Create a magic square of 4-digit numbersMagic square with the position of 8 fixedMagic square with the position of 8 fixedMagic Matrices?The magic square with a holeUnsolved Mysteries: Magic Square of SquaresNo ordinary magic squaremodify a magic square - part IIA challenging Magic SquareCreate a 3x3 Magic Square that uses integers from -10 to -2Albrecht Durer Inspired Magic Square

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Create a magic square of 4-digit numbers


Magic square with the position of 8 fixedMagic square with the position of 8 fixedMagic Matrices?The magic square with a holeUnsolved Mysteries: Magic Square of SquaresNo ordinary magic squaremodify a magic square - part IIA challenging Magic SquareCreate a 3x3 Magic Square that uses integers from -10 to -2Albrecht Durer Inspired Magic Square






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty
margin-bottom:0;

.everyonelovesstackoverflowposition:absolute;height:1px;width:1px;opacity:0;top:0;left:0;pointer-events:none;








7















$begingroup$


Example:




4567 4567 4567

4567 4567 4567

4567 4567 4567



what is magic square? if you add up each diagonal, row and column of
above matrix it will sum upto 13701.




Above is a 3*3 matrix where each entry is the same number. You need to replace the "4567"s with 9 different 4-digit numbers to create a perfect magic square.



Remember that the full square must contain nine of each digit 1, 2, 3, 4, and that all nine entries must be four-digit integers.



You need to use only the four digits 1, 2, 3, 4 to solve the problem so that we won't end up with multiple solutions.



You can use numbers like 1234, 4321, 2211, 2121 and so on. But if you used 4321 once in any of the 9 cells you cannot use it again.



Similar puzzle link.










share|improve this question











$endgroup$










  • 5




    $begingroup$
    I've just made an edit, attempting to make your question more clear/coherent/comprehensible. Please let me know if the question as it's now written is what you intended.
    $endgroup$
    – Rand al'Thor
    Sep 18 at 10:29

















7















$begingroup$


Example:




4567 4567 4567

4567 4567 4567

4567 4567 4567



what is magic square? if you add up each diagonal, row and column of
above matrix it will sum upto 13701.




Above is a 3*3 matrix where each entry is the same number. You need to replace the "4567"s with 9 different 4-digit numbers to create a perfect magic square.



Remember that the full square must contain nine of each digit 1, 2, 3, 4, and that all nine entries must be four-digit integers.



You need to use only the four digits 1, 2, 3, 4 to solve the problem so that we won't end up with multiple solutions.



You can use numbers like 1234, 4321, 2211, 2121 and so on. But if you used 4321 once in any of the 9 cells you cannot use it again.



Similar puzzle link.










share|improve this question











$endgroup$










  • 5




    $begingroup$
    I've just made an edit, attempting to make your question more clear/coherent/comprehensible. Please let me know if the question as it's now written is what you intended.
    $endgroup$
    – Rand al'Thor
    Sep 18 at 10:29













7













7









7


1



$begingroup$


Example:




4567 4567 4567

4567 4567 4567

4567 4567 4567



what is magic square? if you add up each diagonal, row and column of
above matrix it will sum upto 13701.




Above is a 3*3 matrix where each entry is the same number. You need to replace the "4567"s with 9 different 4-digit numbers to create a perfect magic square.



Remember that the full square must contain nine of each digit 1, 2, 3, 4, and that all nine entries must be four-digit integers.



You need to use only the four digits 1, 2, 3, 4 to solve the problem so that we won't end up with multiple solutions.



You can use numbers like 1234, 4321, 2211, 2121 and so on. But if you used 4321 once in any of the 9 cells you cannot use it again.



Similar puzzle link.










share|improve this question











$endgroup$




Example:




4567 4567 4567

4567 4567 4567

4567 4567 4567



what is magic square? if you add up each diagonal, row and column of
above matrix it will sum upto 13701.




Above is a 3*3 matrix where each entry is the same number. You need to replace the "4567"s with 9 different 4-digit numbers to create a perfect magic square.



Remember that the full square must contain nine of each digit 1, 2, 3, 4, and that all nine entries must be four-digit integers.



You need to use only the four digits 1, 2, 3, 4 to solve the problem so that we won't end up with multiple solutions.



You can use numbers like 1234, 4321, 2211, 2121 and so on. But if you used 4321 once in any of the 9 cells you cannot use it again.



Similar puzzle link.







magic-square






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Sep 19 at 6:15







Sayed Mohd Ali

















asked Sep 18 at 10:10









Sayed Mohd AliSayed Mohd Ali

1,2261 silver badge20 bronze badges




1,2261 silver badge20 bronze badges










  • 5




    $begingroup$
    I've just made an edit, attempting to make your question more clear/coherent/comprehensible. Please let me know if the question as it's now written is what you intended.
    $endgroup$
    – Rand al'Thor
    Sep 18 at 10:29












  • 5




    $begingroup$
    I've just made an edit, attempting to make your question more clear/coherent/comprehensible. Please let me know if the question as it's now written is what you intended.
    $endgroup$
    – Rand al'Thor
    Sep 18 at 10:29







5




5




$begingroup$
I've just made an edit, attempting to make your question more clear/coherent/comprehensible. Please let me know if the question as it's now written is what you intended.
$endgroup$
– Rand al'Thor
Sep 18 at 10:29




$begingroup$
I've just made an edit, attempting to make your question more clear/coherent/comprehensible. Please let me know if the question as it's now written is what you intended.
$endgroup$
– Rand al'Thor
Sep 18 at 10:29










3 Answers
3






active

oldest

votes


















11

















$begingroup$

Building on the strategy of Omega Krypton, this is one possibility which also gets the diagonals to sum to the magic total




1214 3134 2324

3334 2224 1114

2124 1314 3234


To clarify, the sum of the numbers in each row, each column and along each diagonal is 6672 (the magic total) and each of the digits 1,2,3,4 appears nine times.




First of all, construct four single digit magic squares...




132

321

213


213

321

132


132

321

213


444

444

444




Then concatenate them to get a 4-digit magic square!






share|improve this answer












$endgroup$














  • $begingroup$
    That is the cleverest way to arrive at a solution that I've yet seen.
    $endgroup$
    – Brandon_J
    Sep 18 at 16:32






  • 1




    $begingroup$
    Wow, the most elegant solution I've seen recently! :)
    $endgroup$
    – user47134
    Sep 18 at 17:16






  • 3




    $begingroup$
    @SayedMohdAli I rather think an explanation of what a magic square is would be up to you as the puzzle-poser. Granted, I don't think it would hurt for hexomino to include the final magic square in his answer.
    $endgroup$
    – Brandon_J
    Sep 18 at 19:44


















1

















$begingroup$

Here is another one




2243 1341 3142
3141 2242 1343
1342 3143 2241




All rows, columns and diagonal sums 6,726 and there is only 9 of each 1, 2, 3, 4



I will edit the explaination later.






share|improve this answer










$endgroup$






















    0

















    $begingroup$


    enter image description here




    I think this is the answer where each number consisting of 4 digits
    with only 1,2,3,4 number and calculation of this 3*3 matrix will be
    equals from each side maybe this the combination of digits which can
    be considered as a magic number.






    share|improve this answer












    $endgroup$










    • 8




      $begingroup$
      Remember that the full square must contain nine of each digit 1, 2, 3, 4
      $endgroup$
      – Omega Krypton
      Sep 18 at 13:09






    • 5




      $begingroup$
      ... and the diagonals don't make the same sum.
      $endgroup$
      – Weather Vane
      Sep 18 at 13:11












    Your Answer








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    3 Answers
    3






    active

    oldest

    votes








    3 Answers
    3






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    11

















    $begingroup$

    Building on the strategy of Omega Krypton, this is one possibility which also gets the diagonals to sum to the magic total




    1214 3134 2324

    3334 2224 1114

    2124 1314 3234


    To clarify, the sum of the numbers in each row, each column and along each diagonal is 6672 (the magic total) and each of the digits 1,2,3,4 appears nine times.




    First of all, construct four single digit magic squares...




    132

    321

    213


    213

    321

    132


    132

    321

    213


    444

    444

    444




    Then concatenate them to get a 4-digit magic square!






    share|improve this answer












    $endgroup$














    • $begingroup$
      That is the cleverest way to arrive at a solution that I've yet seen.
      $endgroup$
      – Brandon_J
      Sep 18 at 16:32






    • 1




      $begingroup$
      Wow, the most elegant solution I've seen recently! :)
      $endgroup$
      – user47134
      Sep 18 at 17:16






    • 3




      $begingroup$
      @SayedMohdAli I rather think an explanation of what a magic square is would be up to you as the puzzle-poser. Granted, I don't think it would hurt for hexomino to include the final magic square in his answer.
      $endgroup$
      – Brandon_J
      Sep 18 at 19:44















    11

















    $begingroup$

    Building on the strategy of Omega Krypton, this is one possibility which also gets the diagonals to sum to the magic total




    1214 3134 2324

    3334 2224 1114

    2124 1314 3234


    To clarify, the sum of the numbers in each row, each column and along each diagonal is 6672 (the magic total) and each of the digits 1,2,3,4 appears nine times.




    First of all, construct four single digit magic squares...




    132

    321

    213


    213

    321

    132


    132

    321

    213


    444

    444

    444




    Then concatenate them to get a 4-digit magic square!






    share|improve this answer












    $endgroup$














    • $begingroup$
      That is the cleverest way to arrive at a solution that I've yet seen.
      $endgroup$
      – Brandon_J
      Sep 18 at 16:32






    • 1




      $begingroup$
      Wow, the most elegant solution I've seen recently! :)
      $endgroup$
      – user47134
      Sep 18 at 17:16






    • 3




      $begingroup$
      @SayedMohdAli I rather think an explanation of what a magic square is would be up to you as the puzzle-poser. Granted, I don't think it would hurt for hexomino to include the final magic square in his answer.
      $endgroup$
      – Brandon_J
      Sep 18 at 19:44













    11















    11











    11







    $begingroup$

    Building on the strategy of Omega Krypton, this is one possibility which also gets the diagonals to sum to the magic total




    1214 3134 2324

    3334 2224 1114

    2124 1314 3234


    To clarify, the sum of the numbers in each row, each column and along each diagonal is 6672 (the magic total) and each of the digits 1,2,3,4 appears nine times.




    First of all, construct four single digit magic squares...




    132

    321

    213


    213

    321

    132


    132

    321

    213


    444

    444

    444




    Then concatenate them to get a 4-digit magic square!






    share|improve this answer












    $endgroup$



    Building on the strategy of Omega Krypton, this is one possibility which also gets the diagonals to sum to the magic total




    1214 3134 2324

    3334 2224 1114

    2124 1314 3234


    To clarify, the sum of the numbers in each row, each column and along each diagonal is 6672 (the magic total) and each of the digits 1,2,3,4 appears nine times.




    First of all, construct four single digit magic squares...




    132

    321

    213


    213

    321

    132


    132

    321

    213


    444

    444

    444




    Then concatenate them to get a 4-digit magic square!







    share|improve this answer















    share|improve this answer




    share|improve this answer








    edited Sep 18 at 20:09

























    answered Sep 18 at 16:13









    hexominohexomino

    69.6k6 gold badges194 silver badges300 bronze badges




    69.6k6 gold badges194 silver badges300 bronze badges














    • $begingroup$
      That is the cleverest way to arrive at a solution that I've yet seen.
      $endgroup$
      – Brandon_J
      Sep 18 at 16:32






    • 1




      $begingroup$
      Wow, the most elegant solution I've seen recently! :)
      $endgroup$
      – user47134
      Sep 18 at 17:16






    • 3




      $begingroup$
      @SayedMohdAli I rather think an explanation of what a magic square is would be up to you as the puzzle-poser. Granted, I don't think it would hurt for hexomino to include the final magic square in his answer.
      $endgroup$
      – Brandon_J
      Sep 18 at 19:44
















    • $begingroup$
      That is the cleverest way to arrive at a solution that I've yet seen.
      $endgroup$
      – Brandon_J
      Sep 18 at 16:32






    • 1




      $begingroup$
      Wow, the most elegant solution I've seen recently! :)
      $endgroup$
      – user47134
      Sep 18 at 17:16






    • 3




      $begingroup$
      @SayedMohdAli I rather think an explanation of what a magic square is would be up to you as the puzzle-poser. Granted, I don't think it would hurt for hexomino to include the final magic square in his answer.
      $endgroup$
      – Brandon_J
      Sep 18 at 19:44















    $begingroup$
    That is the cleverest way to arrive at a solution that I've yet seen.
    $endgroup$
    – Brandon_J
    Sep 18 at 16:32




    $begingroup$
    That is the cleverest way to arrive at a solution that I've yet seen.
    $endgroup$
    – Brandon_J
    Sep 18 at 16:32




    1




    1




    $begingroup$
    Wow, the most elegant solution I've seen recently! :)
    $endgroup$
    – user47134
    Sep 18 at 17:16




    $begingroup$
    Wow, the most elegant solution I've seen recently! :)
    $endgroup$
    – user47134
    Sep 18 at 17:16




    3




    3




    $begingroup$
    @SayedMohdAli I rather think an explanation of what a magic square is would be up to you as the puzzle-poser. Granted, I don't think it would hurt for hexomino to include the final magic square in his answer.
    $endgroup$
    – Brandon_J
    Sep 18 at 19:44




    $begingroup$
    @SayedMohdAli I rather think an explanation of what a magic square is would be up to you as the puzzle-poser. Granted, I don't think it would hurt for hexomino to include the final magic square in his answer.
    $endgroup$
    – Brandon_J
    Sep 18 at 19:44













    1

















    $begingroup$

    Here is another one




    2243 1341 3142
    3141 2242 1343
    1342 3143 2241




    All rows, columns and diagonal sums 6,726 and there is only 9 of each 1, 2, 3, 4



    I will edit the explaination later.






    share|improve this answer










    $endgroup$



















      1

















      $begingroup$

      Here is another one




      2243 1341 3142
      3141 2242 1343
      1342 3143 2241




      All rows, columns and diagonal sums 6,726 and there is only 9 of each 1, 2, 3, 4



      I will edit the explaination later.






      share|improve this answer










      $endgroup$

















        1















        1











        1







        $begingroup$

        Here is another one




        2243 1341 3142
        3141 2242 1343
        1342 3143 2241




        All rows, columns and diagonal sums 6,726 and there is only 9 of each 1, 2, 3, 4



        I will edit the explaination later.






        share|improve this answer










        $endgroup$



        Here is another one




        2243 1341 3142
        3141 2242 1343
        1342 3143 2241




        All rows, columns and diagonal sums 6,726 and there is only 9 of each 1, 2, 3, 4



        I will edit the explaination later.







        share|improve this answer













        share|improve this answer




        share|improve this answer










        answered Sep 19 at 8:08









        Pʀıncess AnayaPʀıncess Anaya

        4507 bronze badges




        4507 bronze badges
























            0

















            $begingroup$


            enter image description here




            I think this is the answer where each number consisting of 4 digits
            with only 1,2,3,4 number and calculation of this 3*3 matrix will be
            equals from each side maybe this the combination of digits which can
            be considered as a magic number.






            share|improve this answer












            $endgroup$










            • 8




              $begingroup$
              Remember that the full square must contain nine of each digit 1, 2, 3, 4
              $endgroup$
              – Omega Krypton
              Sep 18 at 13:09






            • 5




              $begingroup$
              ... and the diagonals don't make the same sum.
              $endgroup$
              – Weather Vane
              Sep 18 at 13:11















            0

















            $begingroup$


            enter image description here




            I think this is the answer where each number consisting of 4 digits
            with only 1,2,3,4 number and calculation of this 3*3 matrix will be
            equals from each side maybe this the combination of digits which can
            be considered as a magic number.






            share|improve this answer












            $endgroup$










            • 8




              $begingroup$
              Remember that the full square must contain nine of each digit 1, 2, 3, 4
              $endgroup$
              – Omega Krypton
              Sep 18 at 13:09






            • 5




              $begingroup$
              ... and the diagonals don't make the same sum.
              $endgroup$
              – Weather Vane
              Sep 18 at 13:11













            0















            0











            0







            $begingroup$


            enter image description here




            I think this is the answer where each number consisting of 4 digits
            with only 1,2,3,4 number and calculation of this 3*3 matrix will be
            equals from each side maybe this the combination of digits which can
            be considered as a magic number.






            share|improve this answer












            $endgroup$




            enter image description here




            I think this is the answer where each number consisting of 4 digits
            with only 1,2,3,4 number and calculation of this 3*3 matrix will be
            equals from each side maybe this the combination of digits which can
            be considered as a magic number.







            share|improve this answer















            share|improve this answer




            share|improve this answer








            edited Sep 18 at 16:31









            Brandon_J

            8,1921 gold badge9 silver badges60 bronze badges




            8,1921 gold badge9 silver badges60 bronze badges










            answered Sep 18 at 13:08









            ankitkanojiaankitkanojia

            1172 bronze badges




            1172 bronze badges










            • 8




              $begingroup$
              Remember that the full square must contain nine of each digit 1, 2, 3, 4
              $endgroup$
              – Omega Krypton
              Sep 18 at 13:09






            • 5




              $begingroup$
              ... and the diagonals don't make the same sum.
              $endgroup$
              – Weather Vane
              Sep 18 at 13:11












            • 8




              $begingroup$
              Remember that the full square must contain nine of each digit 1, 2, 3, 4
              $endgroup$
              – Omega Krypton
              Sep 18 at 13:09






            • 5




              $begingroup$
              ... and the diagonals don't make the same sum.
              $endgroup$
              – Weather Vane
              Sep 18 at 13:11







            8




            8




            $begingroup$
            Remember that the full square must contain nine of each digit 1, 2, 3, 4
            $endgroup$
            – Omega Krypton
            Sep 18 at 13:09




            $begingroup$
            Remember that the full square must contain nine of each digit 1, 2, 3, 4
            $endgroup$
            – Omega Krypton
            Sep 18 at 13:09




            5




            5




            $begingroup$
            ... and the diagonals don't make the same sum.
            $endgroup$
            – Weather Vane
            Sep 18 at 13:11




            $begingroup$
            ... and the diagonals don't make the same sum.
            $endgroup$
            – Weather Vane
            Sep 18 at 13:11


















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