 15:14











  • "63% of the gains" may well mean pow(43.00, 0.63) not 43.00 * 0.63. Using this interpretation it would be only a factor of 10.69 not 27.09. Still far above the 1.64 factor from the best 10 days.

    – Ben Voigt
    Sep 18 at 18:56











  • Start with $100, 4300% returns gives you $4400; take out the compounded returns as Joshua calculated and you have $2674 for a return of 2574%. 2574/4300 is 62%, so 38% of the returns are attributable to the top 10 days. That's not the 63% in question, but it's still a significant proportion.

    – Kevin
    Sep 18 at 19:16


















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Let’s simplify it, our example investment is very boring except for one day when it goes crazy.



Two investors with same $1,000 initial investment, the market doubles every 7 years except for one day at the end of the first 7 years when it goes up by 50%. The first investor invests for the whole period, the second investor skips just one day.



Investor 1:



  • Starts with $1,000

  • 7 years later $2,000 (2x)

  • Crazy day with a 50% increase ends with $3,000

  • 28 years later $48,000 (16x)

Investor 2:



  • Starts with $1,000

  • 7 years later $2,000 (2x)

  • Misses the crazy day but then reenters the market still at $2,000

  • 28 years later $32,000 (16x)

Investor one sees the initial investment go up 48x or 4700% Investor B sees the value go up by 32X or 3100%. So that 1 day with a 50% would erase about 50% of the gains even though the unlucky investor saw 3100% gain.



I did find that a similar phrase in an article on the motley fool website




Time in the market, versus time out of the market



J.P. Morgan Asset Management's 2019 Retirement Guide shows the impact
that pulling out of the market has on a portfolio. Looking back over
the 20-year period from Jan. 1, 1999, to Dec. 31, 2018, if you missed
the top 10 best days in the stock market, your overall return was cut
in half. That's a significant difference for only 10 days over two
decades!




The JP Morgan study can be found on their website. Page 41 of the report has information.






share|improve this answer




























  • Nice, easy to follow, example. Sometimes just showing simple numbers, the 50% one time gain, can really make things clear.

    – JTP - Apologise to Monica
    Sep 18 at 16:03


















10



















I can't speak to the research methods used in that study but Taleb was likely trying to build on his "black swan" hypothesis by showing that the "black swan" trading days have the biggest impact on the market overall.



The math behind Mandelbrot's and Taleb's analyses always goes over my head, even though I'm a fan of Taleb's work from a philosophical standpoint.



Tony Robbins simplified this concept by enforcing the idea that you can't time the stock market. I'm not sure who did the research, but it shows that if you try to time the market and miss out on the top performing days, you ultimately underperform the market.



enter image description here
Image source: MarketWatch






share|improve this answer





















  • 5





    I wonder what the reverse looks like (excluding the worst 10/20/40 days)

    – Ben Voigt
    Sep 17 at 22:05






  • 1





    @BenVoigt That's a good point. I'd love to see that information.

    – daytrader
    Sep 17 at 22:06






  • 1





    The data, easily downloaded back to 1950 on Yahoo, is ready for your analysis. Spreadsheets are my friend.

    – JTP - Apologise to Monica
    Sep 18 at 16:06


















0



















Perhaps true, but not evidence that returns are non-normal. I agree they are not normally distributed but disagree with the reasoning. As others pointed out, if the return of the top ten days is 63%, the claim is true regardless of the the performance of the other days. This can be achieved with a sufficiently volatile normal distribution. If the standard deviation of the returns is low and it is achieved, together it may be evidence of heavy tails. In isolation, it is not.



The simple script below generates normal returns such that the top 10 days have approximately a 70% return. Adjusting the standard deviation parameter will show the relationship.



import numpy as np

n_simulations = 5000
n_days_per_year = 250
n_years = 50
n_days = n_days_per_year*n_years
mean = 0.1/n_days_per_year
std_dev = 0.25 / n_days_per_year**0.5

rnds = np.random.normal(size=(n_days,int(n_simulations/2)))
rnds = np.concatenate((rnds,-rnds),axis=1) # antithetic

returns = mean + std_dev*rnds

sorted_returns = np.array([np.sort(returns[:,i_simulation]) for i_simulation in range(n_simulations)]).T
top_ten_returns = np.product(1+sorted_returns[-10:,:],0) - 1
print(np.mean(top_ten_returns))





share|improve this answer

































    0



















    I have seen many claims of this nature. I suspect that most of them have done the arithmetic correctly. What it is being used for here is to claim that the normal distribution is a bad model of reality far from the mean, because events many standard deviations out are much more common than the normal distribution would claim. The normal distribution is very convenient because we have lots of theorems about what happens when things are normally distributed. As long as you stay close to the mean it doesn't matter much which bell shaped curve you use. When you go far out it matters a lot. In real life the tails are always greater than a normal distribution will say.



    The fact that the arithmetic is right doesn't tell us how to react to the fact. It is often cited to tell you not to try to time the market, because if you miss the best 10 days you miss so much of the return. On the other hand, if you miss the 10 worst days your return goes way up. No justification is offered that trying to time the market makes you more likely to miss the great days than miss the terrible days.






    share|improve this answer

































      0



















      Lots of great mathematical exegesis here but looking more widely there seem to be two primary motivations that people have for making these comments about "best days".



      One is the Nick Taleb point that 'fat tails' mean that the distribution of returns is concentrated (for good or ill) in a few incidents. This seems valid.



      You will also come across it as an argument against pulling out of the market in periods of volatility. This is not really a valid argument - it rather ignores the point that if you instead caught the "worst days" of the market you would be suffering huge losses. (which is not to say the conclusion is wrong - just the argument)



      (FYI, if you are interested in long-term stock market returns the go-to-guy is Elroy Dimson - a professor at LBS & the Judge Instittue. He has analysed this across multiple countries and periods).






      share|improve this answer

































        -1



















        tl;dr- This claim is false. While it's true that an investor who bought in at the start of each of the top-10 days, then sold at the end of them, could enjoy gains of 64% over a similar investor who didn't participate on those 10 days, it doesn't follow that these top-10 days "represent 63 per cent of the returns of the past 50 years".




        The claim is incorrect due to a broken frame.



        Imagine that someone tells you that the best strategy for your financial future is to use a certain strategy for playing poker at a Las Vegas casino. They might be correct about their strategy being optimal, in a frame that assumes that you're going to be betting your financial future at a casino. But, is it then true that the optimal strategy for your financial future involves playing poker in a Las Vegas casino?



        It's not that the claim about how to play poker is necessarily wrong, but the frame around it is. Likewise, the title of this question asks:




        Is it true that, “just ten trading days represent 63 per cent of the returns of the past 50 years”?




        That "63 per cent" figure may come from correctly performed mathematical operations, but the frame suggests that someone who missed those 10 days could only hope to enjoy the remaining 37% of returns over the past 50 years.



        The problem's that it's generally inappropriate to claim that members of some set constitute some portion of that set's total when that set isn't just adding over positive values. (More about the math at the end of this answer.)



        For example, going by Wikipedia's numbers, it looks like an investor who skipped the worst-5 days would've applied a ~79.4% gain to their wealth. But does it make sense to attribute ~79.4% of wealth to skipping the worst-5 days while also attributing 63% of the wealth to being present for the best-10 days?




        Analogy: Did one employee do 90% of a small operation's work?



        Consider a small company with 25 employees. They do little contract jobs.



        One employee, Bob, has a minor role as a specialist on 90% of the projects; the other 10% don't involve his area of expertise. Bob then writes on his resume:




        My efforts represented 90% of the company's productivity during my tenure.




        Which makes it sound like he did 90% of the work, and everyone else did 10%, right? Clearly he's a top-notch employee!



        And he's not lying, in the sense of making numbers up. That figure's accurate, for the frame in which it was calculated.



        The problem's that the frame's broken. This is, it doesn't make sense for Bob to describe his participation in 90% of the projects as having represented 90% of the company's work. It's not that he did the math wrong, it's that the logic behind the model itself is a tad silly.




        Corrected claim: Investing on the top-10 best days would yield a ~64% return.



        It seems that, if an investor invested at the start of a day and then pulled out at the end for each of the top-10 days, they'd have applied a factor of ~164%, for a gain of ~64%.



        Without checking the math or figures, that looks plausible to me. But, assuming it's true, it becomes false if we misrepresent that claim through wording that makes it sound like this is a thing where it's meaningful to attribute 64% of gains to 10 specific days, such that anyone who missed those 10 specific days can only hope to enjoy 36% of gains, or something like that.



        It's not that someone did the math wrong or messed up calculating the figure; rather, it's that the model frame in which the figure exists is itself broken. The correct solution is to exit that frame.




        Discussion: Mathematical explanation.



        When we say that something contributes x% to a total, we're typically working within a framework in which we're adding a bunch of positive values to arrive at a total.



        We can make these investments additive. Specifically, we can take the natural-logarithm of each day's ratio to arrive at an additive parameter. Then, we can sum those additive parameters up, raise Euler's number to the power of their sum, and that's the total factor.



        To grab the table from @MoneyAnn's answer, then augment it:



         Date +% factor ln(factor)
        -----------------------------------------------------
        1987-10-21 0.0910 1.0910 0.0870947068509337
        1987-10-20 0.0533 1.0533 0.0519280928603591
        1970-05-27 0.0502 1.0502 0.0489806222216219
        1987-10-29 0.0493 1.0493 0.0481232751817282
        1982-08-17 0.0476 1.0476 0.0465018336514199
        1962-05-29 0.0465 1.0465 0.0454512629039174
        1974-10-09 0.0460 1.0460 0.0449733656427312
        1957-10-23 0.0449 1.0449 0.0439211870579281
        1974-10-07 0.0419 1.0419 0.0410459694360010
        1974-07-12 0.0408 1.0408 0.0399896482161584
        ------------------
        Total: 0.498009964


        Then exp(0.498009964) is 1.645443519, which recovers that ~1.64-factor, or ~64%, other answers were referring to.



        However, the broken frame presented in the claim has 2 major problems:



        1. The factors aren't totaled over all days.
          If someone wanted to make a claim like this, then they should've ln(factor)'d all of the days, then divided the sum of those parameters for the top-10 days by the sum of those parameters for all of the days.


        2. The factors contain negatives.
          Some days ended lower than they started. For example, apparently 1987-10-19 had a −20.47% hit, for a ln(factor) ~= ln(1-0.247) ~= -0.231553819. In general, for any factor of less than 1, ln(factor) should be negative.


        We could try to fix up the numbers to account for Problem #1, but the frame doesn't lend itself to resolving Problem #2.






        share|improve this answer




























        • To note it, the original authors were apparently trying to make a point about how distributions could be non-normal. This overall point that they were trying to make is very much correct. It's the specific claim asked about in this question that was so poorly expressed that we may as well disregard it as false.

          – Nat
          Sep 20 at 21:32













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        9 Answers
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        43



















        Mild vs. Wild Randomness:
        Focusing on those Risks that
        Matter and A focus on the exceptions
        that prove the rule are copies of the original article referenced by the Wikipedia page. The authors are well respected academics so I assume that they have some support for the statement but the article doesn't appear to explain exactly what they assumed.



        For a plausibility check, according to this chart the total compound increase in the S&P 500 index from 1970-01-01 to on 2018-12-31 (48 years so close to the 50 years they quote though obviously a different 50 year period) is 2622.25% (I'm using the Change in Index rather than including dividends because that requires actual research). I'm also too lazy to find a quick source of the top 60 days by percentage change since 1970 but Wikipedia does have a list of the best day each year so we can ask "If you had been invested in the S&P 500 since 1970-01-01 (ignoring dividends) but missed the best day each year, how much would you have lost overall?" If we take the best single-day returns for every year since 1970 that would produce 440.05% growth. If we exclude those 48 days, the other 364 days must have produced 467.04% growth-- (1+4.4005)*(1+4.6704)-1 = 26.2225). So (rather approximately) half the growth in the index has come from the best single day in each year which is roughly in line with the claim.



        I assume that Prof. Mandelbrot and Taleb did a much more thorough analysis than I did here. Clearly they were looking at a different time period than I am, they were probably looking at a different index, they weren't limiting themselves to the data they could easily grab from Wikipedia, etc. But it's interesting that you can get reasonably close to their number doing a back of the envelope calculation using a much different data set than they were working with.



        Compounding the best day of S&P 500 returns every year



        Compounding the annual return of the S&P 500 since 1970






        share|improve this answer





















        • 11





          @RonJohn - Percentages of percentages don't really make sense (the statement in the article isn't as precise on that point as I would prefer). The best day produced roughly the same total return as the other 364 days (440% vs 467%). If you converted that to an annualized rate of return, the best day would account for roughly half of the total growth over 50 years. My expectation is that the article was actually comparing relative annual rates of return. I'm cheating and just making a rough comparison of the two components and saying they're roughly equal.

          – Justin Cave
          Sep 18 at 3:04






        • 3





          If percentages of percentages don't really make sense, then the statement in question (which is nothing but about a percentage of a percentage) doesn't make sense.

          – RonJohn
          Sep 18 at 3:16






        • 4





          Maybe they meant, in each of the past 50 years, that year's best ten days provided 63% of that year's return, on average.

          – AakashM
          Sep 18 at 9:56






        • 4





          Possibly it is easier if you use ln-scale returns. ln(100%+X%) is the ln-scale return of an X% profit. So a 0% profit is 0 on ln-scale. 440% is 1.686, 2622% is 3.303; here, ln-scale 440% is more than half of 2622%. The difference, 1.617 is the ln-scale of 404%, which is the cumulative return of every other day. In particular, (100%+440%)*(100%+404%)=(100%+2622%); if we take the log of everything we get ln(5.4)+ln(5.04)=ln(27.22); on ln-scale, returns add instead of multiply. Thus "half of the returns" on ln-scale is halving the value; without it, "half the returns" is square root.

          – Yakk
          Sep 18 at 14:02







        • 7





          @NuclearWang - It's at least plausible that if you could replace the returns of several "best days of a year" from a low-volatility year with a single second- or third-best day from one of the more volatile years. '87 had a 9.1% return day, if there were a few 7 or 8% days in there as well, that would easily balance several of the < 2% years that were included. But you'd need to pull more daily-level information to confirm that supposition.

          – Justin Cave
          Sep 18 at 14:37















        43



















        Mild vs. Wild Randomness:
        Focusing on those Risks that
        Matter and A focus on the exceptions
        that prove the rule are copies of the original article referenced by the Wikipedia page. The authors are well respected academics so I assume that they have some support for the statement but the article doesn't appear to explain exactly what they assumed.



        For a plausibility check, according to this chart the total compound increase in the S&P 500 index from 1970-01-01 to on 2018-12-31 (48 years so close to the 50 years they quote though obviously a different 50 year period) is 2622.25% (I'm using the Change in Index rather than including dividends because that requires actual research). I'm also too lazy to find a quick source of the top 60 days by percentage change since 1970 but Wikipedia does have a list of the best day each year so we can ask "If you had been invested in the S&P 500 since 1970-01-01 (ignoring dividends) but missed the best day each year, how much would you have lost overall?" If we take the best single-day returns for every year since 1970 that would produce 440.05% growth. If we exclude those 48 days, the other 364 days must have produced 467.04% growth-- (1+4.4005)*(1+4.6704)-1 = 26.2225). So (rather approximately) half the growth in the index has come from the best single day in each year which is roughly in line with the claim.



        I assume that Prof. Mandelbrot and Taleb did a much more thorough analysis than I did here. Clearly they were looking at a different time period than I am, they were probably looking at a different index, they weren't limiting themselves to the data they could easily grab from Wikipedia, etc. But it's interesting that you can get reasonably close to their number doing a back of the envelope calculation using a much different data set than they were working with.



        Compounding the best day of S&P 500 returns every year



        Compounding the annual return of the S&P 500 since 1970






        share|improve this answer





















        • 11





          @RonJohn - Percentages of percentages don't really make sense (the statement in the article isn't as precise on that point as I would prefer). The best day produced roughly the same total return as the other 364 days (440% vs 467%). If you converted that to an annualized rate of return, the best day would account for roughly half of the total growth over 50 years. My expectation is that the article was actually comparing relative annual rates of return. I'm cheating and just making a rough comparison of the two components and saying they're roughly equal.

          – Justin Cave
          Sep 18 at 3:04






        • 3





          If percentages of percentages don't really make sense, then the statement in question (which is nothing but about a percentage of a percentage) doesn't make sense.

          – RonJohn
          Sep 18 at 3:16






        • 4





          Maybe they meant, in each of the past 50 years, that year's best ten days provided 63% of that year's return, on average.

          – AakashM
          Sep 18 at 9:56






        • 4





          Possibly it is easier if you use ln-scale returns. ln(100%+X%) is the ln-scale return of an X% profit. So a 0% profit is 0 on ln-scale. 440% is 1.686, 2622% is 3.303; here, ln-scale 440% is more than half of 2622%. The difference, 1.617 is the ln-scale of 404%, which is the cumulative return of every other day. In particular, (100%+440%)*(100%+404%)=(100%+2622%); if we take the log of everything we get ln(5.4)+ln(5.04)=ln(27.22); on ln-scale, returns add instead of multiply. Thus "half of the returns" on ln-scale is halving the value; without it, "half the returns" is square root.

          – Yakk
          Sep 18 at 14:02







        • 7





          @NuclearWang - It's at least plausible that if you could replace the returns of several "best days of a year" from a low-volatility year with a single second- or third-best day from one of the more volatile years. '87 had a 9.1% return day, if there were a few 7 or 8% days in there as well, that would easily balance several of the < 2% years that were included. But you'd need to pull more daily-level information to confirm that supposition.

          – Justin Cave
          Sep 18 at 14:37













        43















        43











        43









        Mild vs. Wild Randomness:
        Focusing on those Risks that
        Matter and A focus on the exceptions
        that prove the rule are copies of the original article referenced by the Wikipedia page. The authors are well respected academics so I assume that they have some support for the statement but the article doesn't appear to explain exactly what they assumed.



        For a plausibility check, according to this chart the total compound increase in the S&P 500 index from 1970-01-01 to on 2018-12-31 (48 years so close to the 50 years they quote though obviously a different 50 year period) is 2622.25% (I'm using the Change in Index rather than including dividends because that requires actual research). I'm also too lazy to find a quick source of the top 60 days by percentage change since 1970 but Wikipedia does have a list of the best day each year so we can ask "If you had been invested in the S&P 500 since 1970-01-01 (ignoring dividends) but missed the best day each year, how much would you have lost overall?" If we take the best single-day returns for every year since 1970 that would produce 440.05% growth. If we exclude those 48 days, the other 364 days must have produced 467.04% growth-- (1+4.4005)*(1+4.6704)-1 = 26.2225). So (rather approximately) half the growth in the index has come from the best single day in each year which is roughly in line with the claim.



        I assume that Prof. Mandelbrot and Taleb did a much more thorough analysis than I did here. Clearly they were looking at a different time period than I am, they were probably looking at a different index, they weren't limiting themselves to the data they could easily grab from Wikipedia, etc. But it's interesting that you can get reasonably close to their number doing a back of the envelope calculation using a much different data set than they were working with.



        Compounding the best day of S&P 500 returns every year



        Compounding the annual return of the S&P 500 since 1970






        share|improve this answer














        Mild vs. Wild Randomness:
        Focusing on those Risks that
        Matter and A focus on the exceptions
        that prove the rule are copies of the original article referenced by the Wikipedia page. The authors are well respected academics so I assume that they have some support for the statement but the article doesn't appear to explain exactly what they assumed.



        For a plausibility check, according to this chart the total compound increase in the S&P 500 index from 1970-01-01 to on 2018-12-31 (48 years so close to the 50 years they quote though obviously a different 50 year period) is 2622.25% (I'm using the Change in Index rather than including dividends because that requires actual research). I'm also too lazy to find a quick source of the top 60 days by percentage change since 1970 but Wikipedia does have a list of the best day each year so we can ask "If you had been invested in the S&P 500 since 1970-01-01 (ignoring dividends) but missed the best day each year, how much would you have lost overall?" If we take the best single-day returns for every year since 1970 that would produce 440.05% growth. If we exclude those 48 days, the other 364 days must have produced 467.04% growth-- (1+4.4005)*(1+4.6704)-1 = 26.2225). So (rather approximately) half the growth in the index has come from the best single day in each year which is roughly in line with the claim.



        I assume that Prof. Mandelbrot and Taleb did a much more thorough analysis than I did here. Clearly they were looking at a different time period than I am, they were probably looking at a different index, they weren't limiting themselves to the data they could easily grab from Wikipedia, etc. But it's interesting that you can get reasonably close to their number doing a back of the envelope calculation using a much different data set than they were working with.



        Compounding the best day of S&P 500 returns every year



        Compounding the annual return of the S&P 500 since 1970







        share|improve this answer













        share|improve this answer




        share|improve this answer










        answered Sep 17 at 21:35









        Justin CaveJustin Cave

        4,6361 gold badge13 silver badges22 bronze badges




        4,6361 gold badge13 silver badges22 bronze badges










        • 11





          @RonJohn - Percentages of percentages don't really make sense (the statement in the article isn't as precise on that point as I would prefer). The best day produced roughly the same total return as the other 364 days (440% vs 467%). If you converted that to an annualized rate of return, the best day would account for roughly half of the total growth over 50 years. My expectation is that the article was actually comparing relative annual rates of return. I'm cheating and just making a rough comparison of the two components and saying they're roughly equal.

          – Justin Cave
          Sep 18 at 3:04






        • 3





          If percentages of percentages don't really make sense, then the statement in question (which is nothing but about a percentage of a percentage) doesn't make sense.

          – RonJohn
          Sep 18 at 3:16






        • 4





          Maybe they meant, in each of the past 50 years, that year's best ten days provided 63% of that year's return, on average.

          – AakashM
          Sep 18 at 9:56






        • 4





          Possibly it is easier if you use ln-scale returns. ln(100%+X%) is the ln-scale return of an X% profit. So a 0% profit is 0 on ln-scale. 440% is 1.686, 2622% is 3.303; here, ln-scale 440% is more than half of 2622%. The difference, 1.617 is the ln-scale of 404%, which is the cumulative return of every other day. In particular, (100%+440%)*(100%+404%)=(100%+2622%); if we take the log of everything we get ln(5.4)+ln(5.04)=ln(27.22); on ln-scale, returns add instead of multiply. Thus "half of the returns" on ln-scale is halving the value; without it, "half the returns" is square root.

          – Yakk
          Sep 18 at 14:02







        • 7





          @NuclearWang - It's at least plausible that if you could replace the returns of several "best days of a year" from a low-volatility year with a single second- or third-best day from one of the more volatile years. '87 had a 9.1% return day, if there were a few 7 or 8% days in there as well, that would easily balance several of the < 2% years that were included. But you'd need to pull more daily-level information to confirm that supposition.

          – Justin Cave
          Sep 18 at 14:37












        • 11





          @RonJohn - Percentages of percentages don't really make sense (the statement in the article isn't as precise on that point as I would prefer). The best day produced roughly the same total return as the other 364 days (440% vs 467%). If you converted that to an annualized rate of return, the best day would account for roughly half of the total growth over 50 years. My expectation is that the article was actually comparing relative annual rates of return. I'm cheating and just making a rough comparison of the two components and saying they're roughly equal.

          – Justin Cave
          Sep 18 at 3:04






        • 3





          If percentages of percentages don't really make sense, then the statement in question (which is nothing but about a percentage of a percentage) doesn't make sense.

          – RonJohn
          Sep 18 at 3:16






        • 4





          Maybe they meant, in each of the past 50 years, that year's best ten days provided 63% of that year's return, on average.

          – AakashM
          Sep 18 at 9:56






        • 4





          Possibly it is easier if you use ln-scale returns. ln(100%+X%) is the ln-scale return of an X% profit. So a 0% profit is 0 on ln-scale. 440% is 1.686, 2622% is 3.303; here, ln-scale 440% is more than half of 2622%. The difference, 1.617 is the ln-scale of 404%, which is the cumulative return of every other day. In particular, (100%+440%)*(100%+404%)=(100%+2622%); if we take the log of everything we get ln(5.4)+ln(5.04)=ln(27.22); on ln-scale, returns add instead of multiply. Thus "half of the returns" on ln-scale is halving the value; without it, "half the returns" is square root.

          – Yakk
          Sep 18 at 14:02







        • 7





          @NuclearWang - It's at least plausible that if you could replace the returns of several "best days of a year" from a low-volatility year with a single second- or third-best day from one of the more volatile years. '87 had a 9.1% return day, if there were a few 7 or 8% days in there as well, that would easily balance several of the < 2% years that were included. But you'd need to pull more daily-level information to confirm that supposition.

          – Justin Cave
          Sep 18 at 14:37







        11




        11





        @RonJohn - Percentages of percentages don't really make sense (the statement in the article isn't as precise on that point as I would prefer). The best day produced roughly the same total return as the other 364 days (440% vs 467%). If you converted that to an annualized rate of return, the best day would account for roughly half of the total growth over 50 years. My expectation is that the article was actually comparing relative annual rates of return. I'm cheating and just making a rough comparison of the two components and saying they're roughly equal.

        – Justin Cave
        Sep 18 at 3:04





        @RonJohn - Percentages of percentages don't really make sense (the statement in the article isn't as precise on that point as I would prefer). The best day produced roughly the same total return as the other 364 days (440% vs 467%). If you converted that to an annualized rate of return, the best day would account for roughly half of the total growth over 50 years. My expectation is that the article was actually comparing relative annual rates of return. I'm cheating and just making a rough comparison of the two components and saying they're roughly equal.

        – Justin Cave
        Sep 18 at 3:04




        3




        3





        If percentages of percentages don't really make sense, then the statement in question (which is nothing but about a percentage of a percentage) doesn't make sense.

        – RonJohn
        Sep 18 at 3:16





        If percentages of percentages don't really make sense, then the statement in question (which is nothing but about a percentage of a percentage) doesn't make sense.

        – RonJohn
        Sep 18 at 3:16




        4




        4





        Maybe they meant, in each of the past 50 years, that year's best ten days provided 63% of that year's return, on average.

        – AakashM
        Sep 18 at 9:56





        Maybe they meant, in each of the past 50 years, that year's best ten days provided 63% of that year's return, on average.

        – AakashM
        Sep 18 at 9:56




        4




        4





        Possibly it is easier if you use ln-scale returns. ln(100%+X%) is the ln-scale return of an X% profit. So a 0% profit is 0 on ln-scale. 440% is 1.686, 2622% is 3.303; here, ln-scale 440% is more than half of 2622%. The difference, 1.617 is the ln-scale of 404%, which is the cumulative return of every other day. In particular, (100%+440%)*(100%+404%)=(100%+2622%); if we take the log of everything we get ln(5.4)+ln(5.04)=ln(27.22); on ln-scale, returns add instead of multiply. Thus "half of the returns" on ln-scale is halving the value; without it, "half the returns" is square root.

        – Yakk
        Sep 18 at 14:02






        Possibly it is easier if you use ln-scale returns. ln(100%+X%) is the ln-scale return of an X% profit. So a 0% profit is 0 on ln-scale. 440% is 1.686, 2622% is 3.303; here, ln-scale 440% is more than half of 2622%. The difference, 1.617 is the ln-scale of 404%, which is the cumulative return of every other day. In particular, (100%+440%)*(100%+404%)=(100%+2622%); if we take the log of everything we get ln(5.4)+ln(5.04)=ln(27.22); on ln-scale, returns add instead of multiply. Thus "half of the returns" on ln-scale is halving the value; without it, "half the returns" is square root.

        – Yakk
        Sep 18 at 14:02





        7




        7





        @NuclearWang - It's at least plausible that if you could replace the returns of several "best days of a year" from a low-volatility year with a single second- or third-best day from one of the more volatile years. '87 had a 9.1% return day, if there were a few 7 or 8% days in there as well, that would easily balance several of the < 2% years that were included. But you'd need to pull more daily-level information to confirm that supposition.

        – Justin Cave
        Sep 18 at 14:37





        @NuclearWang - It's at least plausible that if you could replace the returns of several "best days of a year" from a low-volatility year with a single second- or third-best day from one of the more volatile years. '87 had a 9.1% return day, if there were a few 7 or 8% days in there as well, that would easily balance several of the < 2% years that were included. But you'd need to pull more daily-level information to confirm that supposition.

        – Justin Cave
        Sep 18 at 14:37













        29



















        Nassim Taleb is remarkably brilliant. It's his work that's cited in the article. In my opinion, there are 2 choices, a misquote, if the article is wrong, or a misunderstanding on the part of the reader. There are a few things going on. Thanks to member Justin, I fixed the Wikipedia article link. I recall his assertion from the book "The Black Swan" (p275). And here it is -



        enter image description here



        and the referenced chart -



        enter image description here



        Now, with thanks to member Money Ann, who actually noted that the product of the 10 best days, was, in fact 64%.



        Putting on my math hat, those ten days, cumulatively, multiplied one's wealth by 1.64. Game over. Had you 'not' been in the market the full ten days, it doesn't matter how far back you go, nor how far forward. Pull those numbers out and you have to divide your wealth by 1.64. (The only argument one might have is that, for example, deposits are made along the way, I, for instance, only started investing in 1984, so earlier numbers don't matter. That's a distraction, not the point of the long term observation).



        To simplify my examples, say there was one day that the S&P went up 10% (for easy math). And we have the 4300% return long term that Money Ann cites. Remove that one day and you'd have only 3909% return. Not 4290%.



        So, in fact, no surprise, the citation is accurate, although in the book, Taleb is more vague.



        If my answer here needs any clarification, I am happy to do so. Please comment and I'll return, edit, and clean up comments.



        Edit - in response to Dennis’ comment. Say there were a crash, and right after, the market recovered 50% in just one day. In a history of daily returns, we’d now have 1.5 as a factor. Now, over a long period of time, decades, we see the market up 1900%, i.e. the multiplication result is 20, as we flip from percents to factors. Remove the 1.5, and the result is simply 10, or growth of 900%. That one day, in or out, made a huge difference. It’s for the reader to keep an open mind, and realize it doesn’t take too many days to multiply to get that 50%. In fact, it’s not even 10. The moral of Taleb’s story is simply that trading, getting in and out of the market is a greater risk than staying in for the long term. (And note to Dennis - mhoran already made the same 50% math example. This is just the same in my own words.)






        share|improve this answer























        • 1





          So, the paraphrase is NOT accurate. Those 10 days represent a 64% return. Standalone statement. It is completely unrelated to the return of the other 49.95 years, so phrasing it as "64% of the returns of the last 50 years" serves no purpose except to mislead.

          – Ben Voigt
          Sep 19 at 14:26







        • 1





          Ben - are you suggesting Taleb is misleading or that my explanation of his statement is flawed?

          – JTP - Apologise to Monica
          Sep 19 at 15:48






        • 2





          I was speaking about the quote in the question, which paraphrases Taleb. But the book snippet shown in your answer (the prose not the plot) does suggest the mistaken claim... I might have used a stronger word but there's nothing wrong with your description "vague".

          – Ben Voigt
          Sep 19 at 16:20











        • I agree with Ben - half the return should mean square root of the multiplier. Otherwise you can have a ridiculous scenario where there can be many disjoint sets of days, each set having "half the returns".

          – Reinstate Monica
          Sep 20 at 12:55






        • 1





          @DennisJaheruddin - done.

          – JTP - Apologise to Monica
          Sep 21 at 12:32















        29



















        Nassim Taleb is remarkably brilliant. It's his work that's cited in the article. In my opinion, there are 2 choices, a misquote, if the article is wrong, or a misunderstanding on the part of the reader. There are a few things going on. Thanks to member Justin, I fixed the Wikipedia article link. I recall his assertion from the book "The Black Swan" (p275). And here it is -



        enter image description here



        and the referenced chart -



        enter image description here



        Now, with thanks to member Money Ann, who actually noted that the product of the 10 best days, was, in fact 64%.



        Putting on my math hat, those ten days, cumulatively, multiplied one's wealth by 1.64. Game over. Had you 'not' been in the market the full ten days, it doesn't matter how far back you go, nor how far forward. Pull those numbers out and you have to divide your wealth by 1.64. (The only argument one might have is that, for example, deposits are made along the way, I, for instance, only started investing in 1984, so earlier numbers don't matter. That's a distraction, not the point of the long term observation).



        To simplify my examples, say there was one day that the S&P went up 10% (for easy math). And we have the 4300% return long term that Money Ann cites. Remove that one day and you'd have only 3909% return. Not 4290%.



        So, in fact, no surprise, the citation is accurate, although in the book, Taleb is more vague.



        If my answer here needs any clarification, I am happy to do so. Please comment and I'll return, edit, and clean up comments.



        Edit - in response to Dennis’ comment. Say there were a crash, and right after, the market recovered 50% in just one day. In a history of daily returns, we’d now have 1.5 as a factor. Now, over a long period of time, decades, we see the market up 1900%, i.e. the multiplication result is 20, as we flip from percents to factors. Remove the 1.5, and the result is simply 10, or growth of 900%. That one day, in or out, made a huge difference. It’s for the reader to keep an open mind, and realize it doesn’t take too many days to multiply to get that 50%. In fact, it’s not even 10. The moral of Taleb’s story is simply that trading, getting in and out of the market is a greater risk than staying in for the long term. (And note to Dennis - mhoran already made the same 50% math example. This is just the same in my own words.)






        share|improve this answer























        • 1





          So, the paraphrase is NOT accurate. Those 10 days represent a 64% return. Standalone statement. It is completely unrelated to the return of the other 49.95 years, so phrasing it as "64% of the returns of the last 50 years" serves no purpose except to mislead.

          – Ben Voigt
          Sep 19 at 14:26







        • 1





          Ben - are you suggesting Taleb is misleading or that my explanation of his statement is flawed?

          – JTP - Apologise to Monica
          Sep 19 at 15:48






        • 2





          I was speaking about the quote in the question, which paraphrases Taleb. But the book snippet shown in your answer (the prose not the plot) does suggest the mistaken claim... I might have used a stronger word but there's nothing wrong with your description "vague".

          – Ben Voigt
          Sep 19 at 16:20











        • I agree with Ben - half the return should mean square root of the multiplier. Otherwise you can have a ridiculous scenario where there can be many disjoint sets of days, each set having "half the returns".

          – Reinstate Monica
          Sep 20 at 12:55






        • 1





          @DennisJaheruddin - done.

          – JTP - Apologise to Monica
          Sep 21 at 12:32













        29















        29











        29









        Nassim Taleb is remarkably brilliant. It's his work that's cited in the article. In my opinion, there are 2 choices, a misquote, if the article is wrong, or a misunderstanding on the part of the reader. There are a few things going on. Thanks to member Justin, I fixed the Wikipedia article link. I recall his assertion from the book "The Black Swan" (p275). And here it is -



        enter image description here



        and the referenced chart -



        enter image description here



        Now, with thanks to member Money Ann, who actually noted that the product of the 10 best days, was, in fact 64%.



        Putting on my math hat, those ten days, cumulatively, multiplied one's wealth by 1.64. Game over. Had you 'not' been in the market the full ten days, it doesn't matter how far back you go, nor how far forward. Pull those numbers out and you have to divide your wealth by 1.64. (The only argument one might have is that, for example, deposits are made along the way, I, for instance, only started investing in 1984, so earlier numbers don't matter. That's a distraction, not the point of the long term observation).



        To simplify my examples, say there was one day that the S&P went up 10% (for easy math). And we have the 4300% return long term that Money Ann cites. Remove that one day and you'd have only 3909% return. Not 4290%.



        So, in fact, no surprise, the citation is accurate, although in the book, Taleb is more vague.



        If my answer here needs any clarification, I am happy to do so. Please comment and I'll return, edit, and clean up comments.



        Edit - in response to Dennis’ comment. Say there were a crash, and right after, the market recovered 50% in just one day. In a history of daily returns, we’d now have 1.5 as a factor. Now, over a long period of time, decades, we see the market up 1900%, i.e. the multiplication result is 20, as we flip from percents to factors. Remove the 1.5, and the result is simply 10, or growth of 900%. That one day, in or out, made a huge difference. It’s for the reader to keep an open mind, and realize it doesn’t take too many days to multiply to get that 50%. In fact, it’s not even 10. The moral of Taleb’s story is simply that trading, getting in and out of the market is a greater risk than staying in for the long term. (And note to Dennis - mhoran already made the same 50% math example. This is just the same in my own words.)






        share|improve this answer
















        Nassim Taleb is remarkably brilliant. It's his work that's cited in the article. In my opinion, there are 2 choices, a misquote, if the article is wrong, or a misunderstanding on the part of the reader. There are a few things going on. Thanks to member Justin, I fixed the Wikipedia article link. I recall his assertion from the book "The Black Swan" (p275). And here it is -



        enter image description here



        and the referenced chart -



        enter image description here



        Now, with thanks to member Money Ann, who actually noted that the product of the 10 best days, was, in fact 64%.



        Putting on my math hat, those ten days, cumulatively, multiplied one's wealth by 1.64. Game over. Had you 'not' been in the market the full ten days, it doesn't matter how far back you go, nor how far forward. Pull those numbers out and you have to divide your wealth by 1.64. (The only argument one might have is that, for example, deposits are made along the way, I, for instance, only started investing in 1984, so earlier numbers don't matter. That's a distraction, not the point of the long term observation).



        To simplify my examples, say there was one day that the S&P went up 10% (for easy math). And we have the 4300% return long term that Money Ann cites. Remove that one day and you'd have only 3909% return. Not 4290%.



        So, in fact, no surprise, the citation is accurate, although in the book, Taleb is more vague.



        If my answer here needs any clarification, I am happy to do so. Please comment and I'll return, edit, and clean up comments.



        Edit - in response to Dennis’ comment. Say there were a crash, and right after, the market recovered 50% in just one day. In a history of daily returns, we’d now have 1.5 as a factor. Now, over a long period of time, decades, we see the market up 1900%, i.e. the multiplication result is 20, as we flip from percents to factors. Remove the 1.5, and the result is simply 10, or growth of 900%. That one day, in or out, made a huge difference. It’s for the reader to keep an open mind, and realize it doesn’t take too many days to multiply to get that 50%. In fact, it’s not even 10. The moral of Taleb’s story is simply that trading, getting in and out of the market is a greater risk than staying in for the long term. (And note to Dennis - mhoran already made the same 50% math example. This is just the same in my own words.)







        share|improve this answer















        share|improve this answer




        share|improve this answer








        edited Sep 20 at 15:16

























        answered Sep 18 at 12:29









        JTP - Apologise to MonicaJTP - Apologise to Monica

        156k25 gold badges257 silver badges500 bronze badges




        156k25 gold badges257 silver badges500 bronze badges










        • 1





          So, the paraphrase is NOT accurate. Those 10 days represent a 64% return. Standalone statement. It is completely unrelated to the return of the other 49.95 years, so phrasing it as "64% of the returns of the last 50 years" serves no purpose except to mislead.

          – Ben Voigt
          Sep 19 at 14:26







        • 1





          Ben - are you suggesting Taleb is misleading or that my explanation of his statement is flawed?

          – JTP - Apologise to Monica
          Sep 19 at 15:48






        • 2





          I was speaking about the quote in the question, which paraphrases Taleb. But the book snippet shown in your answer (the prose not the plot) does suggest the mistaken claim... I might have used a stronger word but there's nothing wrong with your description "vague".

          – Ben Voigt
          Sep 19 at 16:20











        • I agree with Ben - half the return should mean square root of the multiplier. Otherwise you can have a ridiculous scenario where there can be many disjoint sets of days, each set having "half the returns".

          – Reinstate Monica
          Sep 20 at 12:55






        • 1





          @DennisJaheruddin - done.

          – JTP - Apologise to Monica
          Sep 21 at 12:32












        • 1





          So, the paraphrase is NOT accurate. Those 10 days represent a 64% return. Standalone statement. It is completely unrelated to the return of the other 49.95 years, so phrasing it as "64% of the returns of the last 50 years" serves no purpose except to mislead.

          – Ben Voigt
          Sep 19 at 14:26







        • 1





          Ben - are you suggesting Taleb is misleading or that my explanation of his statement is flawed?

          – JTP - Apologise to Monica
          Sep 19 at 15:48






        • 2





          I was speaking about the quote in the question, which paraphrases Taleb. But the book snippet shown in your answer (the prose not the plot) does suggest the mistaken claim... I might have used a stronger word but there's nothing wrong with your description "vague".

          – Ben Voigt
          Sep 19 at 16:20











        • I agree with Ben - half the return should mean square root of the multiplier. Otherwise you can have a ridiculous scenario where there can be many disjoint sets of days, each set having "half the returns".

          – Reinstate Monica
          Sep 20 at 12:55






        • 1





          @DennisJaheruddin - done.

          – JTP - Apologise to Monica
          Sep 21 at 12:32







        1




        1





        So, the paraphrase is NOT accurate. Those 10 days represent a 64% return. Standalone statement. It is completely unrelated to the return of the other 49.95 years, so phrasing it as "64% of the returns of the last 50 years" serves no purpose except to mislead.

        – Ben Voigt
        Sep 19 at 14:26






        So, the paraphrase is NOT accurate. Those 10 days represent a 64% return. Standalone statement. It is completely unrelated to the return of the other 49.95 years, so phrasing it as "64% of the returns of the last 50 years" serves no purpose except to mislead.

        – Ben Voigt
        Sep 19 at 14:26





        1




        1





        Ben - are you suggesting Taleb is misleading or that my explanation of his statement is flawed?

        – JTP - Apologise to Monica
        Sep 19 at 15:48





        Ben - are you suggesting Taleb is misleading or that my explanation of his statement is flawed?

        – JTP - Apologise to Monica
        Sep 19 at 15:48




        2




        2





        I was speaking about the quote in the question, which paraphrases Taleb. But the book snippet shown in your answer (the prose not the plot) does suggest the mistaken claim... I might have used a stronger word but there's nothing wrong with your description "vague".

        – Ben Voigt
        Sep 19 at 16:20





        I was speaking about the quote in the question, which paraphrases Taleb. But the book snippet shown in your answer (the prose not the plot) does suggest the mistaken claim... I might have used a stronger word but there's nothing wrong with your description "vague".

        – Ben Voigt
        Sep 19 at 16:20













        I agree with Ben - half the return should mean square root of the multiplier. Otherwise you can have a ridiculous scenario where there can be many disjoint sets of days, each set having "half the returns".

        – Reinstate Monica
        Sep 20 at 12:55





        I agree with Ben - half the return should mean square root of the multiplier. Otherwise you can have a ridiculous scenario where there can be many disjoint sets of days, each set having "half the returns".

        – Reinstate Monica
        Sep 20 at 12:55




        1




        1





        @DennisJaheruddin - done.

        – JTP - Apologise to Monica
        Sep 21 at 12:32





        @DennisJaheruddin - done.

        – JTP - Apologise to Monica
        Sep 21 at 12:32











        16



















        Since the book was written in 1997, the relevant period would be roughly 1947-1996. Yahoo Finance data starts from 1950, so I will look at "last 47 years" instead. Presumably, the finding by Mandelbrot and Taleb is not so trivial that it would no longer apply to even a slightly different time period.



        On Jan 3, 1950 the S&P closed $16.66. On December 31, 1996, it closed $740.74. This is an increase of 4300% in total. The best days were:



        1987-10-21 9.10%
        1987-10-20 5.33%
        1970-05-27 5.02%
        1987-10-29 4.93%
        1982-08-17 4.76%
        1962-05-29 4.65%
        1974-10-09 4.60%
        1957-10-23 4.49%
        1974-10-07 4.19%
        1974-07-12 4.08%


        This sums to 50%. Perhaps what is meant is that if you had only traded on the 10 best days you would make the lion's share of profit. To verify that we can take the product and obtain a 64% increase. So as far as I can tell, the claim as presented appears to be false. Neither Mandelbrot nor Taleb are generally considered fools or charlatans, so I'm assuming something was lost in translation. It is interesting that the 64% I got was very close to the 63% cited.



        63% of 4300% is 2709% (if taking the percent of a percent confuses you, just think of making $4300 for every $100 you put in, and taking 63% of that). To obtain this profit by only trading on the best days, you would need to trade on about 115 days spanning from 1950 to 1991. Interestingly, if you traded on only the best days, your maximum gain would be about 3*10^12% from trading on 10240 of 11826 trading days in the dataset.



        Incidentally, if you traded on 20 worst days, you would lose two thirds of your money. Your outlook only improves if you traded on the worst 10040 days, in which case you also lose two thirds. You can at most miss 140 of the best days if you want to at least break even, assuming you trade on every other day.



        Interesting as it is to debate all this arithmetic, the second part of your question is more useful to discuss:




        Or is it even fair to ask if this is true?




        It doesn't really matter exactly what the numbers are. The authors' point is that there is an exponential distribution in stock market returns, where you make or lose huge sums on a minority of days, while most days don't really affect you one way or the other. Of course, the "long" or "fat" tails in market return distributions are well known. In nature, almost everything is distributed such that extreme events are rare, and common events are small. We do not have many phenomena where most values are very far away from the mean or median, the market is no exception. The debate that Mandelbrot and Taleb are addressing here is with regards to exact probability of a given unlikely event being 10^-9 vs. 10^-10 vs. 0. It may seem like it's academic, but in some cases it can make a big difference. The difference is unlikely to be apparent for a non-technically sophisticated trader.






        share|improve this answer




























        • Using your figures, for the 10 best days to deliver 63% of the 4300% in returns, they would have daily increases of 46% if they were all equal. As can be seen from the data in this answer (or Justin Cave's answer), there is not a single day (or even a single year) that delivers this kind of return.

          – jcaron
          Sep 18 at 11:57






        • 12





          Hi Ann, please see my answer. You did all the heavy lifting, but came to the wrong conclusion. The key was noting that returns multiply.

          – JTP - Apologise to Monica
          Sep 18 at 12:33






        • 9





          1.0408 * 1.0419 * 1.0449 * 1.0460 * 1.0465 * 1.0476 * 1.0493 * 1.0502 * 1.0533 * 1.0910 = 1.64544351855912

          – Joshua
          Sep 18 at 15:14











        • "63% of the gains" may well mean pow(43.00, 0.63) not 43.00 * 0.63. Using this interpretation it would be only a factor of 10.69 not 27.09. Still far above the 1.64 factor from the best 10 days.

          – Ben Voigt
          Sep 18 at 18:56











        • Start with $100, 4300% returns gives you $4400; take out the compounded returns as Joshua calculated and you have $2674 for a return of 2574%. 2574/4300 is 62%, so 38% of the returns are attributable to the top 10 days. That's not the 63% in question, but it's still a significant proportion.

          – Kevin
          Sep 18 at 19:16















        16



















        Since the book was written in 1997, the relevant period would be roughly 1947-1996. Yahoo Finance data starts from 1950, so I will look at "last 47 years" instead. Presumably, the finding by Mandelbrot and Taleb is not so trivial that it would no longer apply to even a slightly different time period.



        On Jan 3, 1950 the S&P closed $16.66. On December 31, 1996, it closed $740.74. This is an increase of 4300% in total. The best days were:



        1987-10-21 9.10%
        1987-10-20 5.33%
        1970-05-27 5.02%
        1987-10-29 4.93%
        1982-08-17 4.76%
        1962-05-29 4.65%
        1974-10-09 4.60%
        1957-10-23 4.49%
        1974-10-07 4.19%
        1974-07-12 4.08%


        This sums to 50%. Perhaps what is meant is that if you had only traded on the 10 best days you would make the lion's share of profit. To verify that we can take the product and obtain a 64% increase. So as far as I can tell, the claim as presented appears to be false. Neither Mandelbrot nor Taleb are generally considered fools or charlatans, so I'm assuming something was lost in translation. It is interesting that the 64% I got was very close to the 63% cited.



        63% of 4300% is 2709% (if taking the percent of a percent confuses you, just think of making $4300 for every $100 you put in, and taking 63% of that). To obtain this profit by only trading on the best days, you would need to trade on about 115 days spanning from 1950 to 1991. Interestingly, if you traded on only the best days, your maximum gain would be about 3*10^12% from trading on 10240 of 11826 trading days in the dataset.



        Incidentally, if you traded on 20 worst days, you would lose two thirds of your money. Your outlook only improves if you traded on the worst 10040 days, in which case you also lose two thirds. You can at most miss 140 of the best days if you want to at least break even, assuming you trade on every other day.



        Interesting as it is to debate all this arithmetic, the second part of your question is more useful to discuss:




        Or is it even fair to ask if this is true?




        It doesn't really matter exactly what the numbers are. The authors' point is that there is an exponential distribution in stock market returns, where you make or lose huge sums on a minority of days, while most days don't really affect you one way or the other. Of course, the "long" or "fat" tails in market return distributions are well known. In nature, almost everything is distributed such that extreme events are rare, and common events are small. We do not have many phenomena where most values are very far away from the mean or median, the market is no exception. The debate that Mandelbrot and Taleb are addressing here is with regards to exact probability of a given unlikely event being 10^-9 vs. 10^-10 vs. 0. It may seem like it's academic, but in some cases it can make a big difference. The difference is unlikely to be apparent for a non-technically sophisticated trader.






        share|improve this answer




























        • Using your figures, for the 10 best days to deliver 63% of the 4300% in returns, they would have daily increases of 46% if they were all equal. As can be seen from the data in this answer (or Justin Cave's answer), there is not a single day (or even a single year) that delivers this kind of return.

          – jcaron
          Sep 18 at 11:57






        • 12





          Hi Ann, please see my answer. You did all the heavy lifting, but came to the wrong conclusion. The key was noting that returns multiply.

          – JTP - Apologise to Monica
          Sep 18 at 12:33






        • 9





          1.0408 * 1.0419 * 1.0449 * 1.0460 * 1.0465 * 1.0476 * 1.0493 * 1.0502 * 1.0533 * 1.0910 = 1.64544351855912

          – Joshua
          Sep 18 at 15:14











        • "63% of the gains" may well mean pow(43.00, 0.63) not 43.00 * 0.63. Using this interpretation it would be only a factor of 10.69 not 27.09. Still far above the 1.64 factor from the best 10 days.

          – Ben Voigt
          Sep 18 at 18:56











        • Start with $100, 4300% returns gives you $4400; take out the compounded returns as Joshua calculated and you have $2674 for a return of 2574%. 2574/4300 is 62%, so 38% of the returns are attributable to the top 10 days. That's not the 63% in question, but it's still a significant proportion.

          – Kevin
          Sep 18 at 19:16













        16















        16











        16









        Since the book was written in 1997, the relevant period would be roughly 1947-1996. Yahoo Finance data starts from 1950, so I will look at "last 47 years" instead. Presumably, the finding by Mandelbrot and Taleb is not so trivial that it would no longer apply to even a slightly different time period.



        On Jan 3, 1950 the S&P closed $16.66. On December 31, 1996, it closed $740.74. This is an increase of 4300% in total. The best days were:



        1987-10-21 9.10%
        1987-10-20 5.33%
        1970-05-27 5.02%
        1987-10-29 4.93%
        1982-08-17 4.76%
        1962-05-29 4.65%
        1974-10-09 4.60%
        1957-10-23 4.49%
        1974-10-07 4.19%
        1974-07-12 4.08%


        This sums to 50%. Perhaps what is meant is that if you had only traded on the 10 best days you would make the lion's share of profit. To verify that we can take the product and obtain a 64% increase. So as far as I can tell, the claim as presented appears to be false. Neither Mandelbrot nor Taleb are generally considered fools or charlatans, so I'm assuming something was lost in translation. It is interesting that the 64% I got was very close to the 63% cited.



        63% of 4300% is 2709% (if taking the percent of a percent confuses you, just think of making $4300 for every $100 you put in, and taking 63% of that). To obtain this profit by only trading on the best days, you would need to trade on about 115 days spanning from 1950 to 1991. Interestingly, if you traded on only the best days, your maximum gain would be about 3*10^12% from trading on 10240 of 11826 trading days in the dataset.



        Incidentally, if you traded on 20 worst days, you would lose two thirds of your money. Your outlook only improves if you traded on the worst 10040 days, in which case you also lose two thirds. You can at most miss 140 of the best days if you want to at least break even, assuming you trade on every other day.



        Interesting as it is to debate all this arithmetic, the second part of your question is more useful to discuss:




        Or is it even fair to ask if this is true?




        It doesn't really matter exactly what the numbers are. The authors' point is that there is an exponential distribution in stock market returns, where you make or lose huge sums on a minority of days, while most days don't really affect you one way or the other. Of course, the "long" or "fat" tails in market return distributions are well known. In nature, almost everything is distributed such that extreme events are rare, and common events are small. We do not have many phenomena where most values are very far away from the mean or median, the market is no exception. The debate that Mandelbrot and Taleb are addressing here is with regards to exact probability of a given unlikely event being 10^-9 vs. 10^-10 vs. 0. It may seem like it's academic, but in some cases it can make a big difference. The difference is unlikely to be apparent for a non-technically sophisticated trader.






        share|improve this answer
















        Since the book was written in 1997, the relevant period would be roughly 1947-1996. Yahoo Finance data starts from 1950, so I will look at "last 47 years" instead. Presumably, the finding by Mandelbrot and Taleb is not so trivial that it would no longer apply to even a slightly different time period.



        On Jan 3, 1950 the S&P closed $16.66. On December 31, 1996, it closed $740.74. This is an increase of 4300% in total. The best days were:



        1987-10-21 9.10%
        1987-10-20 5.33%
        1970-05-27 5.02%
        1987-10-29 4.93%
        1982-08-17 4.76%
        1962-05-29 4.65%
        1974-10-09 4.60%
        1957-10-23 4.49%
        1974-10-07 4.19%
        1974-07-12 4.08%


        This sums to 50%. Perhaps what is meant is that if you had only traded on the 10 best days you would make the lion's share of profit. To verify that we can take the product and obtain a 64% increase. So as far as I can tell, the claim as presented appears to be false. Neither Mandelbrot nor Taleb are generally considered fools or charlatans, so I'm assuming something was lost in translation. It is interesting that the 64% I got was very close to the 63% cited.



        63% of 4300% is 2709% (if taking the percent of a percent confuses you, just think of making $4300 for every $100 you put in, and taking 63% of that). To obtain this profit by only trading on the best days, you would need to trade on about 115 days spanning from 1950 to 1991. Interestingly, if you traded on only the best days, your maximum gain would be about 3*10^12% from trading on 10240 of 11826 trading days in the dataset.



        Incidentally, if you traded on 20 worst days, you would lose two thirds of your money. Your outlook only improves if you traded on the worst 10040 days, in which case you also lose two thirds. You can at most miss 140 of the best days if you want to at least break even, assuming you trade on every other day.



        Interesting as it is to debate all this arithmetic, the second part of your question is more useful to discuss:




        Or is it even fair to ask if this is true?




        It doesn't really matter exactly what the numbers are. The authors' point is that there is an exponential distribution in stock market returns, where you make or lose huge sums on a minority of days, while most days don't really affect you one way or the other. Of course, the "long" or "fat" tails in market return distributions are well known. In nature, almost everything is distributed such that extreme events are rare, and common events are small. We do not have many phenomena where most values are very far away from the mean or median, the market is no exception. The debate that Mandelbrot and Taleb are addressing here is with regards to exact probability of a given unlikely event being 10^-9 vs. 10^-10 vs. 0. It may seem like it's academic, but in some cases it can make a big difference. The difference is unlikely to be apparent for a non-technically sophisticated trader.







        share|improve this answer















        share|improve this answer




        share|improve this answer








        edited Sep 19 at 1:49

























        answered Sep 18 at 4:19









        Money AnnMoney Ann

        2,7355 silver badges16 bronze badges




        2,7355 silver badges16 bronze badges















        • Using your figures, for the 10 best days to deliver 63% of the 4300% in returns, they would have daily increases of 46% if they were all equal. As can be seen from the data in this answer (or Justin Cave's answer), there is not a single day (or even a single year) that delivers this kind of return.

          – jcaron
          Sep 18 at 11:57






        • 12





          Hi Ann, please see my answer. You did all the heavy lifting, but came to the wrong conclusion. The key was noting that returns multiply.

          – JTP - Apologise to Monica
          Sep 18 at 12:33






        • 9





          1.0408 * 1.0419 * 1.0449 * 1.0460 * 1.0465 * 1.0476 * 1.0493 * 1.0502 * 1.0533 * 1.0910 = 1.64544351855912

          – Joshua
          Sep 18 at 15:14











        • "63% of the gains" may well mean pow(43.00, 0.63) not 43.00 * 0.63. Using this interpretation it would be only a factor of 10.69 not 27.09. Still far above the 1.64 factor from the best 10 days.

          – Ben Voigt
          Sep 18 at 18:56











        • Start with $100, 4300% returns gives you $4400; take out the compounded returns as Joshua calculated and you have $2674 for a return of 2574%. 2574/4300 is 62%, so 38% of the returns are attributable to the top 10 days. That's not the 63% in question, but it's still a significant proportion.

          – Kevin
          Sep 18 at 19:16

















        • Using your figures, for the 10 best days to deliver 63% of the 4300% in returns, they would have daily increases of 46% if they were all equal. As can be seen from the data in this answer (or Justin Cave's answer), there is not a single day (or even a single year) that delivers this kind of return.

          – jcaron
          Sep 18 at 11:57






        • 12





          Hi Ann, please see my answer. You did all the heavy lifting, but came to the wrong conclusion. The key was noting that returns multiply.

          – JTP - Apologise to Monica
          Sep 18 at 12:33






        • 9





          1.0408 * 1.0419 * 1.0449 * 1.0460 * 1.0465 * 1.0476 * 1.0493 * 1.0502 * 1.0533 * 1.0910 = 1.64544351855912

          – Joshua
          Sep 18 at 15:14











        • "63% of the gains" may well mean pow(43.00, 0.63) not 43.00 * 0.63. Using this interpretation it would be only a factor of 10.69 not 27.09. Still far above the 1.64 factor from the best 10 days.

          – Ben Voigt
          Sep 18 at 18:56











        • Start with $100, 4300% returns gives you $4400; take out the compounded returns as Joshua calculated and you have $2674 for a return of 2574%. 2574/4300 is 62%, so 38% of the returns are attributable to the top 10 days. That's not the 63% in question, but it's still a significant proportion.

          – Kevin
          Sep 18 at 19:16
















        Using your figures, for the 10 best days to deliver 63% of the 4300% in returns, they would have daily increases of 46% if they were all equal. As can be seen from the data in this answer (or Justin Cave's answer), there is not a single day (or even a single year) that delivers this kind of return.

        – jcaron
        Sep 18 at 11:57





        Using your figures, for the 10 best days to deliver 63% of the 4300% in returns, they would have daily increases of 46% if they were all equal. As can be seen from the data in this answer (or Justin Cave's answer), there is not a single day (or even a single year) that delivers this kind of return.

        – jcaron
        Sep 18 at 11:57




        12




        12





        Hi Ann, please see my answer. You did all the heavy lifting, but came to the wrong conclusion. The key was noting that returns multiply.

        – JTP - Apologise to Monica
        Sep 18 at 12:33





        Hi Ann, please see my answer. You did all the heavy lifting, but came to the wrong conclusion. The key was noting that returns multiply.

        – JTP - Apologise to Monica
        Sep 18 at 12:33




        9




        9





        1.0408 * 1.0419 * 1.0449 * 1.0460 * 1.0465 * 1.0476 * 1.0493 * 1.0502 * 1.0533 * 1.0910 = 1.64544351855912

        – Joshua
        Sep 18 at 15:14





        1.0408 * 1.0419 * 1.0449 * 1.0460 * 1.0465 * 1.0476 * 1.0493 * 1.0502 * 1.0533 * 1.0910 = 1.64544351855912

        – Joshua
        Sep 18 at 15:14













        "63% of the gains" may well mean pow(43.00, 0.63) not 43.00 * 0.63. Using this interpretation it would be only a factor of 10.69 not 27.09. Still far above the 1.64 factor from the best 10 days.

        – Ben Voigt
        Sep 18 at 18:56





        "63% of the gains" may well mean pow(43.00, 0.63) not 43.00 * 0.63. Using this interpretation it would be only a factor of 10.69 not 27.09. Still far above the 1.64 factor from the best 10 days.

        – Ben Voigt
        Sep 18 at 18:56













        Start with $100, 4300% returns gives you $4400; take out the compounded returns as Joshua calculated and you have $2674 for a return of 2574%. 2574/4300 is 62%, so 38% of the returns are attributable to the top 10 days. That's not the 63% in question, but it's still a significant proportion.

        – Kevin
        Sep 18 at 19:16





        Start with $100, 4300% returns gives you $4400; take out the compounded returns as Joshua calculated and you have $2674 for a return of 2574%. 2574/4300 is 62%, so 38% of the returns are attributable to the top 10 days. That's not the 63% in question, but it's still a significant proportion.

        – Kevin
        Sep 18 at 19:16











        13



















        Let’s simplify it, our example investment is very boring except for one day when it goes crazy.



        Two investors with same $1,000 initial investment, the market doubles every 7 years except for one day at the end of the first 7 years when it goes up by 50%. The first investor invests for the whole period, the second investor skips just one day.



        Investor 1:



        • Starts with $1,000

        • 7 years later $2,000 (2x)

        • Crazy day with a 50% increase ends with $3,000

        • 28 years later $48,000 (16x)

        Investor 2:



        • Starts with $1,000

        • 7 years later $2,000 (2x)

        • Misses the crazy day but then reenters the market still at $2,000

        • 28 years later $32,000 (16x)

        Investor one sees the initial investment go up 48x or 4700% Investor B sees the value go up by 32X or 3100%. So that 1 day with a 50% would erase about 50% of the gains even though the unlucky investor saw 3100% gain.



        I did find that a similar phrase in an article on the motley fool website




        Time in the market, versus time out of the market



        J.P. Morgan Asset Management's 2019 Retirement Guide shows the impact
        that pulling out of the market has on a portfolio. Looking back over
        the 20-year period from Jan. 1, 1999, to Dec. 31, 2018, if you missed
        the top 10 best days in the stock market, your overall return was cut
        in half. That's a significant difference for only 10 days over two
        decades!




        The JP Morgan study can be found on their website. Page 41 of the report has information.






        share|improve this answer




























        • Nice, easy to follow, example. Sometimes just showing simple numbers, the 50% one time gain, can really make things clear.

          – JTP - Apologise to Monica
          Sep 18 at 16:03















        13



















        Let’s simplify it, our example investment is very boring except for one day when it goes crazy.



        Two investors with same $1,000 initial investment, the market doubles every 7 years except for one day at the end of the first 7 years when it goes up by 50%. The first investor invests for the whole period, the second investor skips just one day.



        Investor 1:



        • Starts with $1,000

        • 7 years later $2,000 (2x)

        • Crazy day with a 50% increase ends with $3,000

        • 28 years later $48,000 (16x)

        Investor 2:



        • Starts with $1,000

        • 7 years later $2,000 (2x)

        • Misses the crazy day but then reenters the market still at $2,000

        • 28 years later $32,000 (16x)

        Investor one sees the initial investment go up 48x or 4700% Investor B sees the value go up by 32X or 3100%. So that 1 day with a 50% would erase about 50% of the gains even though the unlucky investor saw 3100% gain.



        I did find that a similar phrase in an article on the motley fool website




        Time in the market, versus time out of the market



        J.P. Morgan Asset Management's 2019 Retirement Guide shows the impact
        that pulling out of the market has on a portfolio. Looking back over
        the 20-year period from Jan. 1, 1999, to Dec. 31, 2018, if you missed
        the top 10 best days in the stock market, your overall return was cut
        in half. That's a significant difference for only 10 days over two
        decades!




        The JP Morgan study can be found on their website. Page 41 of the report has information.






        share|improve this answer




























        • Nice, easy to follow, example. Sometimes just showing simple numbers, the 50% one time gain, can really make things clear.

          – JTP - Apologise to Monica
          Sep 18 at 16:03













        13















        13











        13









        Let’s simplify it, our example investment is very boring except for one day when it goes crazy.



        Two investors with same $1,000 initial investment, the market doubles every 7 years except for one day at the end of the first 7 years when it goes up by 50%. The first investor invests for the whole period, the second investor skips just one day.



        Investor 1:



        • Starts with $1,000

        • 7 years later $2,000 (2x)

        • Crazy day with a 50% increase ends with $3,000

        • 28 years later $48,000 (16x)

        Investor 2:



        • Starts with $1,000

        • 7 years later $2,000 (2x)

        • Misses the crazy day but then reenters the market still at $2,000

        • 28 years later $32,000 (16x)

        Investor one sees the initial investment go up 48x or 4700% Investor B sees the value go up by 32X or 3100%. So that 1 day with a 50% would erase about 50% of the gains even though the unlucky investor saw 3100% gain.



        I did find that a similar phrase in an article on the motley fool website




        Time in the market, versus time out of the market



        J.P. Morgan Asset Management's 2019 Retirement Guide shows the impact
        that pulling out of the market has on a portfolio. Looking back over
        the 20-year period from Jan. 1, 1999, to Dec. 31, 2018, if you missed
        the top 10 best days in the stock market, your overall return was cut
        in half. That's a significant difference for only 10 days over two
        decades!




        The JP Morgan study can be found on their website. Page 41 of the report has information.






        share|improve this answer
















        Let’s simplify it, our example investment is very boring except for one day when it goes crazy.



        Two investors with same $1,000 initial investment, the market doubles every 7 years except for one day at the end of the first 7 years when it goes up by 50%. The first investor invests for the whole period, the second investor skips just one day.



        Investor 1:



        • Starts with $1,000

        • 7 years later $2,000 (2x)

        • Crazy day with a 50% increase ends with $3,000

        • 28 years later $48,000 (16x)

        Investor 2:



        • Starts with $1,000

        • 7 years later $2,000 (2x)

        • Misses the crazy day but then reenters the market still at $2,000

        • 28 years later $32,000 (16x)

        Investor one sees the initial investment go up 48x or 4700% Investor B sees the value go up by 32X or 3100%. So that 1 day with a 50% would erase about 50% of the gains even though the unlucky investor saw 3100% gain.



        I did find that a similar phrase in an article on the motley fool website




        Time in the market, versus time out of the market



        J.P. Morgan Asset Management's 2019 Retirement Guide shows the impact
        that pulling out of the market has on a portfolio. Looking back over
        the 20-year period from Jan. 1, 1999, to Dec. 31, 2018, if you missed
        the top 10 best days in the stock market, your overall return was cut
        in half. That's a significant difference for only 10 days over two
        decades!




        The JP Morgan study can be found on their website. Page 41 of the report has information.







        share|improve this answer















        share|improve this answer




        share|improve this answer








        edited Sep 18 at 17:30









        JTP - Apologise to Monica

        156k25 gold badges257 silver badges500 bronze badges




        156k25 gold badges257 silver badges500 bronze badges










        answered Sep 18 at 13:05









        mhoran_psprepmhoran_psprep

        79.6k8 gold badges111 silver badges207 bronze badges




        79.6k8 gold badges111 silver badges207 bronze badges















        • Nice, easy to follow, example. Sometimes just showing simple numbers, the 50% one time gain, can really make things clear.

          – JTP - Apologise to Monica
          Sep 18 at 16:03

















        • Nice, easy to follow, example. Sometimes just showing simple numbers, the 50% one time gain, can really make things clear.

          – JTP - Apologise to Monica
          Sep 18 at 16:03
















        Nice, easy to follow, example. Sometimes just showing simple numbers, the 50% one time gain, can really make things clear.

        – JTP - Apologise to Monica
        Sep 18 at 16:03





        Nice, easy to follow, example. Sometimes just showing simple numbers, the 50% one time gain, can really make things clear.

        – JTP - Apologise to Monica
        Sep 18 at 16:03











        10



















        I can't speak to the research methods used in that study but Taleb was likely trying to build on his "black swan" hypothesis by showing that the "black swan" trading days have the biggest impact on the market overall.



        The math behind Mandelbrot's and Taleb's analyses always goes over my head, even though I'm a fan of Taleb's work from a philosophical standpoint.



        Tony Robbins simplified this concept by enforcing the idea that you can't time the stock market. I'm not sure who did the research, but it shows that if you try to time the market and miss out on the top performing days, you ultimately underperform the market.



        enter image description here
        Image source: MarketWatch






        share|improve this answer





















        • 5





          I wonder what the reverse looks like (excluding the worst 10/20/40 days)

          – Ben Voigt
          Sep 17 at 22:05






        • 1





          @BenVoigt That's a good point. I'd love to see that information.

          – daytrader
          Sep 17 at 22:06






        • 1





          The data, easily downloaded back to 1950 on Yahoo, is ready for your analysis. Spreadsheets are my friend.

          – JTP - Apologise to Monica
          Sep 18 at 16:06















        10



















        I can't speak to the research methods used in that study but Taleb was likely trying to build on his "black swan" hypothesis by showing that the "black swan" trading days have the biggest impact on the market overall.



        The math behind Mandelbrot's and Taleb's analyses always goes over my head, even though I'm a fan of Taleb's work from a philosophical standpoint.



        Tony Robbins simplified this concept by enforcing the idea that you can't time the stock market. I'm not sure who did the research, but it shows that if you try to time the market and miss out on the top performing days, you ultimately underperform the market.



        enter image description here
        Image source: MarketWatch






        share|improve this answer





















        • 5





          I wonder what the reverse looks like (excluding the worst 10/20/40 days)

          – Ben Voigt
          Sep 17 at 22:05






        • 1





          @BenVoigt That's a good point. I'd love to see that information.

          – daytrader
          Sep 17 at 22:06






        • 1





          The data, easily downloaded back to 1950 on Yahoo, is ready for your analysis. Spreadsheets are my friend.

          – JTP - Apologise to Monica
          Sep 18 at 16:06













        10















        10











        10









        I can't speak to the research methods used in that study but Taleb was likely trying to build on his "black swan" hypothesis by showing that the "black swan" trading days have the biggest impact on the market overall.



        The math behind Mandelbrot's and Taleb's analyses always goes over my head, even though I'm a fan of Taleb's work from a philosophical standpoint.



        Tony Robbins simplified this concept by enforcing the idea that you can't time the stock market. I'm not sure who did the research, but it shows that if you try to time the market and miss out on the top performing days, you ultimately underperform the market.



        enter image description here
        Image source: MarketWatch






        share|improve this answer














        I can't speak to the research methods used in that study but Taleb was likely trying to build on his "black swan" hypothesis by showing that the "black swan" trading days have the biggest impact on the market overall.



        The math behind Mandelbrot's and Taleb's analyses always goes over my head, even though I'm a fan of Taleb's work from a philosophical standpoint.



        Tony Robbins simplified this concept by enforcing the idea that you can't time the stock market. I'm not sure who did the research, but it shows that if you try to time the market and miss out on the top performing days, you ultimately underperform the market.



        enter image description here
        Image source: MarketWatch







        share|improve this answer













        share|improve this answer




        share|improve this answer










        answered Sep 17 at 21:38









        daytraderdaytrader

        2,0723 silver badges13 bronze badges




        2,0723 silver badges13 bronze badges










        • 5





          I wonder what the reverse looks like (excluding the worst 10/20/40 days)

          – Ben Voigt
          Sep 17 at 22:05






        • 1





          @BenVoigt That's a good point. I'd love to see that information.

          – daytrader
          Sep 17 at 22:06






        • 1





          The data, easily downloaded back to 1950 on Yahoo, is ready for your analysis. Spreadsheets are my friend.

          – JTP - Apologise to Monica
          Sep 18 at 16:06












        • 5





          I wonder what the reverse looks like (excluding the worst 10/20/40 days)

          – Ben Voigt
          Sep 17 at 22:05






        • 1





          @BenVoigt That's a good point. I'd love to see that information.

          – daytrader
          Sep 17 at 22:06






        • 1





          The data, easily downloaded back to 1950 on Yahoo, is ready for your analysis. Spreadsheets are my friend.

          – JTP - Apologise to Monica
          Sep 18 at 16:06







        5




        5





        I wonder what the reverse looks like (excluding the worst 10/20/40 days)

        – Ben Voigt
        Sep 17 at 22:05





        I wonder what the reverse looks like (excluding the worst 10/20/40 days)

        – Ben Voigt
        Sep 17 at 22:05




        1




        1





        @BenVoigt That's a good point. I'd love to see that information.

        – daytrader
        Sep 17 at 22:06





        @BenVoigt That's a good point. I'd love to see that information.

        – daytrader
        Sep 17 at 22:06




        1




        1





        The data, easily downloaded back to 1950 on Yahoo, is ready for your analysis. Spreadsheets are my friend.

        – JTP - Apologise to Monica
        Sep 18 at 16:06





        The data, easily downloaded back to 1950 on Yahoo, is ready for your analysis. Spreadsheets are my friend.

        – JTP - Apologise to Monica
        Sep 18 at 16:06











        0



















        Perhaps true, but not evidence that returns are non-normal. I agree they are not normally distributed but disagree with the reasoning. As others pointed out, if the return of the top ten days is 63%, the claim is true regardless of the the performance of the other days. This can be achieved with a sufficiently volatile normal distribution. If the standard deviation of the returns is low and it is achieved, together it may be evidence of heavy tails. In isolation, it is not.



        The simple script below generates normal returns such that the top 10 days have approximately a 70% return. Adjusting the standard deviation parameter will show the relationship.



        import numpy as np

        n_simulations = 5000
        n_days_per_year = 250
        n_years = 50
        n_days = n_days_per_year*n_years
        mean = 0.1/n_days_per_year
        std_dev = 0.25 / n_days_per_year**0.5

        rnds = np.random.normal(size=(n_days,int(n_simulations/2)))
        rnds = np.concatenate((rnds,-rnds),axis=1) # antithetic

        returns = mean + std_dev*rnds

        sorted_returns = np.array([np.sort(returns[:,i_simulation]) for i_simulation in range(n_simulations)]).T
        top_ten_returns = np.product(1+sorted_returns[-10:,:],0) - 1
        print(np.mean(top_ten_returns))





        share|improve this answer






























          0



















          Perhaps true, but not evidence that returns are non-normal. I agree they are not normally distributed but disagree with the reasoning. As others pointed out, if the return of the top ten days is 63%, the claim is true regardless of the the performance of the other days. This can be achieved with a sufficiently volatile normal distribution. If the standard deviation of the returns is low and it is achieved, together it may be evidence of heavy tails. In isolation, it is not.



          The simple script below generates normal returns such that the top 10 days have approximately a 70% return. Adjusting the standard deviation parameter will show the relationship.



          import numpy as np

          n_simulations = 5000
          n_days_per_year = 250
          n_years = 50
          n_days = n_days_per_year*n_years
          mean = 0.1/n_days_per_year
          std_dev = 0.25 / n_days_per_year**0.5

          rnds = np.random.normal(size=(n_days,int(n_simulations/2)))
          rnds = np.concatenate((rnds,-rnds),axis=1) # antithetic

          returns = mean + std_dev*rnds

          sorted_returns = np.array([np.sort(returns[:,i_simulation]) for i_simulation in range(n_simulations)]).T
          top_ten_returns = np.product(1+sorted_returns[-10:,:],0) - 1
          print(np.mean(top_ten_returns))





          share|improve this answer




























            0















            0











            0









            Perhaps true, but not evidence that returns are non-normal. I agree they are not normally distributed but disagree with the reasoning. As others pointed out, if the return of the top ten days is 63%, the claim is true regardless of the the performance of the other days. This can be achieved with a sufficiently volatile normal distribution. If the standard deviation of the returns is low and it is achieved, together it may be evidence of heavy tails. In isolation, it is not.



            The simple script below generates normal returns such that the top 10 days have approximately a 70% return. Adjusting the standard deviation parameter will show the relationship.



            import numpy as np

            n_simulations = 5000
            n_days_per_year = 250
            n_years = 50
            n_days = n_days_per_year*n_years
            mean = 0.1/n_days_per_year
            std_dev = 0.25 / n_days_per_year**0.5

            rnds = np.random.normal(size=(n_days,int(n_simulations/2)))
            rnds = np.concatenate((rnds,-rnds),axis=1) # antithetic

            returns = mean + std_dev*rnds

            sorted_returns = np.array([np.sort(returns[:,i_simulation]) for i_simulation in range(n_simulations)]).T
            top_ten_returns = np.product(1+sorted_returns[-10:,:],0) - 1
            print(np.mean(top_ten_returns))





            share|improve this answer














            Perhaps true, but not evidence that returns are non-normal. I agree they are not normally distributed but disagree with the reasoning. As others pointed out, if the return of the top ten days is 63%, the claim is true regardless of the the performance of the other days. This can be achieved with a sufficiently volatile normal distribution. If the standard deviation of the returns is low and it is achieved, together it may be evidence of heavy tails. In isolation, it is not.



            The simple script below generates normal returns such that the top 10 days have approximately a 70% return. Adjusting the standard deviation parameter will show the relationship.



            import numpy as np

            n_simulations = 5000
            n_days_per_year = 250
            n_years = 50
            n_days = n_days_per_year*n_years
            mean = 0.1/n_days_per_year
            std_dev = 0.25 / n_days_per_year**0.5

            rnds = np.random.normal(size=(n_days,int(n_simulations/2)))
            rnds = np.concatenate((rnds,-rnds),axis=1) # antithetic

            returns = mean + std_dev*rnds

            sorted_returns = np.array([np.sort(returns[:,i_simulation]) for i_simulation in range(n_simulations)]).T
            top_ten_returns = np.product(1+sorted_returns[-10:,:],0) - 1
            print(np.mean(top_ten_returns))






            share|improve this answer













            share|improve this answer




            share|improve this answer










            answered Sep 20 at 17:54









            Charles FoxCharles Fox

            2,2163 silver badges26 bronze badges




            2,2163 silver badges26 bronze badges
























                0



















                I have seen many claims of this nature. I suspect that most of them have done the arithmetic correctly. What it is being used for here is to claim that the normal distribution is a bad model of reality far from the mean, because events many standard deviations out are much more common than the normal distribution would claim. The normal distribution is very convenient because we have lots of theorems about what happens when things are normally distributed. As long as you stay close to the mean it doesn't matter much which bell shaped curve you use. When you go far out it matters a lot. In real life the tails are always greater than a normal distribution will say.



                The fact that the arithmetic is right doesn't tell us how to react to the fact. It is often cited to tell you not to try to time the market, because if you miss the best 10 days you miss so much of the return. On the other hand, if you miss the 10 worst days your return goes way up. No justification is offered that trying to time the market makes you more likely to miss the great days than miss the terrible days.






                share|improve this answer






























                  0



















                  I have seen many claims of this nature. I suspect that most of them have done the arithmetic correctly. What it is being used for here is to claim that the normal distribution is a bad model of reality far from the mean, because events many standard deviations out are much more common than the normal distribution would claim. The normal distribution is very convenient because we have lots of theorems about what happens when things are normally distributed. As long as you stay close to the mean it doesn't matter much which bell shaped curve you use. When you go far out it matters a lot. In real life the tails are always greater than a normal distribution will say.



                  The fact that the arithmetic is right doesn't tell us how to react to the fact. It is often cited to tell you not to try to time the market, because if you miss the best 10 days you miss so much of the return. On the other hand, if you miss the 10 worst days your return goes way up. No justification is offered that trying to time the market makes you more likely to miss the great days than miss the terrible days.






                  share|improve this answer




























                    0















                    0











                    0









                    I have seen many claims of this nature. I suspect that most of them have done the arithmetic correctly. What it is being used for here is to claim that the normal distribution is a bad model of reality far from the mean, because events many standard deviations out are much more common than the normal distribution would claim. The normal distribution is very convenient because we have lots of theorems about what happens when things are normally distributed. As long as you stay close to the mean it doesn't matter much which bell shaped curve you use. When you go far out it matters a lot. In real life the tails are always greater than a normal distribution will say.



                    The fact that the arithmetic is right doesn't tell us how to react to the fact. It is often cited to tell you not to try to time the market, because if you miss the best 10 days you miss so much of the return. On the other hand, if you miss the 10 worst days your return goes way up. No justification is offered that trying to time the market makes you more likely to miss the great days than miss the terrible days.






                    share|improve this answer














                    I have seen many claims of this nature. I suspect that most of them have done the arithmetic correctly. What it is being used for here is to claim that the normal distribution is a bad model of reality far from the mean, because events many standard deviations out are much more common than the normal distribution would claim. The normal distribution is very convenient because we have lots of theorems about what happens when things are normally distributed. As long as you stay close to the mean it doesn't matter much which bell shaped curve you use. When you go far out it matters a lot. In real life the tails are always greater than a normal distribution will say.



                    The fact that the arithmetic is right doesn't tell us how to react to the fact. It is often cited to tell you not to try to time the market, because if you miss the best 10 days you miss so much of the return. On the other hand, if you miss the 10 worst days your return goes way up. No justification is offered that trying to time the market makes you more likely to miss the great days than miss the terrible days.







                    share|improve this answer













                    share|improve this answer




                    share|improve this answer










                    answered Sep 21 at 2:56









                    Ross MillikanRoss Millikan

                    4802 silver badges7 bronze badges




                    4802 silver badges7 bronze badges
























                        0



















                        Lots of great mathematical exegesis here but looking more widely there seem to be two primary motivations that people have for making these comments about "best days".



                        One is the Nick Taleb point that 'fat tails' mean that the distribution of returns is concentrated (for good or ill) in a few incidents. This seems valid.



                        You will also come across it as an argument against pulling out of the market in periods of volatility. This is not really a valid argument - it rather ignores the point that if you instead caught the "worst days" of the market you would be suffering huge losses. (which is not to say the conclusion is wrong - just the argument)



                        (FYI, if you are interested in long-term stock market returns the go-to-guy is Elroy Dimson - a professor at LBS & the Judge Instittue. He has analysed this across multiple countries and periods).






                        share|improve this answer






























                          0



















                          Lots of great mathematical exegesis here but looking more widely there seem to be two primary motivations that people have for making these comments about "best days".



                          One is the Nick Taleb point that 'fat tails' mean that the distribution of returns is concentrated (for good or ill) in a few incidents. This seems valid.



                          You will also come across it as an argument against pulling out of the market in periods of volatility. This is not really a valid argument - it rather ignores the point that if you instead caught the "worst days" of the market you would be suffering huge losses. (which is not to say the conclusion is wrong - just the argument)



                          (FYI, if you are interested in long-term stock market returns the go-to-guy is Elroy Dimson - a professor at LBS & the Judge Instittue. He has analysed this across multiple countries and periods).






                          share|improve this answer




























                            0















                            0











                            0









                            Lots of great mathematical exegesis here but looking more widely there seem to be two primary motivations that people have for making these comments about "best days".



                            One is the Nick Taleb point that 'fat tails' mean that the distribution of returns is concentrated (for good or ill) in a few incidents. This seems valid.



                            You will also come across it as an argument against pulling out of the market in periods of volatility. This is not really a valid argument - it rather ignores the point that if you instead caught the "worst days" of the market you would be suffering huge losses. (which is not to say the conclusion is wrong - just the argument)



                            (FYI, if you are interested in long-term stock market returns the go-to-guy is Elroy Dimson - a professor at LBS & the Judge Instittue. He has analysed this across multiple countries and periods).






                            share|improve this answer














                            Lots of great mathematical exegesis here but looking more widely there seem to be two primary motivations that people have for making these comments about "best days".



                            One is the Nick Taleb point that 'fat tails' mean that the distribution of returns is concentrated (for good or ill) in a few incidents. This seems valid.



                            You will also come across it as an argument against pulling out of the market in periods of volatility. This is not really a valid argument - it rather ignores the point that if you instead caught the "worst days" of the market you would be suffering huge losses. (which is not to say the conclusion is wrong - just the argument)



                            (FYI, if you are interested in long-term stock market returns the go-to-guy is Elroy Dimson - a professor at LBS & the Judge Instittue. He has analysed this across multiple countries and periods).







                            share|improve this answer













                            share|improve this answer




                            share|improve this answer










                            answered Sep 21 at 9:06









                            Duke BouvierDuke Bouvier

                            4363 bronze badges




                            4363 bronze badges
























                                -1



















                                tl;dr- This claim is false. While it's true that an investor who bought in at the start of each of the top-10 days, then sold at the end of them, could enjoy gains of 64% over a similar investor who didn't participate on those 10 days, it doesn't follow that these top-10 days "represent 63 per cent of the returns of the past 50 years".




                                The claim is incorrect due to a broken frame.



                                Imagine that someone tells you that the best strategy for your financial future is to use a certain strategy for playing poker at a Las Vegas casino. They might be correct about their strategy being optimal, in a frame that assumes that you're going to be betting your financial future at a casino. But, is it then true that the optimal strategy for your financial future involves playing poker in a Las Vegas casino?



                                It's not that the claim about how to play poker is necessarily wrong, but the frame around it is. Likewise, the title of this question asks:




                                Is it true that, “just ten trading days represent 63 per cent of the returns of the past 50 years”?




                                That "63 per cent" figure may come from correctly performed mathematical operations, but the frame suggests that someone who missed those 10 days could only hope to enjoy the remaining 37% of returns over the past 50 years.



                                The problem's that it's generally inappropriate to claim that members of some set constitute some portion of that set's total when that set isn't just adding over positive values. (More about the math at the end of this answer.)



                                For example, going by Wikipedia's numbers, it looks like an investor who skipped the worst-5 days would've applied a ~79.4% gain to their wealth. But does it make sense to attribute ~79.4% of wealth to skipping the worst-5 days while also attributing 63% of the wealth to being present for the best-10 days?




                                Analogy: Did one employee do 90% of a small operation's work?



                                Consider a small company with 25 employees. They do little contract jobs.



                                One employee, Bob, has a minor role as a specialist on 90% of the projects; the other 10% don't involve his area of expertise. Bob then writes on his resume:




                                My efforts represented 90% of the company's productivity during my tenure.




                                Which makes it sound like he did 90% of the work, and everyone else did 10%, right? Clearly he's a top-notch employee!



                                And he's not lying, in the sense of making numbers up. That figure's accurate, for the frame in which it was calculated.



                                The problem's that the frame's broken. This is, it doesn't make sense for Bob to describe his participation in 90% of the projects as having represented 90% of the company's work. It's not that he did the math wrong, it's that the logic behind the model itself is a tad silly.




                                Corrected claim: Investing on the top-10 best days would yield a ~64% return.



                                It seems that, if an investor invested at the start of a day and then pulled out at the end for each of the top-10 days, they'd have applied a factor of ~164%, for a gain of ~64%.



                                Without checking the math or figures, that looks plausible to me. But, assuming it's true, it becomes false if we misrepresent that claim through wording that makes it sound like this is a thing where it's meaningful to attribute 64% of gains to 10 specific days, such that anyone who missed those 10 specific days can only hope to enjoy 36% of gains, or something like that.



                                It's not that someone did the math wrong or messed up calculating the figure; rather, it's that the model frame in which the figure exists is itself broken. The correct solution is to exit that frame.




                                Discussion: Mathematical explanation.



                                When we say that something contributes x% to a total, we're typically working within a framework in which we're adding a bunch of positive values to arrive at a total.



                                We can make these investments additive. Specifically, we can take the natural-logarithm of each day's ratio to arrive at an additive parameter. Then, we can sum those additive parameters up, raise Euler's number to the power of their sum, and that's the total factor.



                                To grab the table from @MoneyAnn's answer, then augment it:



                                 Date +% factor ln(factor)
                                -----------------------------------------------------
                                1987-10-21 0.0910 1.0910 0.0870947068509337
                                1987-10-20 0.0533 1.0533 0.0519280928603591
                                1970-05-27 0.0502 1.0502 0.0489806222216219
                                1987-10-29 0.0493 1.0493 0.0481232751817282
                                1982-08-17 0.0476 1.0476 0.0465018336514199
                                1962-05-29 0.0465 1.0465 0.0454512629039174
                                1974-10-09 0.0460 1.0460 0.0449733656427312
                                1957-10-23 0.0449 1.0449 0.0439211870579281
                                1974-10-07 0.0419 1.0419 0.0410459694360010
                                1974-07-12 0.0408 1.0408 0.0399896482161584
                                ------------------
                                Total: 0.498009964


                                Then exp(0.498009964) is 1.645443519, which recovers that ~1.64-factor, or ~64%, other answers were referring to.



                                However, the broken frame presented in the claim has 2 major problems:



                                1. The factors aren't totaled over all days.
                                  If someone wanted to make a claim like this, then they should've ln(factor)'d all of the days, then divided the sum of those parameters for the top-10 days by the sum of those parameters for all of the days.


                                2. The factors contain negatives.
                                  Some days ended lower than they started. For example, apparently 1987-10-19 had a −20.47% hit, for a ln(factor) ~= ln(1-0.247) ~= -0.231553819. In general, for any factor of less than 1, ln(factor) should be negative.


                                We could try to fix up the numbers to account for Problem #1, but the frame doesn't lend itself to resolving Problem #2.






                                share|improve this answer




























                                • To note it, the original authors were apparently trying to make a point about how distributions could be non-normal. This overall point that they were trying to make is very much correct. It's the specific claim asked about in this question that was so poorly expressed that we may as well disregard it as false.

                                  – Nat
                                  Sep 20 at 21:32
















                                -1



















                                tl;dr- This claim is false. While it's true that an investor who bought in at the start of each of the top-10 days, then sold at the end of them, could enjoy gains of 64% over a similar investor who didn't participate on those 10 days, it doesn't follow that these top-10 days "represent 63 per cent of the returns of the past 50 years".




                                The claim is incorrect due to a broken frame.



                                Imagine that someone tells you that the best strategy for your financial future is to use a certain strategy for playing poker at a Las Vegas casino. They might be correct about their strategy being optimal, in a frame that assumes that you're going to be betting your financial future at a casino. But, is it then true that the optimal strategy for your financial future involves playing poker in a Las Vegas casino?



                                It's not that the claim about how to play poker is necessarily wrong, but the frame around it is. Likewise, the title of this question asks:




                                Is it true that, “just ten trading days represent 63 per cent of the returns of the past 50 years”?




                                That "63 per cent" figure may come from correctly performed mathematical operations, but the frame suggests that someone who missed those 10 days could only hope to enjoy the remaining 37% of returns over the past 50 years.



                                The problem's that it's generally inappropriate to claim that members of some set constitute some portion of that set's total when that set isn't just adding over positive values. (More about the math at the end of this answer.)



                                For example, going by Wikipedia's numbers, it looks like an investor who skipped the worst-5 days would've applied a ~79.4% gain to their wealth. But does it make sense to attribute ~79.4% of wealth to skipping the worst-5 days while also attributing 63% of the wealth to being present for the best-10 days?




                                Analogy: Did one employee do 90% of a small operation's work?



                                Consider a small company with 25 employees. They do little contract jobs.



                                One employee, Bob, has a minor role as a specialist on 90% of the projects; the other 10% don't involve his area of expertise. Bob then writes on his resume:




                                My efforts represented 90% of the company's productivity during my tenure.




                                Which makes it sound like he did 90% of the work, and everyone else did 10%, right? Clearly he's a top-notch employee!



                                And he's not lying, in the sense of making numbers up. That figure's accurate, for the frame in which it was calculated.



                                The problem's that the frame's broken. This is, it doesn't make sense for Bob to describe his participation in 90% of the projects as having represented 90% of the company's work. It's not that he did the math wrong, it's that the logic behind the model itself is a tad silly.




                                Corrected claim: Investing on the top-10 best days would yield a ~64% return.



                                It seems that, if an investor invested at the start of a day and then pulled out at the end for each of the top-10 days, they'd have applied a factor of ~164%, for a gain of ~64%.



                                Without checking the math or figures, that looks plausible to me. But, assuming it's true, it becomes false if we misrepresent that claim through wording that makes it sound like this is a thing where it's meaningful to attribute 64% of gains to 10 specific days, such that anyone who missed those 10 specific days can only hope to enjoy 36% of gains, or something like that.



                                It's not that someone did the math wrong or messed up calculating the figure; rather, it's that the model frame in which the figure exists is itself broken. The correct solution is to exit that frame.




                                Discussion: Mathematical explanation.



                                When we say that something contributes x% to a total, we're typically working within a framework in which we're adding a bunch of positive values to arrive at a total.



                                We can make these investments additive. Specifically, we can take the natural-logarithm of each day's ratio to arrive at an additive parameter. Then, we can sum those additive parameters up, raise Euler's number to the power of their sum, and that's the total factor.



                                To grab the table from @MoneyAnn's answer, then augment it:



                                 Date +% factor ln(factor)
                                -----------------------------------------------------
                                1987-10-21 0.0910 1.0910 0.0870947068509337
                                1987-10-20 0.0533 1.0533 0.0519280928603591
                                1970-05-27 0.0502 1.0502 0.0489806222216219
                                1987-10-29 0.0493 1.0493 0.0481232751817282
                                1982-08-17 0.0476 1.0476 0.0465018336514199
                                1962-05-29 0.0465 1.0465 0.0454512629039174
                                1974-10-09 0.0460 1.0460 0.0449733656427312
                                1957-10-23 0.0449 1.0449 0.0439211870579281
                                1974-10-07 0.0419 1.0419 0.0410459694360010
                                1974-07-12 0.0408 1.0408 0.0399896482161584
                                ------------------
                                Total: 0.498009964


                                Then exp(0.498009964) is 1.645443519, which recovers that ~1.64-factor, or ~64%, other answers were referring to.



                                However, the broken frame presented in the claim has 2 major problems:



                                1. The factors aren't totaled over all days.
                                  If someone wanted to make a claim like this, then they should've ln(factor)'d all of the days, then divided the sum of those parameters for the top-10 days by the sum of those parameters for all of the days.


                                2. The factors contain negatives.
                                  Some days ended lower than they started. For example, apparently 1987-10-19 had a −20.47% hit, for a ln(factor) ~= ln(1-0.247) ~= -0.231553819. In general, for any factor of less than 1, ln(factor) should be negative.


                                We could try to fix up the numbers to account for Problem #1, but the frame doesn't lend itself to resolving Problem #2.






                                share|improve this answer




























                                • To note it, the original authors were apparently trying to make a point about how distributions could be non-normal. This overall point that they were trying to make is very much correct. It's the specific claim asked about in this question that was so poorly expressed that we may as well disregard it as false.

                                  – Nat
                                  Sep 20 at 21:32














                                -1















                                -1











                                -1









                                tl;dr- This claim is false. While it's true that an investor who bought in at the start of each of the top-10 days, then sold at the end of them, could enjoy gains of 64% over a similar investor who didn't participate on those 10 days, it doesn't follow that these top-10 days "represent 63 per cent of the returns of the past 50 years".




                                The claim is incorrect due to a broken frame.



                                Imagine that someone tells you that the best strategy for your financial future is to use a certain strategy for playing poker at a Las Vegas casino. They might be correct about their strategy being optimal, in a frame that assumes that you're going to be betting your financial future at a casino. But, is it then true that the optimal strategy for your financial future involves playing poker in a Las Vegas casino?



                                It's not that the claim about how to play poker is necessarily wrong, but the frame around it is. Likewise, the title of this question asks:




                                Is it true that, “just ten trading days represent 63 per cent of the returns of the past 50 years”?




                                That "63 per cent" figure may come from correctly performed mathematical operations, but the frame suggests that someone who missed those 10 days could only hope to enjoy the remaining 37% of returns over the past 50 years.



                                The problem's that it's generally inappropriate to claim that members of some set constitute some portion of that set's total when that set isn't just adding over positive values. (More about the math at the end of this answer.)



                                For example, going by Wikipedia's numbers, it looks like an investor who skipped the worst-5 days would've applied a ~79.4% gain to their wealth. But does it make sense to attribute ~79.4% of wealth to skipping the worst-5 days while also attributing 63% of the wealth to being present for the best-10 days?




                                Analogy: Did one employee do 90% of a small operation's work?



                                Consider a small company with 25 employees. They do little contract jobs.



                                One employee, Bob, has a minor role as a specialist on 90% of the projects; the other 10% don't involve his area of expertise. Bob then writes on his resume:




                                My efforts represented 90% of the company's productivity during my tenure.




                                Which makes it sound like he did 90% of the work, and everyone else did 10%, right? Clearly he's a top-notch employee!



                                And he's not lying, in the sense of making numbers up. That figure's accurate, for the frame in which it was calculated.



                                The problem's that the frame's broken. This is, it doesn't make sense for Bob to describe his participation in 90% of the projects as having represented 90% of the company's work. It's not that he did the math wrong, it's that the logic behind the model itself is a tad silly.




                                Corrected claim: Investing on the top-10 best days would yield a ~64% return.



                                It seems that, if an investor invested at the start of a day and then pulled out at the end for each of the top-10 days, they'd have applied a factor of ~164%, for a gain of ~64%.



                                Without checking the math or figures, that looks plausible to me. But, assuming it's true, it becomes false if we misrepresent that claim through wording that makes it sound like this is a thing where it's meaningful to attribute 64% of gains to 10 specific days, such that anyone who missed those 10 specific days can only hope to enjoy 36% of gains, or something like that.



                                It's not that someone did the math wrong or messed up calculating the figure; rather, it's that the model frame in which the figure exists is itself broken. The correct solution is to exit that frame.




                                Discussion: Mathematical explanation.



                                When we say that something contributes x% to a total, we're typically working within a framework in which we're adding a bunch of positive values to arrive at a total.



                                We can make these investments additive. Specifically, we can take the natural-logarithm of each day's ratio to arrive at an additive parameter. Then, we can sum those additive parameters up, raise Euler's number to the power of their sum, and that's the total factor.



                                To grab the table from @MoneyAnn's answer, then augment it:



                                 Date +% factor ln(factor)
                                -----------------------------------------------------
                                1987-10-21 0.0910 1.0910 0.0870947068509337
                                1987-10-20 0.0533 1.0533 0.0519280928603591
                                1970-05-27 0.0502 1.0502 0.0489806222216219
                                1987-10-29 0.0493 1.0493 0.0481232751817282
                                1982-08-17 0.0476 1.0476 0.0465018336514199
                                1962-05-29 0.0465 1.0465 0.0454512629039174
                                1974-10-09 0.0460 1.0460 0.0449733656427312
                                1957-10-23 0.0449 1.0449 0.0439211870579281
                                1974-10-07 0.0419 1.0419 0.0410459694360010
                                1974-07-12 0.0408 1.0408 0.0399896482161584
                                ------------------
                                Total: 0.498009964


                                Then exp(0.498009964) is 1.645443519, which recovers that ~1.64-factor, or ~64%, other answers were referring to.



                                However, the broken frame presented in the claim has 2 major problems:



                                1. The factors aren't totaled over all days.
                                  If someone wanted to make a claim like this, then they should've ln(factor)'d all of the days, then divided the sum of those parameters for the top-10 days by the sum of those parameters for all of the days.


                                2. The factors contain negatives.
                                  Some days ended lower than they started. For example, apparently 1987-10-19 had a −20.47% hit, for a ln(factor) ~= ln(1-0.247) ~= -0.231553819. In general, for any factor of less than 1, ln(factor) should be negative.


                                We could try to fix up the numbers to account for Problem #1, but the frame doesn't lend itself to resolving Problem #2.






                                share|improve this answer
















                                tl;dr- This claim is false. While it's true that an investor who bought in at the start of each of the top-10 days, then sold at the end of them, could enjoy gains of 64% over a similar investor who didn't participate on those 10 days, it doesn't follow that these top-10 days "represent 63 per cent of the returns of the past 50 years".




                                The claim is incorrect due to a broken frame.



                                Imagine that someone tells you that the best strategy for your financial future is to use a certain strategy for playing poker at a Las Vegas casino. They might be correct about their strategy being optimal, in a frame that assumes that you're going to be betting your financial future at a casino. But, is it then true that the optimal strategy for your financial future involves playing poker in a Las Vegas casino?



                                It's not that the claim about how to play poker is necessarily wrong, but the frame around it is. Likewise, the title of this question asks:




                                Is it true that, “just ten trading days represent 63 per cent of the returns of the past 50 years”?




                                That "63 per cent" figure may come from correctly performed mathematical operations, but the frame suggests that someone who missed those 10 days could only hope to enjoy the remaining 37% of returns over the past 50 years.



                                The problem's that it's generally inappropriate to claim that members of some set constitute some portion of that set's total when that set isn't just adding over positive values. (More about the math at the end of this answer.)



                                For example, going by Wikipedia's numbers, it looks like an investor who skipped the worst-5 days would've applied a ~79.4% gain to their wealth. But does it make sense to attribute ~79.4% of wealth to skipping the worst-5 days while also attributing 63% of the wealth to being present for the best-10 days?




                                Analogy: Did one employee do 90% of a small operation's work?



                                Consider a small company with 25 employees. They do little contract jobs.



                                One employee, Bob, has a minor role as a specialist on 90% of the projects; the other 10% don't involve his area of expertise. Bob then writes on his resume:




                                My efforts represented 90% of the company's productivity during my tenure.




                                Which makes it sound like he did 90% of the work, and everyone else did 10%, right? Clearly he's a top-notch employee!



                                And he's not lying, in the sense of making numbers up. That figure's accurate, for the frame in which it was calculated.



                                The problem's that the frame's broken. This is, it doesn't make sense for Bob to describe his participation in 90% of the projects as having represented 90% of the company's work. It's not that he did the math wrong, it's that the logic behind the model itself is a tad silly.




                                Corrected claim: Investing on the top-10 best days would yield a ~64% return.



                                It seems that, if an investor invested at the start of a day and then pulled out at the end for each of the top-10 days, they'd have applied a factor of ~164%, for a gain of ~64%.



                                Without checking the math or figures, that looks plausible to me. But, assuming it's true, it becomes false if we misrepresent that claim through wording that makes it sound like this is a thing where it's meaningful to attribute 64% of gains to 10 specific days, such that anyone who missed those 10 specific days can only hope to enjoy 36% of gains, or something like that.



                                It's not that someone did the math wrong or messed up calculating the figure; rather, it's that the model frame in which the figure exists is itself broken. The correct solution is to exit that frame.




                                Discussion: Mathematical explanation.



                                When we say that something contributes x% to a total, we're typically working within a framework in which we're adding a bunch of positive values to arrive at a total.



                                We can make these investments additive. Specifically, we can take the natural-logarithm of each day's ratio to arrive at an additive parameter. Then, we can sum those additive parameters up, raise Euler's number to the power of their sum, and that's the total factor.



                                To grab the table from @MoneyAnn's answer, then augment it:



                                 Date +% factor ln(factor)
                                -----------------------------------------------------
                                1987-10-21 0.0910 1.0910 0.0870947068509337
                                1987-10-20 0.0533 1.0533 0.0519280928603591
                                1970-05-27 0.0502 1.0502 0.0489806222216219
                                1987-10-29 0.0493 1.0493 0.0481232751817282
                                1982-08-17 0.0476 1.0476 0.0465018336514199
                                1962-05-29 0.0465 1.0465 0.0454512629039174
                                1974-10-09 0.0460 1.0460 0.0449733656427312
                                1957-10-23 0.0449 1.0449 0.0439211870579281
                                1974-10-07 0.0419 1.0419 0.0410459694360010
                                1974-07-12 0.0408 1.0408 0.0399896482161584
                                ------------------
                                Total: 0.498009964


                                Then exp(0.498009964) is 1.645443519, which recovers that ~1.64-factor, or ~64%, other answers were referring to.



                                However, the broken frame presented in the claim has 2 major problems:



                                1. The factors aren't totaled over all days.
                                  If someone wanted to make a claim like this, then they should've ln(factor)'d all of the days, then divided the sum of those parameters for the top-10 days by the sum of those parameters for all of the days.


                                2. The factors contain negatives.
                                  Some days ended lower than they started. For example, apparently 1987-10-19 had a −20.47% hit, for a ln(factor) ~= ln(1-0.247) ~= -0.231553819. In general, for any factor of less than 1, ln(factor) should be negative.


                                We could try to fix up the numbers to account for Problem #1, but the frame doesn't lend itself to resolving Problem #2.







                                share|improve this answer















                                share|improve this answer




                                share|improve this answer








                                edited Sep 20 at 21:21

























                                answered Sep 20 at 20:36









                                NatNat

                                1781 gold badge1 silver badge9 bronze badges




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                                • To note it, the original authors were apparently trying to make a point about how distributions could be non-normal. This overall point that they were trying to make is very much correct. It's the specific claim asked about in this question that was so poorly expressed that we may as well disregard it as false.

                                  – Nat
                                  Sep 20 at 21:32


















                                • To note it, the original authors were apparently trying to make a point about how distributions could be non-normal. This overall point that they were trying to make is very much correct. It's the specific claim asked about in this question that was so poorly expressed that we may as well disregard it as false.

                                  – Nat
                                  Sep 20 at 21:32

















                                To note it, the original authors were apparently trying to make a point about how distributions could be non-normal. This overall point that they were trying to make is very much correct. It's the specific claim asked about in this question that was so poorly expressed that we may as well disregard it as false.

                                – Nat
                                Sep 20 at 21:32






                                To note it, the original authors were apparently trying to make a point about how distributions could be non-normal. This overall point that they were trying to make is very much correct. It's the specific claim asked about in this question that was so poorly expressed that we may as well disregard it as false.

                                – Nat
                                Sep 20 at 21:32



















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