Bash, command to variable (cat), output is on 1 line, is not workingHow can I delete a file if it starts with <html> in bash?Disappearing files in the cat commandStore grive command output to variable in bash scriptbash send output from command to variableNumbering paragraphs with the 'cat' commandBash with cat for automatic merging pair of filesGiving cat output to rmCat command with variable in file name not working
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Bash, command to variable (cat), output is on 1 line,
is not workingHow can I delete a file if it starts with <html> in bash?Disappearing files in the cat commandStore grive command output to variable in bash scriptbash send output from command to variableNumbering paragraphs with the 'cat' commandBash with cat for automatic merging pair of filesGiving cat output to rmCat command with variable in file name not working
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty
margin-bottom:0;
2
Issue
In bash, output is on 1 line from command, so
<pre>is not working inhtmltag.log=`cat ../local/log/$(ls -t ../local/log | head -1 )`
echo '
<tr style="background-color: rgb(250,240,240);">
<td style="padding: 10px; text-align: center;"><pre>'$log'</pre></td>
</tr>
' > itf-check-article.htmlHow can I do get output to variable as classic line by line, not in one line?
Thanks.
Update.
Command.
log=`cat ../local/log/$(ls -t ../local/log | head -1 )`; echo $log.Output (1 line).
Start of processing orders. 0 order(s) in this run. No orders in this runBut this command shows me this (with 2 lines).
itfstage@vm14258:~/sofimon$ cat ../local/log/UNIHOBBY_ITF_ORDERS.log
Start of processing orders. 0 order(s) in this run.
No orders in this run
itfstage@vm14258:~/sofimon$
bash cat
asked Sep 30 at 8:39
genderbeegenderbee
5429 bronze badges
add a comment
|
2
Issue
In bash, output is on 1 line from command, so
<pre>is not working inhtmltag.log=`cat ../local/log/$(ls -t ../local/log | head -1 )`
echo '
<tr style="background-color: rgb(250,240,240);">
<td style="padding: 10px; text-align: center;"><pre>'$log'</pre></td>
</tr>
' > itf-check-article.htmlHow can I do get output to variable as classic line by line, not in one line?
Thanks.
Update.
Command.
log=`cat ../local/log/$(ls -t ../local/log | head -1 )`; echo $log.Output (1 line).
Start of processing orders. 0 order(s) in this run. No orders in this runBut this command shows me this (with 2 lines).
itfstage@vm14258:~/sofimon$ cat ../local/log/UNIHOBBY_ITF_ORDERS.log
Start of processing orders. 0 order(s) in this run.
No orders in this run
itfstage@vm14258:~/sofimon$
bash cat
asked Sep 30 at 8:39
genderbeegenderbee
5429 bronze badges
What is the usage of the first line? Can you put the output ofecho "$log"after the 1st line is executed in your question.
– FedonKadifeli
Sep 30 at 9:00
You question is not clear. But, I think you need double quotes around$loglike this:...<pre>'"$log"'</pre>
– FedonKadifeli
Sep 30 at 9:16
add a comment
|
2
2
2
Issue
In bash, output is on 1 line from command, so
<pre>is not working inhtmltag.log=`cat ../local/log/$(ls -t ../local/log | head -1 )`
echo '
<tr style="background-color: rgb(250,240,240);">
<td style="padding: 10px; text-align: center;"><pre>'$log'</pre></td>
</tr>
' > itf-check-article.htmlHow can I do get output to variable as classic line by line, not in one line?
Thanks.
Update.
Command.
log=`cat ../local/log/$(ls -t ../local/log | head -1 )`; echo $log.Output (1 line).
Start of processing orders. 0 order(s) in this run. No orders in this runBut this command shows me this (with 2 lines).
itfstage@vm14258:~/sofimon$ cat ../local/log/UNIHOBBY_ITF_ORDERS.log
Start of processing orders. 0 order(s) in this run.
No orders in this run
itfstage@vm14258:~/sofimon$
bash cat
asked Sep 30 at 8:39
genderbeegenderbee
5429 bronze badges
Issue
In bash, output is on 1 line from command, so
<pre>is not working inhtmltag.log=`cat ../local/log/$(ls -t ../local/log | head -1 )`
echo '
<tr style="background-color: rgb(250,240,240);">
<td style="padding: 10px; text-align: center;"><pre>'$log'</pre></td>
</tr>
' > itf-check-article.htmlHow can I do get output to variable as classic line by line, not in one line?
Thanks.
Update.
Command.
log=`cat ../local/log/$(ls -t ../local/log | head -1 )`; echo $log.Output (1 line).
Start of processing orders. 0 order(s) in this run. No orders in this runBut this command shows me this (with 2 lines).
itfstage@vm14258:~/sofimon$ cat ../local/log/UNIHOBBY_ITF_ORDERS.log
Start of processing orders. 0 order(s) in this run.
No orders in this run
itfstage@vm14258:~/sofimon$
bash cat
bash cat
asked Sep 30 at 8:39
genderbeegenderbee
5429 bronze badges
asked Sep 30 at 8:39
genderbeegenderbee
5429 bronze badges
edited Sep 30 at 9:16
genderbee
asked Sep 30 at 8:39
genderbeegenderbee
5429 bronze badges
asked Sep 30 at 8:39
genderbeegenderbee
5429 bronze badges
asked Sep 30 at 8:39
genderbeegenderbee
5429 bronze badges
5429 bronze badges
What is the usage of the first line? Can you put the output ofecho "$log"after the 1st line is executed in your question.
– FedonKadifeli
Sep 30 at 9:00
You question is not clear. But, I think you need double quotes around$loglike this:...<pre>'"$log"'</pre>
– FedonKadifeli
Sep 30 at 9:16
add a comment
|
What is the usage of the first line? Can you put the output ofecho "$log"after the 1st line is executed in your question.
– FedonKadifeli
Sep 30 at 9:00
You question is not clear. But, I think you need double quotes around$loglike this:...<pre>'"$log"'</pre>
– FedonKadifeli
Sep 30 at 9:16
What is the usage of the first line? Can you put the output ofecho "$log"after the 1st line is executed in your question.
– FedonKadifeli
Sep 30 at 9:00
What is the usage of the first line? Can you put the output ofecho "$log"after the 1st line is executed in your question.
– FedonKadifeli
Sep 30 at 9:00
You question is not clear. But, I think you need double quotes around$loglike this:...<pre>'"$log"'</pre>
– FedonKadifeli
Sep 30 at 9:16
You question is not clear. But, I think you need double quotes around$loglike this:...<pre>'"$log"'</pre>
– FedonKadifeli
Sep 30 at 9:16
add a comment
|
3 Answers
3
active
oldest
votes
2
When a Bash variable contains multiple lines and you want to output it with
echoas it is; you need to put double quotes (") around the variable. For example:echo '
.......<pre>
'"$log"'
</pre>...
' > ...If you put double quotes, the
echocommand will consider it as a single (whose contents happen to contain a multi-line string) parameter. If you don't put double quotes the contents of the string will be split (by Bash) into multiple parameters whenever a white-space (space, tab, newline, etc.) occurs.For example:
$ var='a b c'
$ echo $var
a b c
$ echo "$var"
a b cNote, the first
echowill get three parameters ('a','b', and'c') and will output them by separating with a single space. The secondechowill get a single parameter ('a b c') and will output it as it is.
answered Sep 30 at 9:20
FedonKadifeliFedonKadifeli
1,6391 gold badge7 silver badges24 bronze badges
Yes! You are right. What is difference if I don't use"? Thanks.
– genderbee
Sep 30 at 9:21
add a comment
|
0
Your pre-tag is working fine. Your problem is that $log contains the output of cat on one line. Instead of trying to fix this, I would suggest you split this code into simpler steps.
First of all, this line:
log=`cat ../local/log/$(ls -t ../local/log | head -1 )`Is way to complicated because it nests two command substitutions with two different syntaxes. You might understand it today, but why not split this into two steps so you or one of your co-workers will understand it a year from now:
logfile=../local/log/$(ls -t ../local/log | head -1)
logtext=$(cat $logfile)Or even better (assuming the logfiles end in .log):
logfile=$(ls -t ../local/log/*.log | head -1)
logtext=$(cat $logfile)Now you see that you just put the contents of $logile into $logtext. You seem to want to output the content of $logfile between the pre-tags, just like it appears in the file. With the simplified commands above, it may appear obvious that putting it into $logtext is an extra step that isn't even needed. Just
catthe file where you want it to appear. The backticks or the $()-construct is meant to feed one command with arguments that are created from the output of another. In this case that just messes it all up.So what you could do is this:
outputfile=itf-check-article.html
logfile=$(ls -t ../local/log/*.log | head -1)
echo '<tr style="background-color: rgb(250,240,240);">' > $outputfile
echo '<td style="padding: 10px; text-align: center;"><pre>' >> $outputfile
cat $logfile >> $outputfile
echo '</pre></td></tr>' >> $outputfileor simply run the commands between brackets
()to start a subshell with one redirect statement instead:outputfile=itf-check-article.html
logfile=$(ls -t ../local/log/*.log | head -1)
(
echo '<tr style="background-color: rgb(250,240,240);">'
echo '<td style="padding: 10px; text-align: center;"><pre>'
cat $logfile
echo '</pre></td></tr>'
) > $outputfile
answered Sep 30 at 11:10
OscarOscar
1628 bronze badges
Ok, maybe it is better to have it separately. But what is difference between 'command' and$(command)and when it is better use one method and when second method. Thanks.
– genderbee
Sep 30 at 11:50
@genderbee, there is no difference, except you can't nest these backticks. However you ou could easily doecho $(echo $(echo $(echo Bazinga!)))if you enjoy spawning three subshells just for fun.
– Oscar
Sep 30 at 12:12
Bazinga......! :)
– genderbee
Sep 30 at 12:14
@genderbee, as for the second part of your question: it depends on how you define "better". Often "easier to understand for the human reading it" counts as better than "clever demonstration of all your knowledge packed into one complex statement"
– Oscar
Sep 30 at 12:15
add a comment
|
0
special-purpose code block (here doc).
#!/bin/bash
cat > itf-check-article.html <<PRE
<tr style="background-color: rgb(250,240,240);">
<td style="padding: 10px; text-align: center;"><pre>$(awk 'printf "%s<br/>",$0' $(ls -td ../local/log/* | head -n 1))</pre></td>
</tr>
PREoutput:
$ cat itf-check-article.html
<tr style="background-color: rgb(250,240,240);">
<td style="padding: 10px; text-align: center;"><pre>Start of processing orders. 0 order(s) in this run.<br/>No orders in this run<br/></pre></td>
</tr>Using += operator to append to variable.
#!/bin/bash
declare html
html+='<tr style="background-color: rgb(250,240,240);">n'
html+='<td style="padding: 10px; text-align: center;"><pre>'
html+=$(awk 'printf "%s<br/>",$0' $(ls -td ../local/log/* | head -n 1))
html+='</pre></td>n'
html+='</tr>'
echo -e "$html" > itf-check-article.html
answered Sep 30 at 9:38
bac0nbac0n
1,1531 silver badge13 bronze badges
add a comment
|
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
When a Bash variable contains multiple lines and you want to output it with
echoas it is; you need to put double quotes (") around the variable. For example:echo '
.......<pre>
'"$log"'
</pre>...
' > ...If you put double quotes, the
echocommand will consider it as a single (whose contents happen to contain a multi-line string) parameter. If you don't put double quotes the contents of the string will be split (by Bash) into multiple parameters whenever a white-space (space, tab, newline, etc.) occurs.For example:
$ var='a b c'
$ echo $var
a b c
$ echo "$var"
a b cNote, the first
echowill get three parameters ('a','b', and'c') and will output them by separating with a single space. The secondechowill get a single parameter ('a b c') and will output it as it is.
answered Sep 30 at 9:20
FedonKadifeliFedonKadifeli
1,6391 gold badge7 silver badges24 bronze badges
Yes! You are right. What is difference if I don't use"? Thanks.
– genderbee
Sep 30 at 9:21
add a comment
|
2
When a Bash variable contains multiple lines and you want to output it with
echoas it is; you need to put double quotes (") around the variable. For example:echo '
.......<pre>
'"$log"'
</pre>...
' > ...If you put double quotes, the
echocommand will consider it as a single (whose contents happen to contain a multi-line string) parameter. If you don't put double quotes the contents of the string will be split (by Bash) into multiple parameters whenever a white-space (space, tab, newline, etc.) occurs.For example:
$ var='a b c'
$ echo $var
a b c
$ echo "$var"
a b cNote, the first
echowill get three parameters ('a','b', and'c') and will output them by separating with a single space. The secondechowill get a single parameter ('a b c') and will output it as it is.
answered Sep 30 at 9:20
FedonKadifeliFedonKadifeli
1,6391 gold badge7 silver badges24 bronze badges
Yes! You are right. What is difference if I don't use"? Thanks.
– genderbee
Sep 30 at 9:21
add a comment
|
2
2
2
When a Bash variable contains multiple lines and you want to output it with
echoas it is; you need to put double quotes (") around the variable. For example:echo '
.......<pre>
'"$log"'
</pre>...
' > ...If you put double quotes, the
echocommand will consider it as a single (whose contents happen to contain a multi-line string) parameter. If you don't put double quotes the contents of the string will be split (by Bash) into multiple parameters whenever a white-space (space, tab, newline, etc.) occurs.For example:
$ var='a b c'
$ echo $var
a b c
$ echo "$var"
a b cNote, the first
echowill get three parameters ('a','b', and'c') and will output them by separating with a single space. The secondechowill get a single parameter ('a b c') and will output it as it is.
answered Sep 30 at 9:20
FedonKadifeliFedonKadifeli
1,6391 gold badge7 silver badges24 bronze badges
When a Bash variable contains multiple lines and you want to output it with
echoas it is; you need to put double quotes (") around the variable. For example:echo '
.......<pre>
'"$log"'
</pre>...
' > ...If you put double quotes, the
echocommand will consider it as a single (whose contents happen to contain a multi-line string) parameter. If you don't put double quotes the contents of the string will be split (by Bash) into multiple parameters whenever a white-space (space, tab, newline, etc.) occurs.For example:
$ var='a b c'
$ echo $var
a b c
$ echo "$var"
a b cNote, the first
echowill get three parameters ('a','b', and'c') and will output them by separating with a single space. The secondechowill get a single parameter ('a b c') and will output it as it is.
answered Sep 30 at 9:20
FedonKadifeliFedonKadifeli
1,6391 gold badge7 silver badges24 bronze badges
edited Sep 30 at 9:26
answered Sep 30 at 9:20
FedonKadifeliFedonKadifeli
1,6391 gold badge7 silver badges24 bronze badges
answered Sep 30 at 9:20
FedonKadifeliFedonKadifeli
1,6391 gold badge7 silver badges24 bronze badges
answered Sep 30 at 9:20
FedonKadifeliFedonKadifeli
1,6391 gold badge7 silver badges24 bronze badges
1,6391 gold badge7 silver badges24 bronze badges
Yes! You are right. What is difference if I don't use"? Thanks.
– genderbee
Sep 30 at 9:21
add a comment
|
Yes! You are right. What is difference if I don't use"? Thanks.
– genderbee
Sep 30 at 9:21
Yes! You are right. What is difference if I don't use"? Thanks.
– genderbee
Sep 30 at 9:21
Yes! You are right. What is difference if I don't use"? Thanks.
– genderbee
Sep 30 at 9:21
add a comment
|
0
Your pre-tag is working fine. Your problem is that $log contains the output of cat on one line. Instead of trying to fix this, I would suggest you split this code into simpler steps.
First of all, this line:
log=`cat ../local/log/$(ls -t ../local/log | head -1 )`Is way to complicated because it nests two command substitutions with two different syntaxes. You might understand it today, but why not split this into two steps so you or one of your co-workers will understand it a year from now:
logfile=../local/log/$(ls -t ../local/log | head -1)
logtext=$(cat $logfile)Or even better (assuming the logfiles end in .log):
logfile=$(ls -t ../local/log/*.log | head -1)
logtext=$(cat $logfile)Now you see that you just put the contents of $logile into $logtext. You seem to want to output the content of $logfile between the pre-tags, just like it appears in the file. With the simplified commands above, it may appear obvious that putting it into $logtext is an extra step that isn't even needed. Just
catthe file where you want it to appear. The backticks or the $()-construct is meant to feed one command with arguments that are created from the output of another. In this case that just messes it all up.So what you could do is this:
outputfile=itf-check-article.html
logfile=$(ls -t ../local/log/*.log | head -1)
echo '<tr style="background-color: rgb(250,240,240);">' > $outputfile
echo '<td style="padding: 10px; text-align: center;"><pre>' >> $outputfile
cat $logfile >> $outputfile
echo '</pre></td></tr>' >> $outputfileor simply run the commands between brackets
()to start a subshell with one redirect statement instead:outputfile=itf-check-article.html
logfile=$(ls -t ../local/log/*.log | head -1)
(
echo '<tr style="background-color: rgb(250,240,240);">'
echo '<td style="padding: 10px; text-align: center;"><pre>'
cat $logfile
echo '</pre></td></tr>'
) > $outputfile
answered Sep 30 at 11:10
OscarOscar
1628 bronze badges
Ok, maybe it is better to have it separately. But what is difference between 'command' and$(command)and when it is better use one method and when second method. Thanks.
– genderbee
Sep 30 at 11:50
@genderbee, there is no difference, except you can't nest these backticks. However you ou could easily doecho $(echo $(echo $(echo Bazinga!)))if you enjoy spawning three subshells just for fun.
– Oscar
Sep 30 at 12:12
Bazinga......! :)
– genderbee
Sep 30 at 12:14
@genderbee, as for the second part of your question: it depends on how you define "better". Often "easier to understand for the human reading it" counts as better than "clever demonstration of all your knowledge packed into one complex statement"
– Oscar
Sep 30 at 12:15
add a comment
|
0
Your pre-tag is working fine. Your problem is that $log contains the output of cat on one line. Instead of trying to fix this, I would suggest you split this code into simpler steps.
First of all, this line:
log=`cat ../local/log/$(ls -t ../local/log | head -1 )`Is way to complicated because it nests two command substitutions with two different syntaxes. You might understand it today, but why not split this into two steps so you or one of your co-workers will understand it a year from now:
logfile=../local/log/$(ls -t ../local/log | head -1)
logtext=$(cat $logfile)Or even better (assuming the logfiles end in .log):
logfile=$(ls -t ../local/log/*.log | head -1)
logtext=$(cat $logfile)Now you see that you just put the contents of $logile into $logtext. You seem to want to output the content of $logfile between the pre-tags, just like it appears in the file. With the simplified commands above, it may appear obvious that putting it into $logtext is an extra step that isn't even needed. Just
catthe file where you want it to appear. The backticks or the $()-construct is meant to feed one command with arguments that are created from the output of another. In this case that just messes it all up.So what you could do is this:
outputfile=itf-check-article.html
logfile=$(ls -t ../local/log/*.log | head -1)
echo '<tr style="background-color: rgb(250,240,240);">' > $outputfile
echo '<td style="padding: 10px; text-align: center;"><pre>' >> $outputfile
cat $logfile >> $outputfile
echo '</pre></td></tr>' >> $outputfileor simply run the commands between brackets
()to start a subshell with one redirect statement instead:outputfile=itf-check-article.html
logfile=$(ls -t ../local/log/*.log | head -1)
(
echo '<tr style="background-color: rgb(250,240,240);">'
echo '<td style="padding: 10px; text-align: center;"><pre>'
cat $logfile
echo '</pre></td></tr>'
) > $outputfile
answered Sep 30 at 11:10
OscarOscar
1628 bronze badges
Ok, maybe it is better to have it separately. But what is difference between 'command' and$(command)and when it is better use one method and when second method. Thanks.
– genderbee
Sep 30 at 11:50
@genderbee, there is no difference, except you can't nest these backticks. However you ou could easily doecho $(echo $(echo $(echo Bazinga!)))if you enjoy spawning three subshells just for fun.
– Oscar
Sep 30 at 12:12
Bazinga......! :)
– genderbee
Sep 30 at 12:14
@genderbee, as for the second part of your question: it depends on how you define "better". Often "easier to understand for the human reading it" counts as better than "clever demonstration of all your knowledge packed into one complex statement"
– Oscar
Sep 30 at 12:15
add a comment
|
0
0
0
Your pre-tag is working fine. Your problem is that $log contains the output of cat on one line. Instead of trying to fix this, I would suggest you split this code into simpler steps.
First of all, this line:
log=`cat ../local/log/$(ls -t ../local/log | head -1 )`Is way to complicated because it nests two command substitutions with two different syntaxes. You might understand it today, but why not split this into two steps so you or one of your co-workers will understand it a year from now:
logfile=../local/log/$(ls -t ../local/log | head -1)
logtext=$(cat $logfile)Or even better (assuming the logfiles end in .log):
logfile=$(ls -t ../local/log/*.log | head -1)
logtext=$(cat $logfile)Now you see that you just put the contents of $logile into $logtext. You seem to want to output the content of $logfile between the pre-tags, just like it appears in the file. With the simplified commands above, it may appear obvious that putting it into $logtext is an extra step that isn't even needed. Just
catthe file where you want it to appear. The backticks or the $()-construct is meant to feed one command with arguments that are created from the output of another. In this case that just messes it all up.So what you could do is this:
outputfile=itf-check-article.html
logfile=$(ls -t ../local/log/*.log | head -1)
echo '<tr style="background-color: rgb(250,240,240);">' > $outputfile
echo '<td style="padding: 10px; text-align: center;"><pre>' >> $outputfile
cat $logfile >> $outputfile
echo '</pre></td></tr>' >> $outputfileor simply run the commands between brackets
()to start a subshell with one redirect statement instead:outputfile=itf-check-article.html
logfile=$(ls -t ../local/log/*.log | head -1)
(
echo '<tr style="background-color: rgb(250,240,240);">'
echo '<td style="padding: 10px; text-align: center;"><pre>'
cat $logfile
echo '</pre></td></tr>'
) > $outputfile
answered Sep 30 at 11:10
OscarOscar
1628 bronze badges
Your pre-tag is working fine. Your problem is that $log contains the output of cat on one line. Instead of trying to fix this, I would suggest you split this code into simpler steps.
First of all, this line:
log=`cat ../local/log/$(ls -t ../local/log | head -1 )`Is way to complicated because it nests two command substitutions with two different syntaxes. You might understand it today, but why not split this into two steps so you or one of your co-workers will understand it a year from now:
logfile=../local/log/$(ls -t ../local/log | head -1)
logtext=$(cat $logfile)Or even better (assuming the logfiles end in .log):
logfile=$(ls -t ../local/log/*.log | head -1)
logtext=$(cat $logfile)Now you see that you just put the contents of $logile into $logtext. You seem to want to output the content of $logfile between the pre-tags, just like it appears in the file. With the simplified commands above, it may appear obvious that putting it into $logtext is an extra step that isn't even needed. Just
catthe file where you want it to appear. The backticks or the $()-construct is meant to feed one command with arguments that are created from the output of another. In this case that just messes it all up.So what you could do is this:
outputfile=itf-check-article.html
logfile=$(ls -t ../local/log/*.log | head -1)
echo '<tr style="background-color: rgb(250,240,240);">' > $outputfile
echo '<td style="padding: 10px; text-align: center;"><pre>' >> $outputfile
cat $logfile >> $outputfile
echo '</pre></td></tr>' >> $outputfileor simply run the commands between brackets
()to start a subshell with one redirect statement instead:outputfile=itf-check-article.html
logfile=$(ls -t ../local/log/*.log | head -1)
(
echo '<tr style="background-color: rgb(250,240,240);">'
echo '<td style="padding: 10px; text-align: center;"><pre>'
cat $logfile
echo '</pre></td></tr>'
) > $outputfile
answered Sep 30 at 11:10
OscarOscar
1628 bronze badges
answered Sep 30 at 11:10
OscarOscar
1628 bronze badges
answered Sep 30 at 11:10
OscarOscar
1628 bronze badges
answered Sep 30 at 11:10
OscarOscar
1628 bronze badges
1628 bronze badges
Ok, maybe it is better to have it separately. But what is difference between 'command' and$(command)and when it is better use one method and when second method. Thanks.
– genderbee
Sep 30 at 11:50
@genderbee, there is no difference, except you can't nest these backticks. However you ou could easily doecho $(echo $(echo $(echo Bazinga!)))if you enjoy spawning three subshells just for fun.
– Oscar
Sep 30 at 12:12
Bazinga......! :)
– genderbee
Sep 30 at 12:14
@genderbee, as for the second part of your question: it depends on how you define "better". Often "easier to understand for the human reading it" counts as better than "clever demonstration of all your knowledge packed into one complex statement"
– Oscar
Sep 30 at 12:15
add a comment
|
Ok, maybe it is better to have it separately. But what is difference between 'command' and$(command)and when it is better use one method and when second method. Thanks.
– genderbee
Sep 30 at 11:50
@genderbee, there is no difference, except you can't nest these backticks. However you ou could easily doecho $(echo $(echo $(echo Bazinga!)))if you enjoy spawning three subshells just for fun.
– Oscar
Sep 30 at 12:12
Bazinga......! :)
– genderbee
Sep 30 at 12:14
@genderbee, as for the second part of your question: it depends on how you define "better". Often "easier to understand for the human reading it" counts as better than "clever demonstration of all your knowledge packed into one complex statement"
– Oscar
Sep 30 at 12:15
Ok, maybe it is better to have it separately. But what is difference between 'command' and$(command)and when it is better use one method and when second method. Thanks.
– genderbee
Sep 30 at 11:50
Ok, maybe it is better to have it separately. But what is difference between 'command' and$(command)and when it is better use one method and when second method. Thanks.
– genderbee
Sep 30 at 11:50
@genderbee, there is no difference, except you can't nest these backticks. However you ou could easily doecho $(echo $(echo $(echo Bazinga!)))if you enjoy spawning three subshells just for fun.
– Oscar
Sep 30 at 12:12
@genderbee, there is no difference, except you can't nest these backticks. However you ou could easily doecho $(echo $(echo $(echo Bazinga!)))if you enjoy spawning three subshells just for fun.
– Oscar
Sep 30 at 12:12
Bazinga......! :)
– genderbee
Sep 30 at 12:14
Bazinga......! :)
– genderbee
Sep 30 at 12:14
@genderbee, as for the second part of your question: it depends on how you define "better". Often "easier to understand for the human reading it" counts as better than "clever demonstration of all your knowledge packed into one complex statement"
– Oscar
Sep 30 at 12:15
@genderbee, as for the second part of your question: it depends on how you define "better". Often "easier to understand for the human reading it" counts as better than "clever demonstration of all your knowledge packed into one complex statement"
– Oscar
Sep 30 at 12:15
add a comment
|
0
special-purpose code block (here doc).
#!/bin/bash
cat > itf-check-article.html <<PRE
<tr style="background-color: rgb(250,240,240);">
<td style="padding: 10px; text-align: center;"><pre>$(awk 'printf "%s<br/>",$0' $(ls -td ../local/log/* | head -n 1))</pre></td>
</tr>
PREoutput:
$ cat itf-check-article.html
<tr style="background-color: rgb(250,240,240);">
<td style="padding: 10px; text-align: center;"><pre>Start of processing orders. 0 order(s) in this run.<br/>No orders in this run<br/></pre></td>
</tr>Using += operator to append to variable.
#!/bin/bash
declare html
html+='<tr style="background-color: rgb(250,240,240);">n'
html+='<td style="padding: 10px; text-align: center;"><pre>'
html+=$(awk 'printf "%s<br/>",$0' $(ls -td ../local/log/* | head -n 1))
html+='</pre></td>n'
html+='</tr>'
echo -e "$html" > itf-check-article.html
answered Sep 30 at 9:38
bac0nbac0n
1,1531 silver badge13 bronze badges
add a comment
|
0
special-purpose code block (here doc).
#!/bin/bash
cat > itf-check-article.html <<PRE
<tr style="background-color: rgb(250,240,240);">
<td style="padding: 10px; text-align: center;"><pre>$(awk 'printf "%s<br/>",$0' $(ls -td ../local/log/* | head -n 1))</pre></td>
</tr>
PREoutput:
$ cat itf-check-article.html
<tr style="background-color: rgb(250,240,240);">
<td style="padding: 10px; text-align: center;"><pre>Start of processing orders. 0 order(s) in this run.<br/>No orders in this run<br/></pre></td>
</tr>Using += operator to append to variable.
#!/bin/bash
declare html
html+='<tr style="background-color: rgb(250,240,240);">n'
html+='<td style="padding: 10px; text-align: center;"><pre>'
html+=$(awk 'printf "%s<br/>",$0' $(ls -td ../local/log/* | head -n 1))
html+='</pre></td>n'
html+='</tr>'
echo -e "$html" > itf-check-article.html
answered Sep 30 at 9:38
bac0nbac0n
1,1531 silver badge13 bronze badges
add a comment
|
0
0
0
special-purpose code block (here doc).
#!/bin/bash
cat > itf-check-article.html <<PRE
<tr style="background-color: rgb(250,240,240);">
<td style="padding: 10px; text-align: center;"><pre>$(awk 'printf "%s<br/>",$0' $(ls -td ../local/log/* | head -n 1))</pre></td>
</tr>
PREoutput:
$ cat itf-check-article.html
<tr style="background-color: rgb(250,240,240);">
<td style="padding: 10px; text-align: center;"><pre>Start of processing orders. 0 order(s) in this run.<br/>No orders in this run<br/></pre></td>
</tr>Using += operator to append to variable.
#!/bin/bash
declare html
html+='<tr style="background-color: rgb(250,240,240);">n'
html+='<td style="padding: 10px; text-align: center;"><pre>'
html+=$(awk 'printf "%s<br/>",$0' $(ls -td ../local/log/* | head -n 1))
html+='</pre></td>n'
html+='</tr>'
echo -e "$html" > itf-check-article.html
answered Sep 30 at 9:38
bac0nbac0n
1,1531 silver badge13 bronze badges
special-purpose code block (here doc).
#!/bin/bash
cat > itf-check-article.html <<PRE
<tr style="background-color: rgb(250,240,240);">
<td style="padding: 10px; text-align: center;"><pre>$(awk 'printf "%s<br/>",$0' $(ls -td ../local/log/* | head -n 1))</pre></td>
</tr>
PREoutput:
$ cat itf-check-article.html
<tr style="background-color: rgb(250,240,240);">
<td style="padding: 10px; text-align: center;"><pre>Start of processing orders. 0 order(s) in this run.<br/>No orders in this run<br/></pre></td>
</tr>Using += operator to append to variable.
#!/bin/bash
declare html
html+='<tr style="background-color: rgb(250,240,240);">n'
html+='<td style="padding: 10px; text-align: center;"><pre>'
html+=$(awk 'printf "%s<br/>",$0' $(ls -td ../local/log/* | head -n 1))
html+='</pre></td>n'
html+='</tr>'
echo -e "$html" > itf-check-article.html
answered Sep 30 at 9:38
bac0nbac0n
1,1531 silver badge13 bronze badges
edited Sep 30 at 13:27
answered Sep 30 at 9:38
bac0nbac0n
1,1531 silver badge13 bronze badges
answered Sep 30 at 9:38
bac0nbac0n
1,1531 silver badge13 bronze badges
answered Sep 30 at 9:38
bac0nbac0n
1,1531 silver badge13 bronze badges
1,1531 silver badge13 bronze badges
add a comment
|
add a comment
|
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What is the usage of the first line? Can you put the output of
echo "$log"after the 1st line is executed in your question.– FedonKadifeli
Sep 30 at 9:00
You question is not clear. But, I think you need double quotes around
$loglike this:...<pre>'"$log"'</pre>– FedonKadifeli
Sep 30 at 9:16